I think I got the answer but I'm not sure. Help?

Answers

Answer 1

Answer: I wish I could see your answer in the picture. Then we could put it into the original equation and see if it checks.

It won't, because you made a slight mistake in your first line, where you were
eliminating the parentheses on the right side:

-4(x- 3) = -4x +12 . . . . . not -4x -12 .

That should get you all fixed up.

When you combine like terms from your first line,
your second line will be
4x + 6 = 30 - 4x

and it's all smooth sailing from there.

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Jamal is 167 cm tall which expression finds Jamal's height in dekameters?

Answers

Answer:

16,7

Step-by-step explanation:

I give you very simple example may it's help you

160cm

7cm

16,7cm

Answer:167 Divided by 1000

Step-by-step explanation:I checked multiple times like a scientist.

Only problem 6a. Can someone demonstrate how to do this so I can do the rest solo?

Answers

as far as I can tell, is simply asking to write two more expressions, that are equivalent to the provided one, namely, grab the provided one and expand it, if you simplify the expanded version, you'd end up with the provided, for example

$\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}}\n\n\n\boxed{6a.3}~\hfill \stackrel{ch anging}{\cfrac{15/ 3}{30/ 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15/ 5}{30/ 5}}\implies \stackrel{two}{\cfrac{3}{6}}$

so let's do 6a1, 6a3 and 6a5.

$\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}} \n\n\n \boxed{6a.3}~\hfill \stackrel{changing}{\cfrac{15/ 3}{30/ 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15/ 5}{30/ 5}}\implies \stackrel{two}{\cfrac{3}{6}}$

$\bf \boxed{6a.5}~\hfill \stackrel{changing}{(9\cdot 10)/ (2\cdot 10)}\implies \stackrel{one}{90/ 20}~\hfill \stackrel{changing}{(9\cdot 70)/(2\cdot 70)}\implies \stackrel{two}{630/ 140}$