3x+4y=2 4x-4y=12 elimination

Answers

Answer 1

Answer: 3x+4y=2
+ 4x-4y=12 add them since 4y and -4y can cancel out
7x=14 divide each side by 7
x=2

3x+4y=2 x=2
3(2)+4y=2 substitute
6+4y=2
-6 -6
4y=-4 divide each side by 4
y=-1

Answer 2

Answer: 3x+4y=2
4x-4y=12
Add both
7x=14
X=2
Substitute value of x in first equation
Y=-1

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-5n-8 (1+7)=-8 simplify

Answers

Answer:no its 69. :)

Step-by-step explanation:

For the graph shown, select the statement that best represents the given system of equations. 3y – x = 2 9y – 3x = 6Help Please Thank You

Answers

You can find that out by first putting two equations in slope-intercept form y=mx+b by solving for y.
3y - x = 2
3y = x+2
y = (1/3)x + 2/3

9y = 3x + 6
y = (3/9)x + 6/9
y = (1/3)x + 2/3

They are the same line as you can see in the final step.
Since the two lines are the same line, (they "coincide") they are coincident.
Coincident means there are an infinite number of solutions, and since they are the same line, there are an infinite number of solutions.

2x + y = −3
3x + 2y = −8

Answers

Answer:

x=2/3 y=-3

Step-by-step explanation:

2x+y=-3 *2 6x+2y=-6

3x+2y=-8

6x+2y-3x-2y=-6+8

3x=2

x=2/3

3*2/3+2y=-8

2+2y=-4

1+y=-2

y=-3

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=5.Calculate (a)the common ratio. (b)the first term of this geometric sequence

Answers

1 step: $S_(5)=T_(1)+T_(2)+T_(3)+T_(4)+T_(5)$ , $S_(3)=T_(1)+T_(2)+T_(3)$ , then
$S_(5)-S_(3)=T_(4)+T_(5)=5$ .

2 step: $T_(n)=T_(1)*q^(n-1)$ , then
$T_(6)=T_(1)*q^(5)$
$T_(5)=T_(1)*q^(4)$
$T_(4)=T_(1)*q^(3)$
$T_(3)=T_(1)*q^(2)$
and $\left \{ {{T_(6)-T_(4)= (5)/(2) } \atop {T_(5)+T_(4)=5}} \right.$ will have form $\left \{ {{T_1*q^(5)-T_(1)*q^(3)= (5)/(2) } \atop {T_(1)*q^(4)+T_(1)*q^(3)=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^(3)*(q^(2)-1)= (5)/(2) } \atop {T_(1)*q^(3)*(q+1)=5} \right.$ and dividing first equation on second we obtain $(q^(2)-1)/(q+1)= ( (5)/(2) )/(5)$ . So, $((q-1)(q+1))/(q+1) = (1)/(2)$ and $q-1= (1)/(2)$ , $q= (3)/(2)$ - the common ratio.

4 step: Insert $q= (3)/(2)$ into equation $T_(1)*q^(3)*(q+1)=5$ and obtain $T_(1)* (27)/(8)*( (3)/(2)+1 ) =5$ , from where $T_(1)= (16)/(27)$ .

Which choice shows a correct way to solve 8•13?

Answers

Answer:

Step-by-step explanation:

8 x(10+3)

A 1-day movie rental at red box costs $1.39. For each additional day there is a fee of $0.50. How much will it cost to rent a movie for 7 days?

Answers

It will cost a total amount of $4.89 to rent a movie for 7 days

Word Problem

Given Data

Cost per day = $1.39

Fee per additional day = $0.50

Number of added days = 7

Let us find the mathematical expression for the above question

Total Cost = 1.39+ 0.5*7

Total cost = 1.39+ 3.5

Total cost = $4.89

Learn more about Word Problem here:

brainly.com/question/25693822

Lets just simply solve:-

Days:- 1 2 3 4 5 6 7
1.39 + 0.50 + 0.50 + 0.50 + 0.50 + 0.50 + 0.50 = Cost to rent a movie for 7 days.

1.39 + 0.50 + 0.50 + 0.50 + 0.50 + 0.50 + 0.50 = 4.39

So, to rent a movie for 7 days it would cost $4.39.

Hope i helped ya!!

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