MATHEMATICS COLLEGE

Guided Practice1. A manufacturer gets a shipment of 600 batteries of which 50 are
defective. The quality control manager tests a random sample of
30 batteries in each shipment. Simulate the test by generating random
numbers between 1 and 600. How well does your sample represent the
shipment? Explain. (Explore Activities 1 and 2)

Answers

Answer 1

Answer:

Answer:

18.33

Step-by-step explanation:

600 -50 ÷ 30

550 ÷30 = 18.333

Related Questions

What angle during the first revolution will have the same sin value as 20.5 degrees? Enter only a number.
A : undefined B: ZeroC: Positive D:Negative
Employees at a large company are surveyed about their health insurance status. Employees are coded as "1" if health insurance is obtained through the company’s benefit program, "2" if health insurance is obtained from another source (such as through a spouse’s employment benefit program), or "0" if the employee does not have health insurance. This variable is:categorical numerical quantitatively categorical All answers of the answer options are correct.
Last one anyone know it?
The product of y and 9

Help! due in a min!Find the angle measures for the following:
m<1=___ m<4=___

Answers

Answer:

m∠1 = 20°

m∠4 = 110°

Step-by-step explanation:

m∠1 + 70° = 90°

m∠1 = 20°

70° + m∠4 = 180°

m∠4 = 110°

Answer:

$\boxed{m \angle1 \: = 20} \n \n \boxed{m \angle4 = 110}$

Step-by-step explanation:

$m \angle1 \: =90 - 70 = 20 \n m \angle4 = 360 -( 180 + (180 - 110)) \n m \angle4 = 360 - 250 \n m \angle4 = 110$

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coordinate of the ordered pair represents the first die and the second coordinate represents the second die. If the dice are ‘fair’, then all 36 of these possible outcomes are equally likely. 28. Describe the event E that the sum of the two dice is 5. 29. Find P(E). 30. Let F be the event that the number of the first die is exactly 1 more than the number on the second die. Find P(F|E)

Answers

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=(1)/(9)$

$P(F|E)=(1)/(4)$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒

$P(E)=(4)/(36)=(1)/(9)$ ⇒

$P(E)=(1)/(9)$

Finally we are going to define the event $F$ ⇒

$F$ : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

$F$ = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = $P(A,B)$

We define the conditional probability as

$P(A|B)=(P(A,B))/(P(B))$ with $P(B)>0$

We need to find $P(F|E)$ therefore we can apply the conditional probability equation :

$P(F|E)=(P(F,E))/(P(E))$ (I)

We calculate $P(E)=(1)/(9)$ at the beginning of the question. We only need $P(F,E)$ .

Looking at the sets $E$ and $F$ we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

$P(F,E)=(1)/(36)$

Replacing both probabilities calculated in (I) :

$P(F|E)=(P(F,E))/(P(E))=((1)/(36))/((1)/(9))=(1)/(4)=0.25$

We find out that $P(F|E)=(1)/(4)=0.25$

Final answer:

When rolling two dice, there are 4 combinations that sum to 5. Hence, probability P(E) is 1/9. If considering the event F where the roll on the first die is 1 more than on the second die, it has 5 possible outcomes. So P(F) is 5/36. However, if event E has already happened, P(F|E) is 1/4.

Explanation:

The subject of this question is probability, which is part of Mathematics, specifically, it is a high school-level question. The event E described here is the scenario in which the sum of the numbers rolled on the two dice equals 5. There are 4 possibilities for this event: (1,4), (2,3), (3,2), and (4,1). As there are 36 possible outcomes when rolling two dice, the probability P(E) is 4/36 = 1/9.

Now considering event F where the number on the first die is exactly 1 more than the number on the second die, we have five possible pairs: (2,1), (3,2), (4,3), (5,4), (6,5). So the P(F) is 5/36. However, we're asked to find P(F|E), the probability of event F given that event E has occurred. Looking at the pairs that fit both conditions, we see that there is only one pair: (3,2). Therefore, P(F|E) is 1/4.

Learn more about Probability here:

brainly.com/question/22962752

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Kendra is participating in a fundraiser walk-a-thon she walks 4 miles in 60 minutes how many minutes will it take to walk 7 miles

Answers

Answer:

105 min

Step-by-step explanation:

60 minutes ÷ 4 miles= 15 minutes per mile

15min per mile x 7 miles = 105 minutes

You own a share of a stock worth $400 . It decreases 5% .how much is it worth now?

Answers

Answer:

380$

Step-by-step explanation:

Multiply 400*5%=20

Then subtract 400-20=380

Answer:

$380

Step-by-step explanation:

Lysera enjoys exploring her land on horseback with its lush green valleys and ancient forests. She can cover a great deal of ground on her horse, Princess Grey Dawn, traveling at 9 km/h. Unfortunately Lysera has allergies. How far would Lysera and Princess Gray Dawn have moved while Lysera’s eyes were shut for 0.50 s during a hard sneeze? (answer in kilometers)