Which acid and base react in the formation of salt sodium chloride? hydrochloric acid and sodium hydroxide sodium carbonate and chlorine sodium hydroxide and sodium chloride
Answers
HCl + NaOh ----> NaCl + H2O
Related Questions
What mass of solute is needed to prepare each of the following solutions? a. 3.00 L of 0.125 M K2SO4 b. 550 mL of 0.015 M NaF c. 700 mL of 0.350 M C6H12O6
A solid compound in a sealed container was kept at a very low temperature in a freezer. When placed at room temperature, the substance quickly turned into a liquid. This compound is most likely which of the following?a.an ionic compound because it has a low boiling point b. a covalent compound because it has a low boiling point c.an ionic compound because it has a low melting point d.a covalent compound because it has a low melting point
Metals experience plastic deformation when _____.
What is the golden rule of solubility?
(B) C₂H₂
(C) CH₄
(D) H₂O
(E) C₂H6₆
Answers
......|
H—C—H
..... |
..... H
methane CH4
Answers
mass = 30g so;
30 = mol x GFM
To calculate the GFM, you require a data booklet or similar.
Mine tells me that the GFMs are:
H: 1 H₃ so 3 x 1 = 3
P: 31 P so 1 x 31= 31
O:16 O₄ so 4 x 16 = 64
GFM = 64 + 31 + 3 = 98
30 = 98 x mol
mol = 30 / 98
mol = 0.31 mol
Final answer:
To find the number of moles in 30 grams of H3PO4, divide the mass by the molar mass. In this case, there are 0.306 moles of H3PO4.
Explanation:
To determine the number of moles in 30 grams of H3PO4, we need to use the molar mass of H3PO4. The molar mass of H3PO4 is 98.0 g/mol.
We can use the following conversion factor to convert grams to moles: 1 mole = molar mass (in grams).
Therefore, the number of moles in 30 grams of H3PO4 is calculated as:
30 grams x (1 mole / 98.0 grams) = 0.306 moles of H3PO4.
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Answers
The mass of one cubic meter of gold is 19,300 kilograms.
We can use the specified density and the following formula to determine the mass of one cubic meter of gold:
Mass = Density × Volume
Given:
Density of gold = 19.3 g/cm³
Remember that when converting from cubic centimeters to cubic meters, 1 cubic meter is equal to 1,000,000 cubic centimeters.
Density = Mass / Volume
Mass = Density × Volume
Volume = 1 cubic meter = 1,000,000 cubic centimeters
Density = 19.3 g/cm³
Mass (grams) = Density × Volume = 19.3 g/cm³ × 1,000,000 cm³ = 19,300,000 g
For converting grams to kilograms, divide by 1000:
Mass (kilograms) = 19,300,000 g / 1000 = 19,300 kg
Therefore, the mass of one cubic meter of gold is 19,300 kilograms.
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Answer:
Explanation:
Question:
Gold has a density of
19.3
g
/
c
m
3
.
What is the mass, in kilograms, of one cubic meter of gold?
Density:
The density of an object is a quantity derived from the relation between mass (fundamental quantity) and volume (derived quantity). No matter the size of the object, its density will be the same because it is a constant property that is only varied when changing the mass or volume of the object. There are other factors that affect density such as temperature and pressure.
Data:
Volume:
V
=
1
m
3
Density:
ρ
=
19.3
g
c
m
3
Equation:
The equation to find the mass of the gold is given...
See full answer below.
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Density: Definition, Formula & Practice Problems
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Answers
Here, we got Z = 29 so the charge of the nucleus is 29, and A is the atomic mass.
Since the atom number (Z) is 29, so i guess the isotope is the Copper.
Isotopic notation:
Hope this Helps :)
Final answer:
The isotope with atomic number Z = 29 and atomic mass A = 65 is for Copper and its isotopic notation is 65Cu.
Explanation:
The isotope with atomic number Z = 29 and atomic mass A = 65 is for the element Copper (Cu). To write this in isotopic notation, you represent it as 65Cu. Here, the atomic number Z (number of protons) is represented by Cu and the mass number A (number of protons + neutrons) is represented by the superscript number 65. Thus, the isotope notation symbol for this is is 65Cu.
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b. positive
c. negative
Answers
Write the chemical formula of the compound produced.
Answers
Answer:
0.64 g of S
Solution:
The balance chemical equation is as follow,
2 Cu + S ----> Cu₂S
According to equation,
127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S
So,
2.54 g Cu will produce = X g of Cu₂S
Solving for X,
X = (2.54 g * 159 g) / 127 g
X = 3.18 g of Cu₂S
Now, it is confirmed that the reaction is 100% ideal. Therefore,
As,
127 g (2 mole) Cu required = 32 g (1 mole) of S
So,
2.54 g Cu will require = X g of S
Solving for X,
X = (2.54 g * 32 g) / 127 g
X = 0.64 g of S
Answer : The total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, copper oxide.
Solution :
According to the law of conservation of mass, the total mass of reactant should be equal to the total mass of product.
The balanced chemical reaction will be,
In this reaction, copper and sulfur are the reactants and copper sulfide is the product.
Let the mass of sulfur be 'x' gram
According to the law of conservation of mass,
Therefore, the total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, copper oxide.