In a reaction the mass of a reactant decreases by 58g in 233 seconds. What is the rate?

Answers

Answer 1

Answer:

The rate of the reaction is approximately 0.248 grams per second.

The rate of a reaction is determined by the change in the concentration of reactants or products with respect to time. In this case, the mass of a reactant decreases by 58g over a time interval of 233 seconds. To calculate the rate, we can divide the change in mass by the time elapsed:

Rate = Change in mass / Time

Rate = 58g / 233s ≈ 0.248 g/s

This value represents the rate at which the reactant is being consumed during the reaction. It's important to note that the units of the rate are consistent with the units of the given data (grams and seconds). This rate provides insight into how quickly the reaction is progressing in terms of reactant consumption.

To know more about reactant consumption, here

brainly.com/question/17173796

#SPJ3

Answer 2

Answer:

I've just been doing that now, this might be a bit late but the answere is 0.25g/s

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a car requires 1x10^8J of energy to drive 30km. calculate how many kilometers you could hypothetically drive using the energy contained in the rest mass of 100mg of fuel.

Answers

Ah hah ! I spy a question about E = m c² .
OK, here we go. Fossen your seat belt, mon,
it's going to be eh boompy rade !

E = energy equivalent of mass
m = the mass of the mass
c = the speed of light

E = (m) (c)²

      = (100 mg) (3 x 10⁸ m/s)²

   = (1 x 10⁻⁴ kg) (9 x 10¹⁶ m²/s²)

   = 9 x 10¹² (kg-m²/s²)

   = 9 x 10¹² (kg-m/s²) (m)

   = 9 x 10¹² (newton) (m)

   = 9 x 10¹² joules .

The car can go 30 km on 10⁸ J of energy.

How far can it go on 9 x 10¹² J ?

(9 x 10¹² J) x (30 km / 10⁸J)

   = (9 x 10⁴) x (30 km) = 2,700,000 km

   = roughly 7.3 times the distance to the moon.

Which statement best describes the energy changes that occur while a child is riding on a sled down a steep, snow-covered hill? @4.3.8.A @2A)
Kinetic energy decreases and potential energy increases.

B)
Kinetic energy increases and potential energy decreases.

C)
Both potential and kinetic energy decrease.

D)
Both potential and kinetic energy increase

Answers

Answer is B)
When a child is riding on a sled down a steep, snow-covered hill, his elevation decreases and hence Kinetic energy increases and potential energy decreases.

Hope it helps!

A charge of +1.4 × 10Ò coulombs moves from point A to B. What is the potential difference between the two points if the work done on the charge is +3.4 × 10¥ joules?

Answers

The exponents in both data quantities needed to calculate the answer have been corrupted and misprinted, so no answer is possible. Proofreading was REALLY needed for this one, but alas . . .

Projectile A is launched horizontally at a speed of 20. Meters per second from the top of a cliff and strikes a level surface below, 3.0 seconds later. Projectile B is launched horizontally from the same location at a speed of 30. Meters per second. Approximately how high is the cliff?

Answers

Answer:

The height of the cliff is $44.1\;\rm{m$ .

Explanation:

Given: Projectile $A$ is launched horizontally at a speed of $20$ Meters per second from the top of a cliff and strikes a level surface below, $3.0$ seconds later. Projectile $B$ is launched horizontally from the same location at a speed of $30$ meter per second.

Using the formula of motion: $S=ut+(1)/(2)at^2$

Substiuting all the values: $u=0\;\rm{ms^(-1), a=9.8\;\rm{ms^(-2)\;\& \;t=3.0\; seconds$

Let $h$ be the height of the cliff.

$h=0*3+0.5*(9.8)*3^2\nh=44.1\;\rm{m$

Hence, height of the cliff is $44.1\;\rm{m$ .

Learn more about Laws of motion here:

brainly.com/question/17366362?referrer=searchResults

consider the motion of projectile A in vertical direction :

v₀ = initial velocity of projectile A in vertical direction = 0 m/s (since the projectile was launched horizontally)

a = acceleration of the projectile = g = acceleration due to gravity = 9.8 m/s²

t = time of travel for projectile A = 3.0 seconds

Y = vertical displacement of projectile A = height of the cliff = h = ?

using the kinematics equation along the vertical direction as

Y = v₀ t + (0.5) a t²

h = (0) (3.0) + (0.5) (9.8) (3.0)²

h = 44.1 m

Which astronomer spent 20 years plotting the positions of the planets

Answers

Answer

Tycho Brahe

Explanation

Tycho Brahe who was born on 1546. He was an astronomer.Tycho Brahe spent 20 years in plotting the positions of the planets and he was among those astronomers who helped in giving the heliocentric model of the universe..

That was Tycho Brahe, and I thought it was actually more years than that.

A system dissipates 12 J of heat into the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the internal energy of the system?