TIMED URGENT! REALLY APPRECIATE HELP!! TYSM!!!!!What is the average Speed of the roller coaster? *

20 meters per second
20 meters per minute
20 m/hr
TIMED URGENT! REALLY APPRECIATE HELP!! TYSM!!!!! What is the average - 1

Answers

Answer 1
Answer:

Answer:

1st

Explanation:

Answer 2
Answer:

20 meters per second

Explanation:

look at the chart


Related Questions

A 405 Hz tuning fork and a piano key are struck together, and no beats are heard. When a 402 Hz tuning fork and the same piano key are struck, three beats are heard. What is the frequency of the piano key?
How many electrons does an atom with 8 protons and no charge have? 7 9 5 8 please help
Wave C has an amplitude of 1 and wave D has an amplitude of 3 as shown below. What will happen when the trough of wave C meets the crest of wave D?
Which phrase is an example of kinetic energy? Responses a car sitting motionless a car sitting motionless a girl running in a race a girl running in a race a sled sitting at the top of a hill a sled sitting at the top of a hill a tank containing gasoline
What is the slope of the line if the rise of a line on a distance versus-time graph is 900 meters and the run is 3 minutes?

Which of these are types of meteorites? Select all that apply.a. ice
b. iron
c. stony
d. Kuiper

Answers

The types of meteorites are iron, stone and iron-stony meteorites. The stony-iron meteorites account for less than 2% of all known meteorites. They comprised of roughly equal amounts of nickel-iron and stone and are divided into two groups: pallasites and mesosiderites. The answers are only B and C

A body of mass 2 kg is moving in the positive X-Direction with a speed of 4 m/s collides head on with an another body of mass 3 kg moving in the negative X-Direction with a speed of 1 m/s . During collision a loud sound is heard and they both start moving together . the sound energy cannot be greater than :A) 12 J
B) 14 J
C) 15 J
D) 17.5 J

Answers

m_1=2 \n m_2=3 \n v_1=4 \n v_2=1 \n v\text{ =speed after collision (to be determined)}.

The momentul of the system preserves:

m_1v_1-m_2v_2=(m_1+m_2)v \ \ \ \ \ \Rightarrow \ \ \ \ \ v=(m_1v_1-m_2v_2)/(m_1+m_2).

Ok, we found the speed after the collision.
Now, because the impact is plastic, it produces heat, sound energy and who knows what other forms of energy. We denote all this wasted energy with E.

Now, we write the energy conservation law:

(m_1v_1^2)/(2)+(m_2v^2_2)/(2)=((m_1+m_2)v^2)/(2)+E

From the above equation, you find E,  and then conclude that the sound energy can certainly not be greater than this.

A car travels at a steady speed of 10 m/s. What distance is covered in a minute?

Answers

Answer:

600

Explanation:

10*60=600

You multiply it by 60 because it is saying that it travels 1 mile per second and there are 60 seconds in one minute.

What is the density of water?
gram/mL
(fill in the number)

Answers

Answer:

1.00 gram per milliliter (1 g/mL). In other words, 1 milliliter of water has a mass of 1 gram. A drop of water is 0.05 mL of water, so its mass would be 0.05 grams.

Explanation:

The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth, d, and inversely as the length, l. A wooden beam 3in. wide, 6in. deep, and 11ft long holds up 1213lb. What load would a beam 6in. wide, 3in. deep and 12ft long of the same material support? (Round off your answer to the nearest pound.)

Answers

Answer:

L' = 555.95 lb

Explanation:

Analyzing the given conditions in the question, we get

The safe load, L is directly proportional to width (w) and square of depth (d²)

 also,

L is inversely proportional length (l) i.e L = k/l

combining the above conditions, we get an equation as:

 L = k(wd²/l)

 now, for the first case we have been given

w = 3 in

d = 6 in

l = 11 ft

L = 1213 lbs

 thus,

1213 lb = k ((3 × 6²)/11)

or

k = 123.54 lbs/(ft.in³)  

Now,

Using the calculated value of k to calculate the value of L in the second case  

in the second case, we have

w = 6 in

d =3 in

l = 12 ft

Final Safe load L' =  123.54 × (6 × 3²/12)

or

L' = 555.95 lb

Final answer:

The load that a beam of the given dimensions can support is derived using a joint variation formula. The constant of variaiton is found using the given beam's characteristics, and then applied on the second beam's measurements to find its load. The result is approximately 2025 pounds.

Explanation:

The question is related to joint variation and its principles in mathematics. First, it's necessary to define the equation of the joint variation:
L = k*(w*d^2)/l
where L is the load, w is the width, d is the depth, l is the length, and k is the constant of proportionality. From the information given in the question, we can derive that k equals to 1213 * 11 / (3 * 6^2), which is approximately 135. Then, we substitue the values of the second beam into the equation, w = 6, d = 3, l = 12 and k = 135, to get the load L for the second beam, which equates to about 2025 pounds.

Learn more about Joint Variation here:

brainly.com/question/33421771

#SPJ6

Look at Figure 2. Describe the motion of the object in Graph ACompare Graphs A and B in Figure 2. At a time of 2 seconds, which graph shows a greater velocity? How do you know?

Answers

The graphs show distance versus time data. For graph A, we can say that velocity is constant until it reaches time of 8 seconds. And a constant velocity is again exhibited starting at time 12 seconds. For graph B, the velocity is changing as time pass by since  the slope is changing. At time of 2 seconds, graph A has greater velocity since it has a steeper slope.