The period of an ocean wave is 4 seconds. What is the waves frequency?

Answers

Answer 1

Answer: Frequency= 1/period
Frequency=1/4
Frequency= 0.25Hz

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Why does a compass point to the east or west of true north in different locations?
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List the following items in order of decreasing speed, from greatest to least: (i) A wind-up toy car that moves 0.15 m in 2.5 s. (ii) A soccer ball that rolls 2.3 m in 0.55 s. (iii) A bicycle that travels 0.60 m in 0.075 s. (iv) A cat that runs 8.0 m in 2.0 s. Knight, Randall D., (Professor Emeritus). College Physics (p. 28). Pearson Education. Kindle Edition.

Is it possible to fly from Norway to USA across the North Pole?

Answers

Sure. The Earth is a sphere (ball-shaped), so you can follow practically
any route you want from one place to another. You could even fly from
New York to Chicago by way of the north pole.

If you want to draw a smooth curve from Oslo through the north pole to
a point in the USA, that's perfectly possible. But it's not the shortest way
to travel between those two points.

Why are the vector quantities magnitude and direction

Answers

Because color, cost, temperature, weight, and age
don't tell you enough about the motion.

Because, by definition, a vector has to have magnitude and direction. Otherwise, it's not a vector. If it only has magnitude, then it's a scalar, not a vector. Does that help at all?

There is very high humidity in your area and a cold front moving in. What would be your forecast?

Answers

Answer:

Rain

Explanation:

A cold front is of a cooler mass of air, which replaces warmer mass of air of ground level and lies within a fairly sharp surface trough of low pressure.

As your area has very high humidity and a cold front is moving in, ultimately there will be continues rainfall and it will be there until cold front has moved away.

As in a cold front, warmer air mass is replaced by cold air mass, the cold air mass will combine with humidity resulting in lots and lots of rain.

You will end up having lots of rain until the cold front goes away.

What must exist for electric charges to flow?

Answers

Answer:electric potential difference

Explanation:

Emotional abuse is less harmful than physical abuse.
a. True
b. False

Answers

B) False
There is emerging evidence that emotional abuse is in fact, more harmful, than physical abuse. A study conducted by the Trauma Center at the Justice Resource Institute shows that because of the long-term nature of emotional and psychological abuse, victims score higher on a measure of a variety of negative risk factors and behaviors.

False, just because it's not physical, doesn't mean it's any less harmful than emotional.

After landing from your skydiving experience, you are so excited that you throw your helmet upward. The helmet rises 5.8 m above your hands. What was the initial speed of the helmet when it left your hands? Express your answer to three significant figures and include the appropriate units How long was it moving from the time it left your hands until it returned? Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

Initial velocity: approximately $10.7\; {\rm m\cdot s^(-1)}$ .

Time taken before return to initial height: approximately $2.17\; {\rm s}$ .

(Assumptions: $g = 9.81\; {\rm m\cdot s^(-2)}$ ; air resistance is negligible.)

Explanation:

Under the assumption, acceleration of the helmet would be constantly $a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)}$ .

During the interval between being thrown upward and reaching maximum height:

Initial velocity immediately after the person threw the helmet upward, $u$ , needs to be found.
Final velocity when the helmet reached maximum height is $v = 0\; {\rm m\cdot s^(-1)}$ .
Change in position over this interval is $x = 5.8\; {\rm m}$ .
Acceleration is $a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)}$ .

Apply the following SUVAT equation to find initial velocity $u$ :

$\begin{aligned} u &= \sqrt{v^(2) - 2\, a\, x} \n &= \sqrt{(0)^(2) - 2\, (-9.81)\, (5.8)} \; {\rm m\cdot s^(-1)}\n &\approx 10.668\; {\rm m\cdot s^(-1)} \n &\approx 10.7\; {\rm m\cdot s^(-1)}\end{aligned}$ .

(Round to three significant figures for the final result, but keep more significant figures for intermediary values.)

In other words, the velocity of the helmet was approximately $10.7\; {\rm m\cdot s^(-1)}$ immediately after the person threw the helmet upward.

Right before returning to the initial height, the velocity of the helmet would be the opposite of its initial velocity: $(-u) \approx (-10.7)\; {\rm m\cdot s^(-1)}$ .

The change in velocity would be:

$\begin{aligned}((-u) - u)/(a) &\approx ((-10.668) - 10.668)/((-9.81))\; {\rm s} \n &\approx 2.17\; {\rm m\cdot s^(-1)}\end{aligned}$ .

(Rounded to three significant figures.)

Final answer:

The initial speed of the helmet was 10.7 m/s and it was in the air for a total of 2.18 s.

Explanation:

This problem involves concept from physics specifically kinematics. Kinematics helps us study the motion of objects. To solve this problem, we need to use the second equation of motion: v²=u²+2as. In this case, the final speed (v) is 0 (when the helmet reaches the highest point, its velocity becomes 0), acceleration (a) is -9.8 m/s² (gravity acts downwards), and the distance (s) is 5.8 m.

Plugging in these values we get: 0 = u² - (2 * 9.8 * 5.8). Solving for u (initial velocity), we get u = √(2 * 9.8 * 5.8) = 10.7 m/s. This is the initial speed of the helmet when it left your hands.

To find out how long the helmet was in the air, we can use the first equation of motion: v = u + at. Solving for t (time), we get: t = (v - u) / a = (0 - 10.7) / -9.8 = 1.09 s going up. Because the time going up and coming down is the same, the total time the helmet was moving is 2 * 1.09 = 2.18 s.

Learn more about Kinematics here:

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