MATHEMATICS HIGH SCHOOL

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!A sequence is shown.
3, 9, 13, 33, 51, ...
Which of the following functions can be used to find the nth tern of this sequence?
a.f(n)=n^2+2

b.f(n)=2n^2+1

c.f(n)=2n+1

d.f(n)=3n^2

Answers

Answer 1
Answer:

Answer:

b. f(n) = 2n^2 + 1

Step-by-step explanation:

Thanks for explaining the nth thing to me. It all makes sense now :'D

I'll be honest I think you're at least a grade level above me in math.

It's b. because

f(n) = 2(1)^2 + 1

        2(1) + 1

        2 + 1 = 3 (first term)

f(n) = 2(2)^2 + 1

        2(4) + 1

        8 + 1 = 9 (second term)  ...and so on. :)

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Gina, Sam, and Robby all rented movies from the same video store. They each rented some dramas, comedies, and documentaries. Gina rented 11 movies total. Sam rented twice as many dramas, three times as many comedies, and twice as many documentaries Gina. He rented 27 movies total. If Robby rented 19 movies total with the same number of dramas, twice as many comedies, and twice as many documentaries as Gina, how many movies of each type did Gina rent? Answers:
3 dramas, 5 comedies, and 3 documentaries
2 dramas, 6 comedies, and 3 documentaries
1 dramas, 4 comedies, and 6 documentaries
4 dramas, 3 comedies, and 4 documentaries

Answers

Answer:

Gina rent 3 dramas, 5 comedies, and 3 documentaries.

Step-by-step explanation:

Let Gina rented x movies of dramas , y movies of comedies and z movies of documentaries then , Gina rented total 11 movies.

\Rightarrow x+y+z=11   .........(1)

Also given Sam rented twice as many dramas, three times as many comedies, and twice as many documentaries Gina, thus he rented 2x movies of dramas , 3y movies of comedies and 2z movies of documentaries. also, he rented a total of 27 movies.

\Rightarrow 2x+3y+2z=27 ............(2)

Also, Robby rented the same number of dramas, twice as many comedies, and twice as many documentaries as Gina, thus, he rented x movies of dramas , 2y movies of comedies and 2z movies of documentaries also, he rented a total of 19 movies.

\Rightarrow x+2y+2z=19  ............(3)

Solving the three equation using matrix form,

\left[\begin{array}{ccc}1&1&1\n2&3&2\n1&2&2\end{array}\right] \left[\begin{array}{c}x\ny\nz\end{array}\right]=\left[\begin{array}{c}11\n27\n19\end{array}\right]

This, system is in form of AX= b,

Where, A=\left[\begin{array}{ccc}1&1&1\n2&3&2\n1&2&2\end{array}\right] ,  X=\left[\begin{array}{c}x\ny\nz\end{array}\right] , b=\left[\begin{array}{c}11\n27\n19\end{array}\right]

Pre-mutiply by A inverse both sides,

X=A^(-1)b  ............(P)

First finding inverse,

\mathrm{Augment\:with\:a}\:3x3\:\mathrm{identity\:matrix}

=\begin{bmatrix}1&1&1&\mid \:&1&0&0\n 2&3&2&\mid \:&0&1&0\n 1&2&2&\mid \:&0&0&1\end{bmatrix}

\mathrm{Swap\:matrix\:rows:}\:R_1\:\leftrightarrow \:R_2

=\begin{bmatrix}2&3&2&\mid \:&0&1&0\n 1&1&1&\mid \:&1&0&0\n 1&2&2&\mid \:&0&0&1\end{bmatrix}

\mathrm{Cancel\:leading\:coefficient\:in\:row\:}\:R_2\:\mathrm{\:by\:performing}\:R_2\:\leftarrow \:R_2-(1)/(2)\cdot \:R_1

=\begin{bmatrix}2&3&2&\mid \:&0&1&0\n 0&-(1)/(2)&0&\mid \:&1&-(1)/(2)&0\n 1&2&2&\mid \:&0&0&1\end{bmatrix}

\mathrm{Cancel\:leading\:coefficient\:in\:row\:}\:R_3\:\mathrm{\:by\:performing}\:R_3\:\leftarrow \:R_3-(1)/(2)\cdot \:R_1

=\begin{bmatrix}2&3&2&\mid \:&0&1&0\n 0&-(1)/(2)&0&\mid \:&1&-(1)/(2)&0\n 0&(1)/(2)&1&\mid \:&0&-(1)/(2)&1\end{bmatrix}

