I dont understand graphs at all
i dont understand graphs at all - 1

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Answer 1
Answer:

Answer:

cool?

Step-by-step explanation:

Answer 2
Answer: Same same same same same

Related Questions

Shalika bought a purse for $120. The tax rate is 9%
Which one of these graphs does not illustrate a function? And why
2) A product originally costs $125. If the product goes on sale for 20% off, and then goes on sale for an additional 30% off, what is the price of the product? A.      $62.50  B. $70  C.   $65  D.    $90  3) If you pay $22.90 for a DVD that includes a 7% sales tax, what is the price of the DVD before the sales tax? A.      $21.40    B.  $21.30  C.      $21.50  D.    $20.95  
Bryan worked 32 hours last week. His regular hourly wage is $7.50 per hour. Calculate his gross earnings for the week.His employer deducts 7.65% of his gross pay for Social Security and Medicare 15% of his gross pay for income taxes Bryan's net pay for the week, rounded to the nearest dollar, will be $ __________.
if you horizontally shift the square root parent function, F(x) = , left four units, what is the equation of the new function?

Find the first five terms of the sequence defined by each of these recurrencerelations and initial conditions.
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1

Answers

a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.

c) The first five terms of the sequence are 2, -1, -3, -2, 1.

To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.

a) an = 6an-1, a0 = 2

The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592

So, the first five terms of the sequence are 2, 12, 72, 432, 2592.

b) an = −2an-1, a0 = −1

The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16

So, the first five terms of the sequence are -1, 2, -4, 8, -16.

c) an = an-1 – an-2, a0 = 2, a1 = −1

The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1

So, the first five terms of the sequence are 2, -1, -3, -2, 1.

Learn more about Recurrence

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The two legs (shorter sides ) if a right angle triangle have lengths of 15 cm and 8 cm respectively. Determine the length of the largest third side (to the nearest cm).

Answers

By Pythagoras theorem,
h^2=a^2+o^2
Longest side is the same as the hypotenuse (h)
h^2=8^2+15^2
h^2=64+225
h^2=289
Square root both sides
h=17 cm

Which shows one way to determine the factors of x3 + 4x2 + 5x + 20 by grouping? x(x2 + 4) + 5(x2 + 4) x2(x + 4) + 5(x + 4) x2(x + 5) + 4(x + 5) x(x2 + 5) + 4x(x2 + 5)

Answers

x²(x + 4) + 5(x + 4)

Further explanation

Factoring (also called factorization) is the reserve operation of multiplication. When we factor (or factorize) a polynomial, we write it as a product of its factors.

Grouping is one of the factoring methods. Other methods such as isolating common factors and identities.

Steps for grouping:

  • We group the terms with a common factor.
  • We can isolate a common factor and put it outside the parentheses.

Let’s start.

\boxed{ \ x^3 + 4x^2 + 5x + 20 = \ ? \ }

\boxed{ \ = (x^3 + 4x^2) + (5x + 20) \ }

\boxed{\boxed{ \ = x^2(x + 4) + 5(x + 4) \ }}

We can also group the terms as follows.  

\boxed{ \ x^3 + 4x^2 + 5x + 20 = \ ? \ }

\boxed{ \ = (x^3 + 5x) + (4x^2 + 20) \ }

\boxed{\boxed{ \ = x(x^2 + 5) + 4(x^2 + 5) \ }}

We will get the same results from the two ways above. Let's see.

  • First group, \boxed{ \ x^2(x + 4) + 5(x + 4) \ } \rightarrow \boxed{ \ (x + 4) (x^2 + 5) \ }
  • Second group, \boxed{ \ x(x^2 + 5) + 4(x^2 + 5) \ } \rightarrow \boxed{ \ (x^2 + 5) (x + 4) \ }

Thus the part which shows one way to determine the factors of x³ + 4x² + 5x + 20 by grouping is\boxed{\boxed{ \ x^2(x + 4) + 5(x + 4) \ }}

Learn more

  1. Which expression is equivalent to the product of a binomial and a trinomial after it has been fully simplified brainly.com/question/1394854
  2. The y-intercept of the quadratic function  f(x) = (x – 6)(x – 2) brainly.com/question/1332667
  3. Which is the graph of f(x) = (x - 1)(x + 4) brainly.com/question/2334270

Keywords: which shows, one way, to determine, the factors of x³ + 4x² + 5x + 20, by grouping, common factor, polynomial, identities

The correct option is \fbox{\text{Option B}} that is {x^2}\left( {x + 4} \right) + 5\left( {x + 4} \right) that shows one way to determine the factors of {x^3} + 4{x^2} + 5x + 20.

