Ten less than double a number is the same as seven times the number. Find the number

Answers

Answer 1
Answer: Put in equation form, that problem would be 2n - 10 = 7n

Subtract 2n from each side and you get -10 = 5n

Divide both sides by 5 and you get -2 = n

So the answer would be -2 (negative two).



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The minimum monthly payment for Alicia's credit card is 2% of her balance or $10, whichever is higher. If Alicia's balance at the end of her last billing cycle was $470, what is her minimum monthly payment?

Answers

Answer:

Alicia's minimum monthly payment is $10.

Step-by-step explanation:

Given is :

Alicia's balance at the end of her last billing cycle was $470. So, its 2 % becomes:

(2)/(100) *470 = $9.40

As it is stated that the minimum monthly payment for Alicia's credit card is 2% of her balance or $10, whichever is higher.

Therefore, $10 is higher amount than $9.40

So, the correct answer is: Alicia's minimum monthly payment is $10.

a boat traveled 336 miles downstream and back.the trip downstream took 12 hours.the trip back took 14 hours.what is the speed of the boat in still water?what is the speed of the.current?

Answers

Boat speed speed =x mph
current speed =y mph
against current 14 hours
with current 12 hours

Distance against 336 miles distance with 336 miles
t=d/r against current -
336 / ( x - y )= 14
14 ( x - y ) = 336
14 x - 14 y = 336 ....................1

336 / ( x + y )= 12
12 ( x + y ) = 336
12 x + 12 y = 336 ...............2
Multiply (1) by 6 
Multiply (2) by 7

we get
84 x + -84 y = 2016
84 x + 84 y = 2352
168 x = 4368
/ 168
x = 26.00 mph

plug value of x in (1) y
14 x -14 y = 336
364 -14 -364 = 336
-14 y = 336
-14 y = -28 mph
y = 2.00
Boat speed speed 26.00 mph
current speed 2.00 mph 
It took an avg of 13 mi total 15 mi/hr is the answer for the still water 11 mi/hr is the upstream speed I added 2 and subtracted two because it made sense because there is a difference of two in the hrs it took to go upstream and downstream

Round off 572 389 correct to three significant figure ​

Answers

572000 or 5.72×10^5

Step-by-step explanation:

depends on what format ur teacher prefers but both show 3 sig figs correctly so either is correct

Round 3,989.23655 to the nearest thousandth.

Answers

3,989.23700 would be the answer because you take five and round six to seven. Everything that follows that becomes a zero.

Displacement vectors of 3m and 5m in the same direction combine to make a displacement vector that is.a. 2m.b. 0m. c. 8m. d. 15m

Answers

Displacement vectors is 2m

Displacement vectors:

Given that;

Same length direction of 3m and 5m

Given direction is same

Find:

Displacement vectors

Computation:

Displacement vectors = 5m - 3m

Displacement vectors = 2m

Find out more about 'Displacement vectors'

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If, A+B+C=π(i) Prove that, SinA+SinB-SinC = 4SinA/2. SinB/2. CosC/2
(ii) Prove that, Cos^2A + Cos^2B-Cos^2C = 1-2SinA.SinB.Cos.C
(iii) Prove that, CosA+CosB-CosC = -1+4CosA/2. CosB/2.SinC/2

Answers

(i)
A+B+C = pi
B+C = pi-A
sin(B+C) = sin(pi-A)
sin(B)cos(C)+cos(B)sin(C) = sin(pi)cos(A)-cos(pi)sin(A)
sin(B)cos(C)+cos(B)sin(C) = sin(A)
sin(B)cos(C) - sin(A) = -cos(B)sin(C)
(sin(B)cos(C) - sin(A))^2 = (-cos(B)sin(C))^2
sin^2(B)cos^2(C) + sin^2(A) - 2sin(A)sin(B)cos(C) = cos^2(B)sin^2(C)
-2sin(A)sin(B)cos(C) = cos^2(B)sin^2(C) - sin^2(B)cos^2(C) - sin^2(A)

(ii)
cos^2(A) + cos^2(B) - cos^2(C) = 1-2*sin(A)*sin(B)*cos(C)
cos^2(A) + cos^2(B) - cos^2(C) = 1+cos^2(B)sin^2(C) - sin^2(B)cos^2(C) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(cos^2(B)sin^2(C) - sin^2(B)cos^2(C)) - sin^2(A)cos^2(A) + cos^2(B) - cos^2(C) = 1+((cos(B)sin(C))^2 - (sin(B)cos(C))^2) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(cos(B)sin(C)-sin(B)cos(C))(cos(B)sin(C)+sin(B)cos(C)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(sin(C)cos(B)-cos(C)sin(B))(sin(C)cos(B)+cos(C)sin(B)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+sin(C-B)sin(C+B) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(cos(2B)-cos(2C)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(2cos^2(B)-1-(2cos^2(C)-1)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(2cos^2(B)-1-2cos^2(C)+1) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(2cos^2(B)-2cos^2(C)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+cos^2(B)-cos^2(C) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1 - sin^2(A) + cos^2(B) - cos^2(C)
cos^2(A) + cos^2(B) - cos^2(C) = cos^2(A) + cos^2(B) - cos^2(C)