If a DNA molecule is found to be made of 40% thymine,What percentage guanine would you expect

Answers

Answer 1
Answer: It needs to equal the amount of adenine. The guanine to cyanine. So it would be 40% thymine 40 % adenine then 10% guanine and 10% cyanine would make sense

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A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​

Answers

\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  (given \: weight)/(molecular \: weight) }}

Solution:

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of \sf{CaCO_3}

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = 0.1 moles

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no of the moles calcium carbonate is 0.01

Water is composed of two hydrogen atoms and one oxygen atom therefore, water is a

Answers

two hydrogen
compound !!

When dissolved beryllium chloride reacts with dissolved silver nitrate in water, aqueous beryllium nitrate and silverchloride powder are made.

Answers

Answer:

The balanced chemical equation is :

BeCl_(2) + 2AgNO_(3)\rightarrow Be(NO_(3))_(2) + 2AgCl

Explanation:

The chemical equation in which number of atoms in reactants is equal to products is called balanced equation.

Formula of , Beryllium Chloride :[BeCl_(2)

Beryllium Nitrate : BeNO_(3)

Silver Chloride : AgCl

Silver Nitrate  :AgNO_(3)

When beryllium chloride reacts with dissolved silver nitrate in water , following reaction occur :

 BeCl_(2) + 2AgNO_(3)\rightarrow Be(NO_(3))_(2) + 2AgCl

The number of atoms in reactant as well as in products are balanced :

Be = 1

Ag = 2

N =2

O = 6

Cl = 2

Final answer:

This is a chemical reaction involving beryllium chloride and silver nitrate in water, resulting in the formation of solid silver chloride and aqueous beryllium nitrate.

Explanation:

The question pertains to a chemical reaction in aqueous solution between beryllium chloride and silver nitrate. This reaction can be described by the equation BeCl2(aq) + 2AgNO3(aq) → 2AgCl(s) + Be(NO3)2(aq). In this equation, (aq) represents compounds dissolved in water (aqueous), and (s) represents solid. This reaction results in a precipitate of silver chloride (AgCl(s)), which is a powder, and an aqueous solution of beryllium nitrate (Be(NO3)2a).

Learn more about Chemical Reaction here:

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What method of forecasting uses averages to predict future weather?O
A. Persistence method
B. Climatology method
O
C. Analog method
O
D. Trends method

Answers

The climatology method of forecasting uses averages to predict future weather.

Answer: B

Explanation

The satellites and advanced technologies have helped meteorologists to forecast accurately.

There are four types of forecasting methods prevailing now.

They are climatology method, persistence method, analog method and trends method.

The persistence and trends method uses the previous day forecast and compare with today's condition to forecast about future.

The analog method is a complex method where the forecasting is done by comparing present weather condition with a similar condition occurred in the past to predict for future.

The climatology is the simplest method which uses average of weather conditions observed in the previous days to get accurate forecast for future.

Climatology method is the right answer.

23g of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.

Answers

Answer: The mass of sodium chloride formed will be 58.5 g

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • For Sodium:

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium}=(23g)/(23g/mol)=1mol

  • For chlorine gas:

Given mass of chlorine gas = 35.5 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

\text{Moles of chlorine gas}=(35.5g)/(71g/mol)=0.5mol

The chemical reaction for the formation of sodium chloride follows the equation:

2Na+Cl_2\rightarrow 2NaCl

By stoichiometry of the reaction:

2 moles of sodium reacts with 1 mole of chlorine gas.

So, 1 mole of sodium will react with = (1)/(2)* 1=0.5mol of chlorine gas.

Thus, the formation of sodium chloride can be calculated by using any of the reactant.

By stoichiometry of the reaction:

2 moles of sodium produces 2 moles of sodium chloride.

So, 1 mole of sodium will react with = (2)/(2)* 1=1mol of sodium chloride.

Now, calculating the mass of sodium chloride by using equation 1, we get:

Moles of sodium chloride = 1 mole

Molar mass of sodium chloride = 58.5 g/mol

Putting values in equation 1, we get:

1mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\n\n\text{Mass of NaCl}=58.5g

Hence, the mass of sodium chloride formed will be 58.5 g

58.5 is the final mass of the compound as long as any gases the reaction causes to be

What is the compound of nacI is an example of a/an?

Answers

Sodium chloride is the compound of nacl.

The compound of NaCl is sodium chloride