HeredityGenes


Alleles


Genotype


Phenotype


Dominant


Recessive


Incomplete Dominance


Codominance


Please define these words

Answers

Answer 1
Answer: Heredity- The passing on of traits from parents to their offspring:

Genes- A gene is the basic physical and functional unit of heredity. Genes are made of (DNA).

Alleles- Allele, also called allelomorph, any one of two or more genes that may occur alternatively at a given site(locus) on a chromosome.

Genotype- A genetic constitution of an individual organism.

Phenotype- The set of observable characteristics of an individual resulting from the interaction of its genotype with the environment.

Dominant- To be in control

Recessive- is a Quality found in the relationship between two versions of a gene.

Incomplete Dominance- is an important concept in the study of genetics.

Codominance- is a relationship between two versions of a gene.

Hope this works :)
Answer 2
Answer:

Genes-Adistancesequenceofnucleotides.


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Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: PCl5(g) → PCl3(g) + Cl2(g) P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
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Answers

The value of  ΔH will be 249.75 KJ.

To obtain the reaction :

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We have to add the given reactions and then divide it by 4.

(i) adding the reactions

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 4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ

we get:

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(ii) dviding by 4

  PCl5(g) → PCl3(g) + Cl2(g)  ,  ΔH = (3438 - 2439)/4

 ΔH = 249.75 kJ is the required enthapy.

Learn more about enthalpy:

brainly.com/question/12676996

Answer:

The value of \Delta H for the desired reaction will be 249.75 KJ.

Explanation:

The desired reaction is shown below

\textrm{PCl}_(5)\left ( g \right )\rightarrow \textrm{PCl}_(3)\left ( g \right )+\textrm{Cl}_(2)\left ( g \right )

The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.

P_(4)\left ( s \right )+6Cl_(2)\left ( g \right )\rightarrow 4PCl_(3)\left ( g \right ) \n4PCl_(5)\left ( g \right )\rightarrow P_(4)\left ( s \right )+10Cl_(2)\left ( g \right )

Net Enthalpy change for the desired reaction

\displaystyle (3438-2439)/(4) \textrm{ KJ} = 249.75 \textrm{ KJ}

\Delta H = 249.75 \textrm{ KJ}

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