\mathrm{Cancel\:leading\:coefficient\:in\:row\:}\:R_3\:\mathrm{\:by\:performing}\:R_3\:\leftarrow \:R_3+1\cdot \:R_2

=\begin{bmatrix}2&3&2&\mid \:&0&1&0\n 0&-(1)/(2)&0&\mid \:&1&-(1)/(2)&0\n 0&0&1&\mid \:&1&-1&1\end{bmatrix}

\mathrm{Cancel\:leading\:coefficient\:in\:row\:}\:R_1\:\mathrm{\:by\:performing}\:R_1\:\leftarrow \:R_1-2\cdot \:R_3

=\begin{bmatrix}2&3&0&\mid \:&-2&3&-2\n 0&-(1)/(2)&0&\mid \:&1&-(1)/(2)&0\n 0&0&1&\mid \:&1&-1&1\end{bmatrix}

\mathrm{Multiply\:matrix\:row\:by\:constant:}\:R_2\:\leftarrow \:-2\cdot \:R_2

=\begin{bmatrix}2&3&0&\mid \:&-2&3&-2\n 0&1&0&\mid \:&-2&1&0\n 0&0&1&\mid \:&1&-1&1\end{bmatrix}

\mathrm{Cancel\:leading\:coefficient\:in\:row\:}\:R_1\:\mathrm{\:by\:performing}\:R_1\:\leftarrow \:R_1-3\cdot \:R_2

=\begin{bmatrix}2&0&0&\mid \:&4&0&-2\n 0&1&0&\mid \:&-2&1&0\n 0&0&1&\mid \:&1&-1&1\end{bmatrix}

\mathrm{Multiply\:matrix\:row\:by\:constant:}\:R_1\:\leftarrow (1)/(2)\cdot \:R_1

=\begin{bmatrix}1&0&0&\mid \:&2&0&-1\n 0&1&0&\mid \:&-2&1&0\n 0&0&1&\mid \:&1&-1&1\end{bmatrix}

Thus, A^(-1)=\begin{pmatrix}2&0&-1\n -2&1&0\n 1&-1&1\end{pmatrix}

Put values in equation (P),

X=A^(-1)b

\left[\begin{array}{c}x\ny\nz\end{array}\right]=\left[\begin{array}{c,c,c}2&0&-1\n -2&1&0\n 1&-1&1\end{array}\right]\left[\begin{array}{c}11\n27\n19\end{array}\right]

\left[\begin{array}{c}x\ny\nz\end{array}\right]=\left[\begin{array}{c,c,c}2\cdot \:11+0\cdot \:27+\left(-1\right)\cdot \:19\n \left(-2\right)\cdot \:11+1\cdot \:27+0\cdot \:19\n 1\cdot \:11+\left(-1\right)\cdot \:27+1\cdot \:19\end{array}\right]

\left[\begin{array}{c}x\ny\nz\end{array}\right]=\left[\begin{array}{c}3\n5\n3\end{array}\right]

Thus, Gina rent 3 dramas, 5 comedies, and 3 documentaries.
3 dramas, 5 comedies, and 3 documentaries

Need help please, ASAP

Answers

Answer:

the answer is the last one BC is congruent to yz and a and x

Step-by-step explanation:

Answer:

BC ≅ YX and ∠A ≅ ∠X

Step-by-step explanation:

Jika x1 dan x2 merupakan akar akar persamaan x2+5x-2=0, maka (x1+2x2)(x2+2x1)=

Answers

-8 ........................

6xy (x 2 - xy + y 2 )

Answers

(if 2 is a square)

6xy ( x2 - xy + y2)

= 6x3y - 6x2y2 - 6xy3 --------------the threes and twos on this line are squares and cubics. the six is just a whole number

A population decreases from 14,500 to 12,035. What is the percentage change?

Answers

Answer:

Your answer is 17%

If the probability of success during a single event of a geometric experiment is 0.16, what is the probability of success by the 8th event? Round your answer to the nearest tenth of a percent.

Answers

The probability of success by the 8th event is 75.21%.

Probability of success: 0.16
Probability of failure:
        = 1 - P (Prob. of success)
        = 1 - 0.16
        = 0.84
Total probability of failure:
        = 0.84 ^ 8 (# of event)
        = 0.247875891

Probability of success on the 8th event:
        = 1 - Probability of failure on previous events
        = 1 - 0.247875891
        = 0.7521 or 75.21% 

To get either probability, deduct the given from 1 which serves as the 100% probability.

Hope this helps! :)

Answer:...

Step-by-step explanation:
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