What times what equals 160

Answers

Answer 1

Answer: The question is asking to state the number that when multiply, the product would be 160, base on my research and calculation, I would say that the answer would be 16*10, 2*80, 40*4, 20*8, 160*1 and 32*5. I hope you are satisfied with my answer and feel free to ask for more

Answer 2

Answer:

The equivalent value of the equation is A = 160 = 20 x 8

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the first number be p

Let the second number be q

Now , A = pq

when the value of p = 20

And , when the value of q = 8

On simplifying the equation , we get

160 = 20 x 8

So , the left hand side of the equation is equated to the right hand side by the value of ( 20 x 8 )

A = 20 x 8

A = 160

Therefore , the value of A = 160 = 20 x 8

Hence , the expression is A = 160 = 20 x 8

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A leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. At that rate how many gallons of water will the faucet leak in 48 hours.

Answers

To solve this problem, let's set up a proportion, letting x represent the unknown number of gallons the faucet loses in 48 hours.

5 gallons / 20 hours = x gallons / 48 hours

To solve this proportion, we are going to use cross-products. This is the products of numerator of one fraction and the denominator of the other fraction set equal to one another. It results in the equation:

5 * 48 = 20 * x

Next we simplify by performing the operations.

240 = 20x

Finally, we divide both sides by 20 to get x alone on the right side of the equation.

12=x

Therefore, 12 gallons of water will be lost in 48 hours.

5gallons leakout every 20 hours
5g:20h
fractionify
5g/20h=g/4h
g:4h

how many gallons in 48 hours
xgallons:48
assume constant rate of flow so
g:4h=x:48
fractionfy
g/4h=x/48h
multiply both sides by 48h
12g=x
answer is 12 gallons

Owen simplified the expression r-8 s-5.

r−8s−5 = 1r8 ⋅ s5 = s5r8

Answers

r⁻⁸ s⁻⁵

using the rule x⁻ⁿ=1/xⁿ

r⁻⁸ s⁻⁵ = (1/r⁸)(1/s⁵)

Sample Response: Each base must be treated separately. Since each base is raised to a negative exponent, they should both be in the denominator of the fractions. The simplified form of the expression has 1 in the numerator and r to the 8th power times s to the 5th power in the denominator.

Are 16:14 and 64:60 equivalent ratios?

Answers

Answer:

Both the ratios are not equivalent.

Step-by-step explanation:

Consider the provided ratios:

16:14

The above ratio can be written as:

$(16)/(40)=(2)/(5)$

Now consider the another ratio:

64:60

The above ratio can be written as:

$(64)/(60)=(16)/(15)$

Now compare both the ratio:

$(2)/(5)\neq (16)/(15)$

Hence, both the ratios are not equivalent.

Ratios are equivalent when you divide the first term by the second and it's the same for both ratios.

In this case, 16/14 is not equal to 64/60

The answer show work please

Answers

well you need to do 10 plus 13 which equals 23 you don't count the inside number

Sara's savings account balance changed by -$34 one week and by -$67 the next week .Which amount represents the greater change?

Answers

Answer:

Change in one week is more than the change in the next week

Step-by-step explanation:

Change in Sara's savings account balance in one week = $- \$ 34$

Change in Sara's savings account balance in next week = $- \$ 67$

Tens digit in 34 = 3

Tens digit in 67 = 6

If we compare the tens digit of 34 and 67, we get $6> 3$

So, $67> 34$

On multiplying both sides by -1 , we get $-67< -34$ .

{ We know that negative sign changes sign of inequality }

So, we get change in one week is more than the change in the next week .

The greater change is represented by the absolute magnitude

|-34| = 34
|-67| = 67

67 > 34

-67 represents the greater change

What is the 50th term of the arithmetic sequence 32,27,22,17,12

Answers

The 50th term of the arithmetic sequence is -213.and this can be determined by using the $\rm T^(th)$ term of the arithmetic sequence formula.

Given :

Arithmetic sequence --- 32,27,22,17,12

The difference of the arithmetic operation is given by the formula:

$a_2-a_1 = 27 - 32 = - 5$

The $\rm T^(th)$ term of the arithmetic sequence is given by the formula:

$\rm T_n = a + (n-1)d$

where a is the first term, n is the total number of terms, d is the difference, and $\rm T^(th)$ is the term of the arithmetic sequence.

$\rm T_(50) = 32 - (50-1)5$