Answer:
0.295 mol/L
Explanation:
Given data:
Volume of solution = 3.25 L
Mass of BaBr₂ = 285 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of solute:
Number of moles = mass/ molar mass
Molar mass of BaBr₂ = 297.1 g/mol
Number of moles = 285 g/ 297.1 g/mol
Number of moles= 0.959 mol
Molarity:
M = 0.959 mol / 3.25 L
M = 0.295 mol/L
The question is about calculating the molarity of a solution. First, convert the given mass of solute into moles using the molar mass. Then, using the molarity formula, divide the moles of solute by the volume of the solution in liters.
In order to determine the molarity of the solution, we will divide the amount of solute (in moles) by the volume of the solution (in liters). The formula for molarity (M) is:
M = moles of solute/volume of solution in liters
First, we need to convert the mass of BaBr2 into moles. The molecular weight of BaBr2 is 297.14 g/mol. So, 285 g of BaBr2 is equal to 285/297.14 = 0.959 moles.
The volume of the solution is given as 3.25 L. So, plugging these values into the formula gives us the molarity of the solution:
M = 0.959 moles/3.25 L = 0.295 M
So, the molarity of the solution is 0.295 M.
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Answer:
8.08 grams
Explanation:
Given;
Mass of the steam, m = 100 g
Change in temperature of water = (95°C - 35°C) = 60°C
Change in temperature of steam = (110°C - 100°C) = 10°C
let the mass of water by 'M'
also,
We know
specific heat of water, c = 4.184 J/Kg.°C
And, specific heat of steam, C = 2.03 J/Kg.°C
Now,
Heat released = Mass × specific heat × change in temperature
thus, for the condition given in the question
M × 4.184 × 60 = 100 × 2.03 × 10
or
M = 8.08 grams
The mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110C to 100C is 125 grams. To solve this question, we used the specific heat of water, calculated the heat produced in the latter scenario, and deduced the mass needed from that.
To determine the mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110 to 100C, we need to first calculate the amount of heat produced in the latter situation. Using the specific heat of water which is 4.184 J/g °C, the heat produced when cooling 100g of steam from 110C to 100C is Q=msΔT, where m is mass, s is specific heat, and ΔT is temperature difference. So, Q = 100g * 4.184 J/g°C * (110°C - 100°C) = 4184 J.
Now, we have to calculate the mass of water that will produce the same amount of heat when cooled from 95°C to 35°C. We rearrange the equation to solve for mass. Hence, m = Q/sΔT = 4184 J / 4.184 J/g°C / (95.0 °C - 35.0 °C) = 125g. Therefore, 125g of water will provide the same amount of heat when cooled from 95.0 to 35.0 C.
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fluorate
nitrogen
nitrite
Could you explain how to find this? The process?
Answer:
the answer is nitrogen
B. -1,+1,0
C. -2,+3,-1
D. 0,0,0
Three resonance structures contribute to the structure of dinitrogen monoxide.
The resonance structure is invoked when a single structure can not sufficiently explain all the bonding properties of a compound. All the various contributing structures contribute to the final structure of the compound but not all to the same degree.
There are three resonance structures of dinitrogen monoxide. The most stable structure is always the structure that has the formal charges as -1, +1 and zero as shown.
Learn more: brainly.com/question/14283892
Answer:
A. 0, +1, -1
Explanation:
You can draw the lewis structure for NNO 3 ways: With two double bonds N=N=O, with a triple bond between the N and O and single bond between the two N's, or a triple bond between the two N's and a single bond between the N and O.
The goal is to have formal charges that are as small as possible, to have no identical formal charges on adjacent atoms, and to have the most negative formal charge on the most electronegative atom. The most stable structure is the one with the triple bond between the two N's because it gives the formal charges 0, 1, and -1 respectively. Unlike the other two structures, the negative formal charge is correctly placed on O, the most electronegative atom.
i) Before adding NaOH
ii) After adding 24.00 mL NaOH
Answer:
i) pH = 0.6990
ii) pH = 2.389
Explanation:
i) Before adding aqueous NaOH, there are 25.00 mL of 0.2000 M HCl. HCl reacts with the water in the aqueous solution as follows:
HCl + H₂O ⇒ H₃O⁺ + Cl⁻
The HCl and H₃O⁺ are related to each other through a 1:1 molar ratio, so the concentration of H₃O⁺ is equal to the HCl concentration.
The pH is related to the hydronium ion concentration as follows:
pH = -log([H₃O⁺]) = -log(0.2000) = 0.699
ii) Addition of NaOH causes the following reaction:
H₃O⁺ + NaOH ⇒ 2H₂O + Na⁺
The H₃O⁺ and NaOH react in a 1:1 molar ratio. The amount of NaOH added is calculated:
n = CV = (0.2000 mol/L)(24.00 mL) = 4.800 mmol NaOH
Thus, 4.800 mmol of H₃O⁺ were neutralized.
The initial amount of H₃O⁺ present was:
n = CV = (0.2000 mol/L)(25.00 mL) = 5.000 mmol H₃O⁺
The amount of H₃O⁺ that remains after addition of NaOH is:
(5.000 mmol) - (4.800 mmol) = 0.2000 mmol
The concentration of H₃O⁺ is the amount of H₃O⁺ divided by the total volume. The total volume is (25.00 mL) + (24.00 mL ) = 49.00 mL
C = n/V = (0.2000 mmol) / (49.00 mL) = 0.004082 M
The pH is finally calculated:
pH = -log([H₃O⁺]) = -log(0.004082) = 2.389
Answer:
Because the water is filled up with the sand every where
Explanation:
So the exess sand goes to the bottem
Answer:
Mass/Volume
Explanation:
The sand eventually makes it way to the bottom because of its mass/volume compared to the waters density. Just like while swimming in a pool, we sink to the bottom because of our mass/volume.