What is the chemical symbol for gold?

Answers

Answer 1
Answer: The chemical symbol for gold is AU
Answer 2
Answer:

Answer:

au

Explanation:

on the periodic table golds chmeical symbol is au


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Which substance will require more energy to heat if all the samples have the same mass and same temperature change?

Answers

If mass and the temperature change is not a factor then we can take a look at the chemical bonds in the substance. Chemical bonds can also dictate how hard a sample can be heated or to break the bonds in it.Two of the strongest bonds are the ionic and covalent bond. The strongest of the two is the ionic.

The molarity of an aqueous sodium phosphate solution is 0.650 M. What is the molality of sodium ions present in this solution? The density of solution is 1.43 g/mL.

Answers

Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg

the molality = (moles of solute)/(mass of solvent in kg)=(0.65)/(1.323)= 0.491m

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

Thus molality of sodium ions = 3 X 0.491 = 1.473 m

Leutium-176 has a half-life of 3.85 mc012-1.jpg 1010 years. After 1.155 mc012-2.jpg 1011 years, how much leutium-176 will remain from an original 16.8-g sample?2.10 g
3.00 g
5.56 g
8.40 g

Answers

Answer : The amount left of leutium-176 will be, 2.10 g

Solution :

First we have to calculate the rate constant, we use the formula :

k=(0.693)/(t_(1/2))

k=\frac{0.693}{3.85* 10^(10)\text{years}}

k=0.18* 10^(-10)\text{years}^(-1)

Now we have to calculate the amount left of the sample.

Expression for rate law for first order kinetics is given by :

t=(2.303)/(k)\log(a)/(a-x)

where,

k = rate constant  = 0.18* 10^(-10)\text{years}^(-1)

t = decay time  = 1.155* 10^(11)\text{ years}

a = initial amount of the sample = 16.8 g

a - x = amount left after decay process  = ?

Now put all the given values in above equation, we get

1.155* 10^(11)\text{years}=\frac{2.303}{0.18* 10^(-10)\text{years}^(-1)}\log(16.8)/(a-x)

a-x=2.10g

Therefore, the amount left of leutium-176 will be, 2.10 g

Answer:

A.

Explanation:

In the reaction 2H2 + O2-->2H2O how many hydrogen molecules are needed to produce two water molecules

Answers

2 hydrogens per water molecule

Answer:

B

Explanation:

Which half-reaction can occur at the anode in avoltaic cell?
(1) Ni2+ + 2e---> Ni (3) Zn--> Zn2+ + 2e-
(2) Sn + 2e---> Sn2+ (4) Fe3+--> Fe2+ + e-

Answers

The answer is (3). The reaction that can occur at the anode is oxidation reaction which will lose electrons. So (1) and (2) are not correct. For (4) Fe3+ can not lose electrons again.

The thirdreaction of the zinc-releasing electron and zinc ion will occur as the half-reaction at the anode of the voltaic cell. Thus, option 3 is the correct option.

What is a half-reaction?

A half-reaction is a depiction of the oxidation or the reduction half of a redox reaction that involves the stating of the oxidation states and the release or the absorption of the electrons.

The anode is an electrode of the voltaic cell where the oxidation reaction takes place. The oxidation results in the loss of the electrons and hence, reactions 1 and 2 cannot occur at the anode. The fourth reaction is also not possible as iron cannot lose its electron.

Therefore, option 3. Zn → Zn²⁺ + 2e⁻ will occur at the anode.

Learn more about anode and oxidation here:

brainly.com/question/2166768

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An environmental chemist needs a carbonate buffer of pH 10.00. How many grams of Na,Co, must she add to 1.5 L of 0.20 M NaHCO,? K, of HCO, = 4.7 x 10"

Answers

Answer: a

Explanation: it just like simple math but it just adding stuff