6x-5y=22 y=-8 using systems of equations by substitution

Answers

Answer 1

Answer: We need to sub y=-8 into the first equation
6x+40=22
6x=-18
x=-3

Answer 2

Answer: $\left \{ {{6x-5y=22} \atop {y=-8}} \right. \n\n substitute\ y=-8\ into\ first\ equation\n\n6x-5*(-8)=22\n\n6x+40=22\ \ \ | subtract\ 40\n\n6x=-18\ \ \ | divide\ by\ 6\n\nx=-3\n\ny=-8$

Related Questions

What is 8t^5 times 8t^5?I thought you were suppose to keep the bases the same and just add the powers.
Help me please help me helpm
) If the base of the panel is 31.2 inches and the height is 18 inches, what is the area of one triangular section? Show your work
Dakota read 130 pages over the weekend. Dajuan read 165 pages over the weekend. Which prime number do the prime factorization of 130 and 165 have in common?
5 times the sum of 12 and a number is 80What is the value of the unknown number

What is the means-to-MAD ratio of the two data sets, expressed as a decimal to the nearest tenth?Data Set 1: {43, 42, 56, 62, 72}
Data Set 2: {76, 57, 81, 51, 70}

Answers

Frist we need to find the mean of both so

1.55

2.67

then we make a number graph and see how mant place does it take to get to them from 0 67and55/by them selfs = 1.2(rounded)

1.2 is you answer

last week Cy earned slightly more money than he spent. is his net income represented by a positive number or a negative number? Explain.

Answers

It's a positive number. Here's why:
Let's say he earned $10 and only spent $9. This means he would have $1 left. That isn't much, but it is still a positive number because he did not spend more than he made. For example, if he spent more than he made, it would look like this: He made $10, but spent $11, which leaves him with a debt of $1, which can be represented by $-1.

Can someone help me with the following questions with work!!1. A prism is filled with 25 cubes with 1_2-unit side lengths. What is the volume of the prism in cubic units?
2. A rectangular prism-shaped gift box measures 8 inches long by
10 inches wide by 3 inches high. What is the surface area of the box?
3. Miguel is painting a cabinet shaped like a rectangular prism. He is going to paint all of the exterior sides except the top and the bottom. The cabinet is 6 feet tall, 4 feet wide, and 2 feet deep. What is the surface area of the portion of the cabinet that Miguel is going to paint?

Answers

1. each cube is 1/8 of a cubic unit, so the volume total would be 3 and 1/8 cubic unit
2. 268 in^2
3. 9/11

Solve the equation. Check your answer. If necessary, round to 3 decimal places In (t - 1) + In x^2 = 6, X=

Algebra 2

Answers

Answer:

x ≈ ±20.086/√(t - 1)

Step-by-step explanation:

ln(t - 1) + ln(x²) = 6

Recall that lnu + lnv = ln(uv). Then

ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6

Take the natural antilogarithm of each side

(t - 1)x² = e⁶

Divide each side by t - 1

x² = e⁶/(t-1)

Take the square root of each side

x = ±e³/√(t - 1)

x ≈ ±20.086/√(t - 1)

Bonnie and some friends went to an amusement park. They bought rve of thesame lunches and 3 desserts and spent a total of $60.25 on the food. Eachdessert costs $5.25 less than one of the lunches.a. Detine a variable: Write an equation that can be used to find the cost oflunch.b. Solve the equation to find the cost of a lunch.en5.2

Answers

Let the variable be the cost of the lunch: x

so they bought 5 lunches: 5x
deserts are cheaper than lunches; they cost:
x-5.25
So together they paid:
5x+3*(x-5.25)=60.25

(we know how much they paid, so we can make an equation)

Let's remove the bracket:
5x+3*x-15.75=60.25

8x-15.75=60.25//we add 15.75 to both sides:
8x=76
and divide by 8:
x=9.5

So each lunch costs 9.5 dollars!

PLEASEE HURRY!!!!!!!! Tom determines that the system of equations below has two solutions, one of which is located at the vertex of the parabola.
Equation 1: (x – 3)2 = y – 4
Equation 2: y = -x + b
In order for Tom’s thinking to be correct, which qualifications must be met?
A: b must equal 7 and a second solution to the system must be located at the point (2, 5).
B: b must equal 1 and a second solution to the system must be located at the point (4, 5).
C: b must equal 7 and a second solution to the system must be located at the point (1, 8).
D: b must equal 1 and a second solution to the system must be located at the point (3, 4).