How do I solve this inequality
how do I solve this inequality - 1

Answers

Answer 1
Answer: 3x+5x/4≤34
leat common multiple=4
12x+5x≤136
17x≤136
x≤136/17
x≤8

Answer: x≤8        or            (-∞,8]

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Ava's dog weighs 56 kilograms. Marty's dog weighs 7/8 as much. How much does Marty's dog weigh?

Answers

Answer:

49 kg.

Step-by-step explanation:

We have been given that Ava's dog weighs 56 kilograms. Marty's dog weighs 7/8 as much. We are asked to find the weight of Marty's dog.

To find the weight of Marty's dog, we will multiply 56 by (7)/(8).

\text{Weight of Marty's dog}=56\text{ kg}* (7)/(8)

\text{Weight of Marty's dog}=7\text{ kg}* 7

\text{Weight of Marty's dog}=49\text{ kg}

Therefore, the weight of Marty's dog is 49 kilograms.

49 kilograms!
56:8=7 (is the 1\8)
so the 7\8 are 7*7=49 kilograms

Solve the following equation

w-6/5=-2

Answers

w - (6)/(5) = -2

First, move (6)/(5) around to both sides.
w = -2 +  (6)/(5)
Second, subtract the numerator (6) and -2. 
w =  -(4)/(5)

Answer as fraction: w =  -(4)/(5)
Answer as decimal: -0.8

This is a probability question:A committee of six is to review the value of discipline in education. The committee is to be chosen randomly from 3 interest teachers, a student council of 6 students and 5 interested parents. What are the following probabilities?
a)no students are on the committee
b) The committee is made up only of students
c) There will be at least one teacher on the committee.

Answers

Im pretty sure it is b

An electrician charges a $20 house call fee plus $30 per hour of work. Which equation represents this relationship?An electrician charges a $20 house call fee plus $30 per hour of work.

Answers

Answer:

20+30h

......................................

Which of the following would indicate that a dataset is skewed to the right? a. The interquartile range is larger than the range.
b. The range is larger than the interquartile range.
c. The mean is much larger than the median.
d. The mean is much smaller than the median.

Answers

Answer: c. The mean is much larger than the median

Step-by-step explanation:

A dataset is skewed to the right when the peak of the dataset is located in the left( left of the mean), and it has a long right tail. It is also call positive skewed distribution. One of the characteristics of right skewed dataset is that the mean of the dataset is always greater/larger than the median and mode.

Therefore, for the case above if the mean is much larger than the median, it indicates that the dataset is skewed to the right.

A dataset is skewed to the right when the mean is much larger than the median. Therefore, the correct answer is option c.

When a dataset is skewed to the right, it means that the distribution of data is not symmetric, and it is stretched out more towards the higher values (right side) than the lower values (left side). This can be due to the presence of outliers or a natural characteristic of the data.

Now, let's look at why option "c" indicates right skewness:

c. The mean is much larger than the median.

The mean is the arithmetic average of all the values in the dataset, while the median is the middle value when the data is arranged in order. When a dataset is positively skewed (skewed to the right), it means that there are some significantly larger values in the right tail of the distribution that pull the mean to the right (towards higher values).

In this situation:

The mean gets pulled toward the larger values because the larger values have a greater impact on the mean due to their magnitude.

The median remains closer to the bulk of the data because it is not affected by extreme values as much as the mean.

So, when the mean is much larger than the median, it is an indication that there are significant outliers or a longer right tail in the dataset, which is a characteristic of a right-skewed distribution.

Therefore, the correct answer is option c.

Learn more about Skewed to the right here:

brainly.com/question/31544308

#SPJ3

What is the square root property of:

Answers

The square root property seems to be another name for completing the square

x^2 + 5x + 6 = 0

We move the constant to the other side

x^2 + 5x = -6

We square half the linear coefficient and add that to both sides

x^2 + 5x + (5/2)^2 = -6 + 25/4

Now the left side is a perfect square,

(x + 5/2)^2 = 1/4

Here's the square root property part, we take the square root of both sides, remembering the ±

x + 5/2 = ± 1/2

x = -5/2 ± 1/2

Answer: x = -3 or x=-2

We check by plugging in these values to the original equation, and they work.

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x^2 + 6x = 16

Again we add half the linear coefficient, squared, to both sides

x^2 + 6x + 3^2 = 16 + 9

(x + 3)^2 = 25

Here comes the square root property, taking the square root of both sides:

x + 3 = ±5

x = -3 ± 5

x = 2 or x = -8

Again we check by substitution, and they both work

Answer: x = 2 or x = -8