MATHEMATICS HIGH SCHOOL

Please help If triangle ABC is dialted by a scale factor of 2 and the origin as it's center, what would be the coordinates of A'?

A.(4,2)
B.(9,9)
C.(6,6)

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please help If triangle ABC is dialted by a scale - 1

Answers

Answer 1
Answer: It would be C since a scale factor of 2 makes the original A coordinate of (3,3) times 2 therefore the new coordinates being (6,6)

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Joe paid $14.00 for a board game this is 70% of the original price what was the original price

Answers

Answer:

The original price was $20.00

Step-by-step explanation:

Joe paid $14.00 for a board game.

This is the 70% of the original price.

Let the original price of a board game be x

70% of x = $14.00

0.70x = 14.00

x = (14)/(0.7) = $20.00

The original price was $20.00

start off by finding 10% of $14. in order to find 10%, divide it by 70 which gives 2. you now need to make the 30% to add to the 70%, by timesing the 2 by 3to give 6. now all you need to do it add the 6 to 14 to make 20!

so your answer is $20

you have 160 boxes of cookies, in each case you can pack 8 boxes. how many cases will be packed from these cookies ?

Answers

1 case=8 boxes of cookies   and we have 160 boxes
160/8=20
we will have 20 cases

The equation of a line a is given by 3y=x+12- Find line b that is parallel to line a and passes through the point (6, -8)

Answers

Answer is x-3y=-12. Get Photomath it’s app

the product of two integers is -21. the diference between the two integers is -10. the sum of the two integers is 4. what are the two integers

Answers

it would be 7 and -3
7 x -3 = -21
difference = -10
the sum = 4

hope this helps you
The two integers are -3 and 7.

if  sin (α+β) = 1,  sin (α-β) = 1/2 then tan (α+2β) tan(2α+β) = a. 1          b.-1            c.0              d. none

Answers

\alpha;\ \beta\in(0^o;\ 90^o)\n\nsin(\alpha+\beta)=1\to sin(\alpha+\beta)=sin90^o\to\alpha+\beta=90^o\n\nsin(\alpha-\beta)=(1)/(2)\to sin(\alpha-\beta)=sin30^o\to\alpha-\beta=30^o\n\n +\left\{\begin{array}{ccc}\alpha+\beta=90^o\n\alpha-\beta=30^o\end{array}\right\n---------\n.\ \ \ \ \ \ \ 2\alpha=120^o\ \ \ /:2\n.\ \ \ \ \ \ \ \ \ \alpha=60^o\n\n60^o+\beta=90^o\ \ \ /-60^o\n\beta=90^o-60^o\n\beta=30^o


tan(\alpha+2\beta)\cdot tan(2\alpha+\beta)\n\n=tan(60^o+2\cdot30^o)\cdot tan(2\cdot60^o+30^o)\n\n=tan120^o\cdot tan150^o=tan(180^o-60^o)\cdot tan(180^o-30^o)\n\n=-tan60^0\cdot(-tan30^o)=-\sqrt3\cdot(-(\sqrt3)/(3))=(3)/(3)=1\n\n\nAnswer:A

4) -4x - 10.2
I need the answer to this question asap please.

Answers

Answer: -2.55

Explanation: First add 10.2, and then the equation becomes -4x = 10.2.

Then, you just divide by -4 from both sides of the equation, and you get x = -2.55. :]

Answer:

21 - 4x

Step-by-step explanation:

Multiply 10 and 2 to get 20.

41 - 4x - 20

Subtract 20 from 41 to get 21.

21 - 4x
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