Find the slope of the line:
5x+3y=6

Answers

Answer 1

Answer: To get the result we have to transform given formula into y=ax+b form.
Lets do this
5x+3y=6 /-5x (subtract 5x both sides)
3y=-5x+6 /:3 (divide both sides by 3)
y= $-(5)/(3) x+6$
In form y=ax+b we know that a is slope and b is y intersect. We can read from our transformed equation that slope a= $-(5)/(3)$ and its the result

Answer 2

Answer: $5x+3y=6\n3y=-5x+6\ny=-(5)/(3)x+2\n\boxed{m=-(5)/(3)}$

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Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Write a system of equations that can be used to find how many problems of each point value are on the test.

Answers

x - the number of 5 points worth problems
y - the number of 2 points worth problems

The test has 29 problems.
$x+y=29$

The test is worth 100 points.
$5x+2y=100$

The system of equations:
$x+y=29 \n5x+2y=100$

The solution:
$x+y=29 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |* (-2) \n5x+2y=100 \n \n-2x-2y=-58 \n\underline{5x+2y=100 \ \ \ \ \ } \n3x=42 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 3 \nx=14 \n \nx+y=29 \n14+y=29 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |-14 \ny=15$

There are 14 problems worth 5 points and 15 problems worth 2 points.

Final answer:

The system of equations to find the number of 5-point and 2-point problems on the math test is x + y = 29 and 5x + 2y = 100, where x and y are the numbers of 5-point and 2-point problems respectively.

Explanation:

The question posed involves setting up a system of equations to determine how many of each type of problem are on a math test. There are two types of problems: those worth 5 points and those worth 2 points, with the test having a total of 29 problems and worth 100 points in all. To solve this, we can define two variables, let's say x represents the number of problems worth 5 points and y represents the number of problems worth 2 points.

We can set up the following system of equations:

x + y = 29 (This represents the total number of problems.)
5x + 2y = 100 (This represents the total points for the test.)

Solving this system will give the number of 5-point problems and 2-point problems on the test.

Learn more about System of Equations here:

brainly.com/question/21620502

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Which step should be completed first in the following problem 4(27÷3²)

Answers

Answer:

3²

Step-by-step explanation:

We have to use BPEMDAS Order of Operations:

B - Brackets

P - Parenthesis

E - Exponents

M - Multiply

D - Divide

A - Addition

S - Subtraction

We use this order left to right. Since we have parenthesis, we look at that first. Inside, we have division and exponents. Since exponents come first, we have to evaluate 3² first.

Answer:

square the 3

Step-by-step explanation:

In the order of operations, you must do the exponent inside the parentheses first, so the first step is:

4(27 ÷ 3²) =

= 4(27 ÷ 9)

Answer: square the 3

What is the probability that a five-card poker hand contains the two of diamonds and the three of spades?(Note: Enter the value in decimal format and report it to four decimal places.)

Answers

The total probability is 52 choose 5, which is 2598960
Then we multiply the combinations of two diamonds and 3 spades, which is 13 choose 2 times 13 choose 3. That is 22308.
Then we divide to get the decimal. 22308/2598960 is 0.00858343337

A school’s population increased by 42 students. This was a 3% increase. About how many students attended before the increase?

Answers

Answer:

is this about corona but the answer is 23

Step-by-step explanation:

A toy rocket is shot vertically into the air from a launching pad 5 feel above the ground with an initial velocity of 80 feet per second. The height h, in feet, of the rocket above the ground as t seconds after launch is given by the function h(t)=-16t^2+80t+5. How long will it take the rocket to reach its maximum height? What is the maximum height?CAN ANYONE HELP ME ASAP!!!!
Thank you in advance

Answers

$h(t)=-16t^2+80t+5\n\nt_(max)-time\ for\ a\ maximum\ height\n\nt_(max)=- (80)/(2\cdot(-16)) = (80)/(32) =2.5\ [s]\n\nh_(max)-the\ maximum\ height\ above\ the\ ground\n\nh_(max)=h(2.5)=-16\cdot2.5^2+80\cdot2.5+5=-16\cdot6.25+200+5=\n.\ \ \ \ \ \ =-100+205=105\n\nh_(max\ rocket)-the\ maximum\ height\ of\ a\ toy\ rocket\n\nh_(max\ rocket)=105-5=100\ [ft]\n\nAns.\ t_(max)=2.5\ second,\ \ h_(max\ rocket)=100\ feet.$