A sample of silver contains 5.71x10^22 atoms. how many moles of silver are present

Answers

Answer 1

Answer:

According to the concept of Avogadro's number, there are 0.0948 moles of silver present in 5.71×10²² atoms of silver.

What is Avogadro's number?

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number

Therefore, number of moles=number of atoms/Avogadro's number

number of moles=5.71×10²²/6.023×10²³=0.0948

Thus, there are 0.0948 moles in 5.71×10²² atoms of silver.

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Answer 2

Answer:

N=n×Nav

n=N / Nav

(5.71×10^22) / (6.02×10^23)

n=0.09mol

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How many molecules are in 2.47 moles of CC14? *

Answers

Answer:

1.49x10^24 molecules

A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate. 2KClO3 mc019-1.jpg 2KCI + 3O2 What is the percent yield of oxygen in this chemical reaction?

Answers

The balanced equation that describes the reaction of heatinf potassium chlorate to produce potassium chloride and oxygen is expressed 2KClO3 = 2KCI + 3O2. For a 400 g potassium chloride, using stoichiometry, the mass oxygen produced is 156.67 grams oxygen. The actual product weighed 115.0 grams. Yield is equal to 115/156.67 or 73.74%

Answer:

The percent yield of oxygen in this chemical reaction is 73.71 %.

Explanation:

Experimental yield of oxygen gas = 115.0 g

Theoretical yield:

$2KClO_3rightarrow 2KCI + 3O_2$

Mass of potassium chlorate = 400.0 g

Moles of potassium chlorate = $(400 g)/(122.5 g/mol)=3.2653 mol$

According to reaction, 2 moles of potassium chlorate gives 3 moles of oxygen gas.

Then 3.2653 mol of potassium chlorate will give:

$(3)/(2)* 3.2653 mol=4.89795 mol$

Mass of oxygen gas :

$32 g/mol* 4.89795 mol=156.73 g$

Percentage yield:

$\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100$

$\%=(115.0 g)/(156.73 g)* 100=73.71\%$

The percent yield of oxygen in this chemical reaction is 73.71 %.

Hydrogen has three isotopes 1H, 2H, and 3H. What is the difference between these three isotopes?

Answers

The main difference between the 3 isotopes of hydrogen are the number of neutrons in the nucleus. Hydrogen has no neutrons, Deuterium has one neutron, and tritium has two neutrons. All three have one proton and one electron.

How is 0.00025 written in scientific notation

Answers

2.5 × 10⁴ is the scientific notation for 0.00025. this is done by moving decimal to the first non zero number.

When a number is too big or too tiny to be readily stated in decimal form, or if doing so would involve writing down an exceptionally lengthy string of digits, it can be expressed using scientific notation. It is also known as standard form within the UK and scientific form, standard index form, and standard form. Scientists, mathematicians, or engineers frequently utilise this base ten notation because it may make some mathematical operations simpler. 2.5 × 10⁴ is the scientific notation for 0.00025. this is done by moving decimal to the first non zero number.

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Answer:

2.5 * 10^4

Explanation:

A chemist who is performing this reaction starts with 160.1 g of NH4NO3. The molar mass of NH4NO3 is 80.03 g/mol; the molar mass of water (H2O) is 18.01 g/mol. What mass, in grams, of H2O is produced?

Answers

the answer
the general equation of the reaction is
NH4NO3 -------------- N2O + 2H2O

The molar mass of NH4NO3 is 80.03
The mass of NH4NO3 is 160.1 g
so we can deduce that

nNH4NO3 = number of mole of NH4NO3 = 160.1 g / 80.03 =2 moles
by using proportion property

NH4NO3 -------------- N2O + 2H2O
1mole 1mole 2 moles
nNH4NO3 nH2O

the number of mole nH2O can be found by

1/ nNH4NO3 = 2 / nH2O

nH2O = 2 x nNH4NO3 = 2 x 2 = 4 moles
to find the mass, we use

mH2O = 4 moles x 18.01 g /mol = 36 g

Answer:

80.0

Explanation:

edge 2020

(True or False) It would be most appropriate to use the noble gas core [He] when writing the shorthand electron configuration for sulfur.