57.4 divided by 10???????

Answers

Answer 1

Answer: 57.4/10=5.74
the answer is 5.74

Answer 2

Answer: 57.4 / 10 = 5.74
You just move the decimal over one place to the left

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What fraction is equivalent to the expression 4/8 + 2/8

Simplify -62 ÷ 12 - 2(-7).

-17
35
11
-35

Answers

I don't know if you know something called PEMDAS

Parentheses
Exponent
Multiply
Divide
Add
Subtract

So you would do the -2(-7) first giving you 14

So now we have -62/12 +14

now you would do -62/12 giving you -5.16666667

and now the equation is -5.16666667 + 14 = 8.83333333

I know for a fact, being in Calculus Honors, that what I did to simplify is correct. Using the Order of Operations, or PEMDAS (Commonly remebered as "Please Excuse My Dear Aunt Sally". It stands for "Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction".) to simplify this answer is necessary.

If your teacher wrote this problem please inform him or her of Order of Operations before your classmates use it even though its wrong.

Towns A and B are 400 miles apart. If a train leaves A in the direction of B at 50 miles per hour, how long will it take before that train meets another train, going from B to A,
at a speed of 30 miles per hour?

Answers

from A :50/hour. *x(hour)
From B : 30/hour *x(hour)
50 *x +30 *x =400
80 *x=400
x=5(hour)
Then the train from A will make 50 *5=250 miles
(These is fisik)

Solve for x in simplest form. 4=1/3(7x-3)

Answers

Answer:

x=15 over 7

Hope this helps

Step-by-step explanation:

Find the missing value 6x=12

Answers

According to the order of operations, the first thing you need to do is divide both sides by 6.

6x ÷ 6 = 12 ÷ 6

That gets x on one side by itself, making x = 2

The missing value of 6x = 12 is 2

2 is the answer also u can just think of it as dividing

the flight of an aircraft from toronto to montrel can be modelled by he relation h=-2.5t2+200t where t is the time, in minutes, and h is the height in metre

Answers

Final answer:

The equation for the aircraft's flight is a quadratic equation representing the height of the aircraft at any given time. By rearranging the equation to isolate time and applying the quadratic formula, we can find the time at which the aircraft reaches its maximum height, which in this case is 3.79 minutes.

Explanation:

The flight of an aircraft from Toronto to Montreal is modeled by the equation h = -2.5t2 + 200t where t represents time in minutes and h represents height in meters. This is fundamentally a quadratic equation which is utilized in physics to characterize motion under constant acceleration. In this case, it models the height of the aircraft at any given time.

To find the time at which the airplane's maximum height is achieved, we must solve the equation for t. By rearranging the equation, we can isolate t, yielding a quadratic equation as follows: 0 m = 0 m + (10.0 m/s) t + (2.00 m/s2) t2. This simplifies to 200 = 10t + t2.

Applying the quadratic formula, we find two solutions for t, 3.79 s and 0.54 s. The time it takes the aircraft to reach its maximum height would be the longer solution, which is 3.79 minutes in this case.

Learn more about Quadratic Equations in Motion here:

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Final answer:

The question provides a quadratic equation to model the flight of an aircraft. This equation can be used to calculate the height of the aircraft at a specific time or to determine when the aircraft reaches its maximum height.

Explanation:

The question is asking about the trajectory of an aircraft as modelled by a quadratic equation, and specifically, how time influences height. The equation given is h = -2.5t²+200t. Quadratic equations are frequently used to describe the motion of objects when the acceleration is constant. This equation tells us that the height of the aircraft is dependent on the time squared and the time.

To solve for a specific time (t), we can plug the desired time into the equation to find the height of the aircraft at that time. For instance, if we want to find out the height of the aircraft 10 minutes into the flight, we would substitute t=10 into the equation, giving us h=-2.5 × (10)²+200 × (10). Simplifying this equation would provide the height of the aircraft 10 minutes into the flight.

Additionally, this equation could also be used to find the maximum height of the aircraft. The maximum height is reached when the derivative of the equation equals zero. Taking the derivative of h = -2.5t²+200t and setting it equal to zero will provide the time when the maximum height is reached.

Learn more about Quadratic Equations here:

brainly.com/question/30098550

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Find the product of 543 and 36.
A. 507
B. 19,548
C. 15.08
D. 579

Answers

1 Set up the long multiplication.

543x36

2 Calculate 3 x 6, which is 18.
Since 18 is two-digit, we carry the first digit 1 to the next column.

3 Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.

4 Calculate 5 x 6, which is 30. Now add the carry digit of 2, which is 32.
Since 32 is two-digit, we carry the first digit 3 to the next column.

5 Bring down the carry digit of 3.

6 Calculate 3 x 3, which is 9.

7 Calculate 4 x 3, which is 12.
Since 12 is two-digit, we carry the first digit 1 to the next column.

8 Calculate 5 x 3, which is 15. Now add the carry digit of 1, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.

9 Bring down the carry digit of 1.

10 Calculate 3258 + 16290, which is 19548

11 Therefore, 543 x 36 = 19548.

The answer is B.19548

B. 19,548 because a product is an aswer in amultipacation problem so you would have to multiply 543 x 36

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