A loan of $900 will be repaid in 36 installment payments of $30.22 each. What the finance charge for the loan?

Answers

Answer 1
Answer: First you need to multiply 36 *$30.22=$1087.92
This gives you the total amount paid

Then subtract 1087.92-900=187.92
This gives you the amount of money you paid in finance charges.

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The sum of the first 65 odd, positive integers is?I know the answer is 4225, but I don't know how to solve.

Answers

1+3+5+7+9+11+...\n\nThis\ is\ an\ atihmetic\ progression\ where\ a_1=1\ and\ d=2.\n\nThe\ sum:S_n=(2a_1+(n-1)d)/(2)\cdot n\n\nS_(65)=(2\cdot1+(65-1)\cdot2)/(2)\cdot65=(2+64\cdot2)/(2)\cdot65=(2+128)/(2)\cdot65\n\n=(130)/(2)\cdot65=65\cdot65=4225

Shannon and her family are traveling in the car. Her mom brought 1/2 pound of raisins to share equally between the four family members. How much will each person get?

Answers

Each family member will recieve .125 pounds of raisins because 1/2 divided by 4 = .125
 

Answer: 1/8

The answer is: 1/8

A regular square pyramid has a base length of 6 cm. The slant height of the pyramid is 9 cm. What is the surface area of the regular pyramid?a. 90 cm2
b. 120 cm2
c. 144 cm2
d. 252 cm2

Answers

l = 6 cm
h = 9 cm
A = l×l + 4×1/2×l×h = 6×6 + 2×6×9 = 36 + 108 = 144 sq cm

Need help on m number 2 please

Answers

so the qustion is which of these shos the commutative property
the commutative property of multiplication is
note:ab=a times b=a(b)

so a(bc)=(ab)c

first choice: 4.1 times (6.2 times 5.0)=(4.1 times 6.2) times 5.0
this is obviously the right answer A is the answer

B
2.7 times 1=2.7 this is the identity property of multiplicaiton, anything times 1= same thing


C 7.2 times 0=0 this is the 0 property of multiplication

D. 8.5 times 0.4=0.4 times 8.5
this is the equality property

the answer is A

1+csc(t) / 1+sin(t)
I have to make it into a single trig function

Answers

Consider this:
csc t=1/sin t


(1+ csc t) / (1+ sin t)=[1+(1/sin t)] / (1+sin t)=[(sin t+1)/sin t] / (1+sin t)=
=1/sin t= csc t.



Answer: (1+csc t) / (1+sin t)=csc t

Kevin is an auto mechanic. He spends 2 hours when he replaces the shocks on a car and 2 hours when he replaces the brakes. He works no more than 42 hours a week. He routinely completes at least 4 shocks replacements and 6 break replacements a week. If he charges $450 for labor replacing shock and $200 in labor for replacing breaks, how many jobs of each type should he complete a week to maximize his income?Kevin should do ___ shock replacements and ___ brake replacements every week to maximize his weekly income.

Answers

Kevin has been working as an auto-mechanic. For maximizing weekly income Kevin should do 6 breaks replacement and 4 shock replacements. The time required for performing both the tasks has been equal. Since the time required has been the same, to increase the income, the task resulting in more income has been prioritized

Given :

  • The charges for shock replacement = $450,
  • The charge for breaks replacement = $200.

Since there have been more income with shock replacement, the brake replacement task has been prioritized.

The time Kevin works in a week has been 42 hours. Since each job takes 2 hours, the number of jobs he can perform has been 21 jobs.

The routine jobsof brake replacement performed by Kevin have been 6. Thus to increase his income, the rest jobs have been of shock replacement.

The number of shock replacement tasks performed by the Kevin =

= 21 - 6

= 15

The number of shock replacement jobs = 15.

Thus for increasing the income Kevin has to perform 6 brake replacement tasks and 15 shock replacement tasks.

For more information, refer to the link given below:

brainly.com/question/24406804

Answer:

Kevin should do 15 shock replacements and 6 brake replacements every week to maximize his weekly income.

Step-by-step explanation:

Both jobs take the same amount of time to complete (2 hours), therefore, in order to maximize his income, Kevin should prioritize the job that gives him the greatest income, which is replacing shocks.

If each job takes 2 hours and he works at most 42 hours per week, Kevin can complete 21 jobs per week. He should aim to do as little break replacements as possible and as many shock replacements as possible to maximize income.

If he completes at least 6 break replacements, the remaining jobs should all be shock replacements:

S=21-6\nS=15

Kevin should do 15 shock replacements and 6 brake replacements every week to maximize his weekly income.