What is the cosine of 135 degrees?

Answers

Answer 1

Answer: $cos135^o=cos(90^o+45^o)=-sin45^o=-(\sqrt2)/(2)\n\nreduction\ formulas:\ cos(90^o+\alpha)=-sin\alpha$

Answer 2

Answer: $cos(180^0- \alpha )=-cos \alpha \n \n cos135^0=cos(180^0-45^0)=-cos45^0=- ( √(2) )/(2)$

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1. Complete the tables of values below for graphing the secant and cotangent functions. You can type “U” for an undefined value. Use exact values with fractions and square roots, not the decimal approximations. For example, use 3/2 rather than 0.866 (pictures attached) 2. Graph the secant graph for 0 ≤ x ≤ 2π. Graph the cotangent graph for 0 ≤ x ≤ 2π. (don't need these pictures I have them)

3. Indicate whether each of the three reciprocal functions (cosecant, secant, and cotangent) is a periodic function. If so, state the period of each.

4. List the domain and range for the secant and cotangent functions. (Use "pi" for π.)

5. Compare the graphs of the cosecant and secant functions. How are they different? How are they similar?

Answers

Step-by-step explanation:

1. All the trigonometric values can be found using the unit circle. See attached table.

2. Graph:

desmos.com/calculator/10n7yrm3tm

3. All trig functions are periodic functions. The period of secant and cosecant is 2π. The period of cotangent is π.

4. Using the table from step 1 and the graph from step 2, secant has a domain of x ≠ pi/2, 3pi/2 and a range of x ≤ -1, x ≥ 1. Cotangent has a domain of x ≠ 0, pi, 2pi and a range of -∞ < x < ∞.

5. Graph:

desmos.com/calculator/tldiqt7qra

Cosecant has the same graph as secant shifted π/2 to the right. So they have different domains, but the same range.

Which complex number is equivalent to (7-9i)-(-1+3i)?

Answers

just like algebra
i lis like x
distribute invisible -1 to second set
-1(-1+3i)=1-3i

now we have
7-9i+1-3i
8-12i

2.0 is ???? times greater than 0.02

Answers

2.0 is 100 times greater than 0.02. When you have two numbers that are just separated by zeroes, simply count the number of zeroes and multiply the smaller number by a multiple of ten with the same number of zeroes to get the larger number. For instance, if you were to have 40 and 0.0004, you can just count the number of decimal places between them (in this case 4), and put the same number of zeroes behind a 1 (10,000). Then, if you multiply 0.0004 by 10,000, you should get 40. Likewise, if you multiply 0.02 by 100, you should get 2.

Josie rode her bike 18 miles at 12 and then rode another 24 miles at 15. How long did she ride in all?

A.27 hours

B.15 hours

C.6 hours

D.3.1 hours

Answers

18/12= 1.5
24/15= 1.6
1.6+1.5=3.1
I think D is your answer

Solve for t. 50= − 10 t + 80

Answers

The answer is t= 3 !!!

50= - 10t+80
We move all terms to the left:
50 - ( -10t+80) =0
Get rid of the parentheses
10t - 80+50=0
We add all the numbers together, and all the variables
10+ - 30=0
We move all the terms containing t to the left, all the other terms to the right
10t = 30
t = 30/10
t = 3

A square field has an area of 479 ft2. What is the approximate length of a side of the field? Give your answer to the nearest foot.A. 240
B. 23
C. 22
D. 21

Answers

The approximate length of a side of the square field is 22 feet.

Given,

A square field has an area of 479 ft².

We need to find out what is the approximate length of a side of the field.

Give your answer to the nearest foot.

What is the area of a square?

It is given as :

Area = side²

Find the length of a side of a square.

Side = length of a side

Area = side²

We have,

Area = 479 ft²

479 = side²

Side = √479

Side = 21.886

Rounding to the nearest foot.

Side = 21.886 feet

0.886 can be round to 1 foot.

So,

Side = 22 feet.

Thus the approximate length of a side of the square field is 22 feet.

Learn more about finding the side of a square with its perimeter given here:

brainly.com/question/5247625

#SPJ2

Hey there,

So all we really need to do for this one is

area=LW, L=W in squaer so 479=L^2, squaer root both sides, L=W=21.88=22 rounded

so it is C

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