MATHEMATICS COLLEGE

Solve for x x/8−9=1

x= ​

Answers

Answer 1
Answer:

Answer:

x = 80

Step-by-step explanation:

9+1=10 so x/8 must equal 10.

80/8 = 10 and subract by 9 = 1
Answer 2
Answer: 1. X/-1 (divid X to 1)
2. -1• X/-1 = 1• -1
( multiple -1 by both sides)
3. X= -1

I hope this helps

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Which of The following best describes The english expression two more than the quantity of a number minus seven? A. (X-7)+2 B. (X+2)-7 C. X/7+2 D. (2+x)-7
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In the first 1/6 hour of a rain storm, 1/10 inch of rain fell. If the rain continues to fall at the same rate, how much rain fell in 2 1/2 hours?

Answers

Answer:

3/2 inches

Step-by-step explanation:

HELP!!!!!In a group of 15 children, 5 said they are an only child, 3 said they have 1 sibling only, 4 said they have exactly 2 siblings, and 3 said they have exactly 3 siblings.

What is the average number of siblings for this group? Enter your answer as a decimal, rounded to the nearest tenth,
_______

Answers

The average number of siblings for the group is 1.3.

We must compute the total number of siblings and divide it by the total number of children in the group to determine the average number of siblings for the group.

There are a total of: siblings in the bunch.

3 + 8 + 9 = 20 (1 sibling times 3 children) + (2 siblings times 4 children) + (3 siblings times 3 children)

The total number of kids in the group is: 5 + 3 + 4 + 3 = 15

As a result, the group as a whole has an average of:

20/15 = 1.33 (rounded to the nearest tenth) (rounded to the nearest tenth)

So, the group as a whole has 1.3 siblings on average.

To know more about Average visit:

brainly.com/question/29550341

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I NEED HELPPP ASAPPPPP I WILL GIVE BRAINLIESTTTT!!!!!!a function is a binary relation between two sets that associates every element of the first set to exactly one element of the second set.

Answers

No, there are x sets that match the same one in the y set. The red one

Express the number as a ratio of integers. 3.469 = 3.469469469

Answers

If you're looking for a fractional representation of the non-terminating decimal,
3.469469469....
then:

Let x=3.469469469.....
then
1000x-x=(3469.469469469...) - (3.469469469....)
999x = 3466
x=3466 / 999
= 3+469/999
=3(469)/(999)

In circle F what is the measure of arc CB?

17.5
35
70
60

Answers

The inscribed angle theorem says that the angle formed by two intersecting chords of a circle (the angle A between the chords AC and AB in this case) has half the measure of the central angle subtended by the arc containing those chords (arc CB in this case). So

m\angle BAC=\frac12m\angle BFC\implies m\angle BFC=2\cdot35^\circ=70^\circ

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that the highest bid in excess of $10,000 will be accepted. Assume that the competitor's bid x is a is a random variable that is uniformly distributed between $10,000 and $15,000.a. Suppose you bid $12,000. What is the probability that your bid will be accepted? (please show calculations)
b. Suppose you bid $14,000. What is the probability that your bid will be accepted? (please show calculations)
c. What amount should you bid to maximize the probability that you get the property? (please show calculations)d. Suppose you know someone who is willing to pay you $16,000 for the property. Would you consider bidding less than the amount in part (c)? Why or why not?

Answers

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\nP\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\n\n = 1 - \int\limits_(12000)^(15000) {\frac{1}{{15000 - 10000}}} dx\n\n = 1 - \int\limits_(12000)^(15000) {\frac{1}{{5000}}} dx\n\n = 1 - \frac{1}{{5000}}\left[ x \right]_(12000)^(15000)\n\end{array}

=1- ([15000-12000])/(5000)\n\n=1-0.6\n\n=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\nP\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\n\n = 1 - \int\limits_(14000)^(15000) {\frac{1}{{15000 - 10000}}} dx\n\n = 1 - \int\limits_(14000)^(15000) {\frac{1}{{5000}}} dx\n\n = 1 - \frac{1}{{5000}}\left[ x \right]_(14000)^(15000)\n\end{array} P(X<14,000)=1-P(X>14000)

=1- ([15000-14000])/(5000)\n\n=1-0.2\n\n=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\nf\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\n\n{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\n\n{\rm{ = 1}}\n\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.
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