How do you classify the slope of a line ?

Answers

Answer 1

Answer: y=mx+b

slope= rise
run
If its already graphed then you find where the line meets the y- line ( thats the b in the equation) from there you go up or down on the y- line to the point where the line next meets directly over another vertical line on the grid, the number of times you moved up or down is the "rise" in the equation for slope. After finding rise your move left or right from that point on the y-line until you meet the point where the line is and that will be the run. That fraction or number once you simplify the equation is you slope. Hope that helps.

Answer 2

Answer:

Answer:

Easy the equation will always be y=mx+b

mx is the slope in the equation and b is the y intercept and always remember rise over run

Step-by-step explanation:

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Adam’s sister wants to watch her intake of fat per day.He estimates that the dinner will have 48 grams of fat.

What percentage of her total daily allowance of fat will the dinner be with a daily allowance of 70g
?

Answers

Answer:

68.57% of her total daily allowance of fat will the dinner.

Step-by-step explanation:

We have been given that the dinner will have 48 grams of fat.

And the daily allowance of fat is 70 grams.

We have to find that what percentage of her total daily allowance of fat will the dinner.

$\%=\frac{\text{allowance of fat of dinner}}{\text{daily allowance of fat} } * 100\n\n\%=(48)/(70)* 100\n\n\%=68.57\%$

Therefore, 68.57% of her total daily allowance of fat will the dinner.

48/70 = 24/35

24/35 = 0.6857

= 68.57%

Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?A. tan A = sin A/sin C
B. cos A = tan (90-A)/sin (90-C)
C. sin C = cos A/tan C
D. cos A = tan C
E. sin C = cos (90-C)/tan A

Answers

First, note that $m\angle A+m\angle C=90^(\circ).$ Then

$m\angle A=90^(\circ)-m\angle C \text{ and } m\angle C=90^(\circ)-m\angle A.$

Consider all options:

$\tan A=(\sin A)/(\sin C)$

By the definition,

$\tan A=(BC)/(AB),\n \n\sin A=(BC)/(AC),\n \n\sin C=(AB)/(AC).$

Now

$(\sin A)/(\sin C)=((BC)/(AC))/((AB)/(AC))=(BC)/(AB)=\tan A.$

Option A is true.

$\cos A=(\tan (90^(\circ)-A))/(\sin (90^(\circ)-C)).$

By the definition,

$\cos A=(AB)/(AC),\n \n\tan (90^(\circ)-A)=(\sin(90^(\circ)-A))/(\cos(90^(\circ)-A))=(\sin C)/(\cos C)=((AB)/(AC))/((BC)/(AC))=(AB)/(BC),\n \n\sin (90^(\circ)-C)=\sin A=(BC)/(AC).$

Then

$(\tan (90^(\circ)-A))/(\sin (90^(\circ)-C))=((AB)/(BC))/((BC)/(AC))=(AB\cdot AC)/(BC^2)\neq (AB)/(AC).$

Option B is false.

$\sin C = (\cos A)/(\tan C).$

By the definition,

$\sin C=(AB)/(AC),\n \n\cos A=(AB)/(AC),\n \n\tan C=(AB)/(BC).$

Now

$(\cos A)/(\tan C)=((AB)/(AC))/((AB)/(BC))=(BC)/(AC)\neq \sin C.$

Option C is false.

$\cos A=\tan C.$

By the definition,

$\cos A=(AB)/(AC),\n \n\tan C=(AB)/(BC).$

As you can see $\cos A\neq \tan C$ and option D is not true.

$\sin C = (\cos(90^(\circ)-C))/(\tan A).$

By the definition,

$\sin C=(AB)/(AC),\n \n\cos (90^(\circ)-C)=\cos A=(AB)/(AC),\n \n\tan A=(BC)/(AB).$

Then

$(\cos(90^(\circ)-C))/(\tan A)=((AB)/(AC))/((BC)/(AB))=(AB^2)/(AC\cdot BC)\neq \sin C.$

This option is false.

The right anwer is option A.
tan A = sin A / sin C
sin C = sin A / tan A = sin A / (sin A / cos A) = cos A
sin C = cos A

Which ordered pair could be removed to make thisrelation a function?
0 (-5, 0)
0 (-1, -3)
O (4, -2)
O (6, -1)

Answers

Answer: (4, -2)

Step-by-step explanation:

Answer:

(4,-2)

letter C

In your own words, define “rate of change.” Give an example.This is Advanced Functions, not sure how to explain the term out on paper but ik what it means, any help?

Answers

how fast or slow something changes over a period of time

it can generally be expressed as a ratio between a change in one variable relative to a corresponding change in another, graphically the rate of change is represented by the slope of a line

Please :’) help me out

Answers

Answer:

10 units

Step-by-step explanation:

In this equation the parenthesis act as a multiplier, so you take w(2w + 2) = 40.

the variable w represents the number 1, so you multiply the numbers within the parenthesis.

w x 2w = 2w

w x 2 = 2w

so now you have 2w + 2w = 40

add the w's for 4w = 40

Now you need to get rid of the number next to the W.

divide the four from the W and divide the 40 as well

4w/4= w

40/4 = 10

W=10

8 is 50% 0f what number

Answers

'is' in mathematics means equal
'of' in mathematics means multiplication

Translating 8 is 50% of what number into an equation, we get:

8 = 50% * x

50%, or 50 percent, is nothing but 50 over 100 or 50/100, which is the same as 1/2.

8 = 1/2 * x

Multiply 2 on both sides.

8 * 2 = 1/2 * 2 * x

16 = x

x = 16

8 is 50% of 16.

x=is the number.
50% of x=8
(50/100)x=8
x=(8*100)/50=16

Answer: 8 is 50% of 16

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