MATHEMATICS HIGH SCHOOL

Chris wanted to buy 5 games for his PS5 each game costs $49.95. What math operation will you have to use to solve this problem?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Multiplication?

Answer 2

Answer: multiplication: 5*49.95=
or addition: 49.95+49.95+49.95+49.95+49.95=

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What is the solution to the inequality??: 1 2 x + 8 ≤ 3

What is the problem of this solving?!

Answers

This question can be solved primarily by L'Hospital Rule and the Product Rule.

$y= \lim_(x \to 0) (x^2cos(x)-sin^2(x))/(x^4)$

I) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([2xcos(x)-x^2sin(x)]-2sin(x)cos(x))/(4x^3)$

II) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)])/(12x^2) \n y= \lim_(x \to 0) (2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x))/(12x^2)$

III) Product Rule and L'Hospital Rule:

$]y= \alpha + \beta \n \n \alpha =\lim_(x \to 0) (-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)])/(24x) \n \beta = \lim_(x \to 0) (4sin(x)cos(x)+4sin(x)cos(x))/(24x) \n \n y = \lim_(x \to 0) (-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x))/(24x)$

IV) Product Rule and L'Hospital Rule:

$y = \phi + \varphi \n \n \phi = \lim_(x \to 0) (-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)])/(24x) \n \varphi = \lim_(x \to 0) ([2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)])/(24x)$

V) Using the Definition of Limit:

$y= (-6*1-4*1-2*1+8*1^2)/(24) \n y= (-4)/(24) \n \boxed {y= (-1)/(6) }$

What is the solution to the following bernoulli de?\[t^2 dy/dx+y^2=ty\]
It looks like it is homogenous because if you divide through by \[t^2\] it will be \[y/t\] all over. Also if it's a bernoulli, wouldn't \[v=y\], which isn't very useful. Any thoughts?

Answers

Here t is constant only x and y are variables so it reduces to

dy/ty-y^2 = 1/t^2(dx)

just solve it taking t as constant.

hope this helps

Let X and Y have the joint probability density function f(x,y)={3x,0

Answers

Answer:

Step-by-step explanation:

Simplify 25 pq + 13 pq-6-35pq+4=

Answers

25pq+13pq-6-35pq+4
-6+4+25Pq+13pq-35pq
-2+3pq

The two solids are similar and the ratio between the lengths of their edges is 2:9. What is the ratio of their surface areas?Can you also help me with the 2nd attachment, the question is on the picture?

Answers

Hello,

During a dilatation of ratio k (length ratio),
area are multiplied by k² and volume bu k^3.

A)
(2/9)²=4/81 answser A

B) (3/5)²=9/25 Answer D

we know that

If two solids are similar

then

the ratio of their corresponding sides are equal and is called the scale factor

Part 1)

In this problem

$scale\ factor= (2)/(9)$