OFFERING 60 POINTS IF YOU CAN SHOW THE WORK!!!!A 1000 kg roller coaster begins on a 10 m tall hill with an initial velocity of 6m/s and travels down before traveling up a second hill. As the coaster moves from its initial height to its lowest position, 1700J of energy is transformed to thermal energy by friction.
Answers
Answer; 10.6 i think
Explanation:
(a) At the top of the hill, the coaster has total energy (potential and kinetic)
E = (1000 kg) g (10 m) + 1/2 (1000 kg) (6 m/s)² = 116,000 J
As it reaches its lowest position, its potential energy is converted to kinetic energy, and some is lost to friction, making its speed v such that
1/2 (1000 kg) v ² = 116,000 J - 1700 J = 114,300 J
===> v ≈ 15.2 m/s
If no energy is lost to friction as the coaster makes its way up the second hill, all of its kinetic energy would be converted to potential energy at the maximum possible height H.
1/2 (1000 kg) (15.2 m/s)² = (1000 kg) gH
===> H ≈ 11.7 m
(b) At the top of the second hill with minimum height h, and with maximum speed 4.6 m/s, the coaster has energy
E = P + K = (1000 kg) gh + 1/2 (1000 kg) (4.6 m/s)²
Assuming friction isn't a factor again, the energy here should match the energy at the lowest point in part (a), 114,300 J.
(1000 kg) g h + 1/2 (1000 kg) (4.6 m/s)² = 114,300 J
===> h ≈ 10.6 m
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Answers
Answer:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Explanation:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Also notice that convex mirror always makes virtual images.
Another feature of the convex mirror is that an upright image is always formed by the convex mirror.
An important mirror formula to remember which is applicable for both convex and mirrors
- 1/f= 1/u + 1/v
Here:
'u' is an object which gets placed in front of a spherical mirror of focal
length 'f' and image 'u' is formed by the mirror.
Answer:
right side up
Explanation:
Answers
Answer:
Explanation:
When the spring is compressed by .80 m , restoring force by spring on block
= 130 x .80
= 104 N , acting away from wall
External force = 82 N , acting towards wall
Force of friction acting towards wall = μmg
= .4 x 4 x 9.8
= 15.68 N
Net force away from wall
= 104 -15.68 - 82
= 6.32 N
Acceleration
= 6.32 / 4
= 1.58 m / s²
It will be away from wall
Energy released by compressed spring = 1/2 k x²
= .5 x 130 x .8²
= 41.6 J
Energy lost in friction
= μmg x .8
= .4 x 4 x 9.8 x .8
= 12.544 J
Energy available to block
= 41.6 - 12.544 J
= 29 J
Kinetic energy of block = 29
1/2 x 4 x v² = 29
v = 3.8 m / s
This will b speed of block as soon as spring relaxes. (x = 0 )
Answers
Answer:
None, both objects will hit ground at the same time.
Explanation:
- Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:
- As the left side in (1) is the same for both objects, the right side will be the same also.
- Since g is constant close to the surface of the Earth, it's also the same for both objects.
- So, the time t must be the same for both objects also.
Answers
Answer:
-384.22N
Explanation:
From Coulomb's law;
F= Kq1q2/r^2
Where;
K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2
q1 and q2 = magnitudes of the both charges
r= distance of separation
F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2
F= -495.65 × 10^-3/ 1.29 × 10^-3
F= -384.22N
Answers
Answer: the first shows the speakers actions; the second shows the beloveds opposition to them
Explanation:
Answers
Answer:
1.0 dioptres
Explanation:
Farsightedness is an eye defect in which a person can see far objects clearly but not near objects. That implies that the patients' near point is farther than 25cm which is the normal least distance of distinct vision.
Farsightedness results from the eyeball being too long or the crystalline lens not being sufficiently converging.
Carol is farsighted with a near point of about a meter (100cm). We desire to make a lens to enable her near point be reduced to about 50cm. The focal length and power of this lens is calculated in the image attached.
The power of a lens is the inverse of its focal length in meters hence the 100 in the formula for power of the lens.
Answer:
+1.00 diopter
Explanation:
The power of a lens can be described simply as the reciprocal of the focal length of the lens measured in meters.
But f is unknown, hence we look for the focal length with the formula
1/f = 1/u + 1/v
where u is former near point = 100cm
v is the new intended near point = 50cm
1/f = 1/50 - 1/100
1/f = 1/100
f = 100 cm
Hence we get Power (D) = 1/f
where f = focal length of the lens in meter
From the question, the focal length of the lens = 100cm = 1m
Hence D = 1/1
D = +1.00
Hence the refractive power of the reading glasses that would allow Carol to read a book 50cm away from the relaxed eye will be +1.00 diopters.