Seven vans each hold 6 passengers. Each passenger is carrying 20 candies divided equally among 5 small boxes. How many candies are on the vans? 840 candies 4200 candies 168 candies 120 candies

Answers

Answer 1

Answer: I believe the correct answer from the choices listed above is the first option. There are about 840 candies present on all vans present. We calculate it by multiplying the number of total passengers by the number of candies each passenger is carrying. Hope this answers the question.

Answer 2

Answer:

840 candies: answer

Explanation:

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Photosynthesis transfers carbonfrom the nonliving environment to the living environment.
from the cell to the air.
from the water to the cell.
from the nucleus to the mitochondria.

Answers

Photosynthesis is the process in plants to make their food. This involves the use carbon dioxide to react with water and make sugar or glucose as the main product and oxygen as a by-product. I think the best answer would be the first statement.

Answer: Option A

Explanation:

Photosynthesis is a process that helps the plants to make food by the help of carbon dioxide from the atmosphere and water, nutrients from soil and converts it into glucose in the presence of sunlight.

Atmosphere is a non living component of environment where carbon dioxide is present and it is transferred to plants which is a living component of ecosystem.

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron. 2. How many MOLES of fluorine are present in 5.35*1022 molecules of boron trifluoride ? moles of fluorine.

Answers

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.

Explanation:

The molecular formula of boron trifluoride is $BF_3$ .

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- $6.023x10^2^3$ atoms.

Then, 2.20 moles of boron has

- $=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\n=13.25x10^2^3 atoms$

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

$(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\n=0.0888mol$

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

Do you think that there is a high correlation between proficiency in mathematics and proficiency in chemistry? Explain why or why not. Use details about the components of each field to support your answer.

Answers

According to the fact that they both include the reaction change of elements through different processes, there should be a nice connection between them. In math, numbers pose as an element, and in chem - elements are physical things. Both of them can change due to reaction or a formula.

Which types of reactions would result in the formation of precipitate?

Answers

Answer:

Double Displacement Reaction

Explanation:

A double displacement reaction is a type of chemical reaction in which the reactant ions exchange places to form new products. Usually, a double displacement reaction results in precipitate formation.

Waves with the shortest wave lengths have the highest

Answers

Answer:

shortest wavelength - gamma rays

highest wavelength - radio waves

Explanation:

Look at the electromagnetic spectrum

Answer:

I don't use your question?

What is the mass percentage of carbon in 5.000 G of sucrose

Answers

Answer : The mass percentage of carbon in sucrose is, 42.1 %

Explanation: Given,

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

First we have to calculate the molar mass of sucrose.

Molar mass of sucrose $(C_(12)H_(22)O_(11))$ = $12(12)+22(1)+11(16)=342g/mole$

Now we have to calculate the mass of carbon in 5 g of sucrose.

As we now that there are 12 number of carbon atoms, 22 number of hydrogen atoms and 11 number of oxygen atoms.

The mass of carbon = $12* 12=144g$

As, 342 g of sucrose contains 144 g of carbon

So, 5 g of sucrose contains $(5)/(342)* 144=2.105g$ of carbon

Now we have to calculate the mass percentage of carbon in sucrose.

Formula used :

$\%\text{ Mass percentage of carbon}=\frac{\text{Mass of carbon}}{\text{Mass of sucrose}}* 100$

Now put all the given values in this formula, we get:

$\%\text{ Mass percentage of carbon}=(2.105)/(5)* 100=42.1\%$

Therefore, the mass percentage of carbon in sucrose is, 42.1 %

17) 8.4 / 20 x 100

18) 20 . 0.5150

19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass

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