The escape velocity required for gas molecules to overcome the earth’s gravity and go off to outer space is 1.12 x 103m/s at 15oC. Calculate the molar mass of a species with that velocity.

Answers

Answer 1
Answer: Here we use the root-mean-square velocity:
V(rms)² = (3RT)/M; where R is the molar gas constant, T is the temperature in Kelvin and M is the molar mass.
(1.12 x 10³)² = (3 x 8.314 x (273 + 15))/M
M = 5.72 x 10⁻³ kg = 5.72 grams

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What is the charge of the most stable ion of bromine?

Answers

The charge on the most stable ion of bromine is - 1.

What is an ion?

A charged atom or molecule is known as an ion. It has a charge because the atom or molecule's number of protons and electrons is not equal. Depending on whether an atom has more electrons than protons or fewer electrons than protons, an atom might become positively or negatively charged.

An atom is referred to be an ION when it is drawn to another atom due to an imbalance in its electron and proton numbers. A negative ion, or ANION, is an atom that contains more electrons than protons. A positive ion is one that has more protons than electrons.

Either there are too many or not enough electrons in a charged atom. Atoms in DS1 are heated to extremely high energy and unstable state. Then, a cathoderay in the thruster chamber discharges electrons, which strike the. Some of the electrons in the atoms in the chamber are stripped or knocked away when the electrons strike them. Plasma is created when a mass of charged, overheated atoms with free electrons.

Therefore, the charge on the most stable ion of bromine is - 1

Read more about ions, here

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Br (Bromide)

-1 or Br- hope this helps

How much heat is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling? Specific heat of water is c=4.184 J/(g oC) a 78.5 kJ b 15.7 kJ c 157 kJ d 1.57 kJ

Answers

The heat that is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling

C) 157 kJ

Heat

Heat required= Mass of water x specific heat capacity of water x change in temperature of water required

Q=m* c* delta T

M = 500g

C = 4.184 g°C

Delta T = 100 - 25(room temp) = 75°C

Heat = 500 x 4.184 x 75

Heat = 156900 J

Heat = 156.9 KJ

Heat ~ 157.0 KJ (3.D.P)

Thus, the correct answer is C.

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Answer:

C

Explanation:

Heat required= Mass of water x specific heat capacity of water x change in temperature of water required

q \:  = m  * c  * delta \: t

M = 500g

C = 4.184 g°C

Delta T = 100 - 25(room temp) = 75°C

Heat needed= 500 x 4.184 x 75

= 156900 J

= 156.9 KJ

~ 157.0 KJ (3.D.P)

If a student weighs out 0.744 g Fe ( NO 3 ) 3 ⋅ 9 H 2 O , what is the final concentration of the ∼0.2 M Fe ( NO 3 ) 3 solution that the student makes?

Answers

Answer:

Molar concentration of Fe(NO3)3 . 9H2O = 0.12M

Explanation:

Fe(NO3).9H2O --> Fe(NO3)3 + 9H2O

By stoichiometry,

1 mole of Fe(NO3)3 will be absorb water to form 1 mole of Fe(NO3)3 . 9H2O

Therefore, calculating the mass concentration of Fe(NO3)3;

Molar mass of Fe(NO3)3 = 56 + 3*(14 + (16*3))

= 242 g/mol

Mass concentration of Fe(NO3)3 = molar mass * molar concentration

= 242 * 0.2

= 48.4 g/L

Molar mass of Fe(NO3)3 . 9H2O = 56 + 3*(14 + (16*3)) + 9* ((1*2) + 16)

= 242 + 162 g/mol

= 404g/mol

Concentration of Fe(NO3)3 . 9H2O = mass concentration/molar mass

= 48.4 /404

= 0.12 mol/l

Molar concentration of Fe(NO3)3 . 9H2O = 0.12M

Consider four small molecules, A–D, which have the following binding affinities for a specific enzyme (these numbers are the equilibrium constants Kd for the dissociation of the enzyme/molecule complex). Which binds most tightly to the enzyme? Which binds least tightly?A) 4.5 μM

B) 13 nM

C) 8.2 pM

D) 6.9 mM

Answers

Answer:

Binding affinity measures the strength of the interaction between a molecule to its ligand; it is expressed in terms of the equilibrium dissociation constant; and the higher value of this constant, the more weaker the binding between the molecule and the ligand is. On the other hand, small constans means that the interaction is tight. So "C" binds most tightly to the enzyme and "D" binds least tightly.

A potassium ion (K+) would most likely bond with _____.

Mg+
O
Cl-
Na+

Answers

Answer:

Chlorine

Explanation:

Answer:

That would be the negative ion:  Cl-.

1. An isotope of cesium-137 has a half-life of 30 years. If 5.0 g of cesium-137 decays over 60 years, how many grams will remain?

Answers

Answer:

1.25 g

Explanation:

Now we have to use the formula;

N/No = (1/2)^t/t1/2

N= mass of cesium-137 left after a time t (the unknown)

No= mass of cesium-137 present at the beginning = 5.0 g

t= time taken for 5.0 g of cesium-137 to decay =60 years

t1/2= half life of cesium-137= 30 years

Substituting values;

N/5= (1/2)^60/30

N/5= (1/2)^2

N/5= 1/4

4N= 5

N= 5/4

N= 1.25 g

Therefore, 1.25 g of cesium-137 will remain after 60 years.