Find the line's slope and a point on the line.
y-4=
= (x + 5)

Answers

Answer 1
Answer:

Answer:

y=x+9

Step-by-step explanation:

First, remove the parentheses.

Write in slope-intercept form. (y=mx+b)


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Which expressions are differences of squares?Choose all answers that are correct.Question 2 options:8b^2 – 16c^616e^8 – 81g^449x^25 – 4y^16121m^18 – 9n^10
1.The Springfield Meteorological Center wanted to determine the accuracy of their weather forecasts. Theysearched their records for those days when the forecaster had reported a 70% chance of rain. Theycompared these forecasts to records of whether or not it actually rained on those particular days. Theforecast of 70% chance of rain can be considered very accurate if it rained on:A. 95% to 100% of those days.B. 85% to 94% of those days.C. 75% to 84% of those days.D. 65% to 74% of those days.E55% to 64% of those days.

Complete the following item based on the given information.The volume of a box(V) varies directly with its length(l). If one of the boxes has a volume of 325 cubic inches and a length of 13 inches, what is the constant of proportionality for the group of boxes?
k = ________

Answers

Answer:

The constant of proportionality for the group of boxes is 25.

Step-by-step explanation:

Given : The volume of a box(V) varies directly with its length(l). If one of the boxes has a volume of 325 cubic inches and a length of 13 inches.

To find : What is the constant of proportionality for the group of boxes?

Solution :

The volume of a box(V) varies directly with its length(l).

Using k for the constant of proportionality.

We can express the relationship between V and l

If V varies directly with l.  

V = kl

According to question,

If one of the boxes has a volume of 325 cubic inches and a length of 13 inches, then  

325=13k\n\n\Rightarrow\ k=(325)/(13)\n\n\Rightarrow\ k=25

Therefore, The constant of proportionality for the group of boxes is 25.

k = 325/13
..............................................

give you 300 dollars if u get this right. you have my word The lifetimes of 20,000 light bulbs are normally distributed. The mean lifetime is 230 days. The standard deviation is 40 days. Find the values defined by the standard deviation in a normal distribution for 3 standard deviations.

Answers


Wow !  I didn't know the numbers when I read the question,
but with that much riding on it, I had to go look them up and
learn something.  You probably could have done the same thing
and saved yourself some money, but it's too late for that.  It's all
mine now, as soon as I finish writing this answer.  

In the normal distribution, 68.27% of the values lie within one
standard deviation of the mean, 95.45% lie within two standard
deviations, and 99.73% lie with three standard deviations.

Within one sigma:  68.27% of 20,000 = 13,654
13,654 light bulbs will last between 190 days and 270 days.

Within two sigma:  95.34% of 20,000 = 19,068 
19,068 light bulbs will last between 150 days and 310 days.


Here's the one you asked for:

Within three sigma:  99.73% of 20,000 = 19,946
19,946 light bulbs will last between 110 days and 350 days.

Only 54 light bulbs will burn out in less than 110 days
OR keep going more than 350 days. 

OK.  Now you owe me.

Round all the way 2689

Answers

2689 rounded to the nearest thousand will be 3,000 because 6 added one to 2 since it is more than 4.

What is the slope of the line that passes through (8,4) and (6,7)?

Answers

slope=(y_2-y_1)/(x_2-x_1)\n\n (x_1,y_1)=(8,4)\n (x_2,y_2)=(6,7)\n\n slope=(7-4)/(6-8)=(3)/(-2)=-(3)/(2)\n\nSlope\ is\ equal\ to\ -(3)/(2).

Doing monomials. How do you do this one?

Answers

(- (5)/(10) )( ( x^(3) )/( x^(3)) } )( ( y^(3) )/( y^(3) y^(4) ) )( (z^(4) )/( z^(4) ) ) => (- (1)/(2) )( (1)/( y^(4) ) ) => (-1)/(2 y^(4) ) .

Priya has $30 to spend at the school festival. Admission is $4 and each ride ticket is $2. Which inequality represents the greatest number of ride tickets she can buy2n+4<30
2n+3>30
2n+4≤30
2n+4≥30

Answers

Answer:

4 + 2n ≤ 30

Step-by-step explanation:

  • Priya has $30 to spend at the school festival.
  • Each ride ticket costs $2, and the admission is $4.
  • So, the cost of n ride tickets would be 2n dollars.
  • The total cost of the admission and ride tickets would be the sum of the admission and the cost of ride tickets: 4 + 2n.
  • We want to find an inequality that ensures the total cost does not exceed $30.
  • In other words, we want 4 + 2n to be less than or equal to 30.

Now, let's represent this in an inequality:

4 + 2n ≤ 30