What is the solution for this equation 13m-22=9m-6. This is a equation with variables on both sides

Answers

Answer 1

Answer: 13m-22=9m-6
4m-22=-6
4m=16
m=4

Answer 2

Answer: 13m-22=9m-6
13m-9m=22-6 <-- integer signs change when it goes to the other side of the equal to sign
4m=16
m=16/4
m=4

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Fill in the number to make this true : 3/4 = /100

Answers

3/4 = 3*25 / 4*25 = 75/100

GOOD LUCK M8!

How do i solve this inequality?

Answers

Answer: -9<x<4

Step-by-step explanation:

/ 2x +5/ < 13 , the first thing is to remove the absolute symbol , which will be

-13 < 2x + 5 < 13

solving the first part:

-13 < 2x + 5

-13 - 5 < 2x

-18 < 2x

-9 < x

solving the second part

2x + 5 < 13

2x < 13 - 5

2x < 8

x < 4

combining the two results

-9<x<4

If 2.5 is a root of the equation 2x2+5x−q=0, what are the possible values of q?

Answers

Answer:

The possible value of q is $25$

Step-by-step explanation:

step 1

we have

$2x^(2) +5x-q=0$

If 2.5 is a root of the equation

then

substitute the value of x=2.5 in the equation and solve for q

$2(2.5)^(2) +5(2.5)-q=0$

$12.5 +12.5-q=0$

$25-q=0$

$q=25$

Is 3/8 greater than less than or equal to 3/4

Answers

First, we will find a common denominator to both terms. The common denominator is 8
3/4 is equivalent to 6/8

Now, we have the two terms 3/8 and 6/8
Since the denominators are equal, therefore, we will just compare the numerators.
We will find that:
6/8 is greater than 3/8

This means that 3/8 is less than 3/4

Find the value of: $27x^(3)+8 y^(3)$ if 3x+2y = 20 and xy = $(14)/(9)$

Answers

$27x^3+8y^3=(3x)^3+(2y)^3=(3x+2y)[(3x)^2-3x\cdot2y+(2y)^2]\n\n=(3x+2y)[(3x)^2+2\cdot3x\cdot2y+(2y)^2-3\cdot3x\cdot2y]\n\n=(3x+2y)[(3x+2y)^2-18xy]=(*)\n---------------------------\n3x+2y=20\n\nxy=(14)/(9)\n------------------------------\n(*)=20\cdot(20^2-19\cdot(14)/(9))=20\cdot(400-18\cdot(14)/(9))=20\cdot(400-2\cdot14)\n\n=20\cdot(400-28)=20\cdot372=7440$

$a^3+b^3=(a+b)(a^2-ab+b^2)\n\n(a+b)^2=a^2+2ab+b^2$

Please help this is very easy!!!!!!!