Further explanation:

Factors are the numbers if we multiply them we get the original number.

Factorization is finding the numbers if we multiply them we get the original number.

Prime factorization is finding the numbers if we multiply them we get the original number.

Given:

The polynomial is {x^3} + 4{x^2} + 5x + 20.

The options are,

A. x\left( {{x^2} + 4} \right) + 5\left( {{x^2} + 4} \right).

B. {x^2}\left( {x + 4} \right) + 5\left( {x + 4} \right).

C. {x^2}\left( {x + 5} \right) + 5\left( {x + 5} \right).

D. x\left( {{x^2} + 5} \right) + 4x\left( {{x^2} + 5} \right)

Explanation:

Consider the polynomial {x^3} + 4{x^2} + 5x + 20 as P\left( x \right).

Steps involve in finding the factors of {x^3} + 4{x^2} + 5x + 20 are as follows,

First we have to make the groups of the terms as,

P\left( x \right) = \left( {{x^3} + 4{x^2}} \right) + \left( {5x + 20} \right)

Now factorize the above 2 groups.

\begin{gathered}P\left( x \right) = {x^2}\left( {x + 4} \right)+5\left( {{x^2}+4} \right)\n= \left( {{x^2}+5} \right)\left( {x+4} \right) \n\end{gathered}

The factors of {x^3} + 4{x^2} + 5x + 20\text{ } \text{are} \left( {{x^2} + 5} \right) \text{and} \left( {x + 4} \right).

Option A is not correct as the first common factor is x from group one but it not the highest common factor.

\fbox{\text{Option B}} is correct as the factors are same as the factors of the polynomial.

Option C is not correct as the factors are not same as the factors of the polynomial.

Option D is not correct as the factors are not same as the factors of the polynomial.

Learn more:

1. Learn more about the polynomial brainly.com/question/12996944

2. Learn more about logarithm model brainly.com/question/13005829

3. Learn more about the product of binomial and trinomial brainly.com/question/1394854

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Polynomials

Keywords: factor, factorization, polynomial, quadratic, cubic, greatest common factor, groups, multiplication, product, identities, common factor, expression, terms, grouping.

Which steps should be followed to write an equivalent ratio to find 2% of 6700? Write 2% as the ratio StartFraction 200 Over 100 EndFraction. Write the equivalent ratio StartFraction question mark Over 6700 EndFraction. (100)(67) = 6700, so (20)(67) = 1340. Write 2% as the ratio StartFraction 20 Over 100 EndFraction. Write the equivalent ratio StartFraction 6700 Over question mark EndFraction. (20)(335) = 6700, so (100)(335) = 33,500. Write 2% as the ratio StartFraction 2 Over 100 EndFraction. Write the equivalent ratio StartFraction question mark Over 6700 EndFraction. (100)(67) = 6700, so (2)(67) = 134. Write 2% as the ratio StartFraction 2 Over 100 EndFraction. Write the equivalent ratio StartFraction question mark Over 6700 EndFraction. (100)(6.7) = 6700, so (20)(6.7) = 13.4

Answers

Answer:

Step-by-step explanation:

To evaluate the expression 2% 0f 6700, we can follow the steps;

2% = 2/100

6700 = 67(100)

2% of 6700 = 2/100 * 67(100)

The 10 at the numerator will cancel out that at the denominator

2/100 * 67(100) = 2(67)

2(67) = 134

Answer:

Write 2% as the ratio 2/100. Write the equivalent ratio_?_ . (100)(67)= 6700, so (2)(67)=134

6700

Step-by-step explanation: Just did it on edg 2020. IF THIS HELPS IT IS C.

If I make 11.50 an hour working full time (40 hours a week) how much money do i make a year after deducting 60 dollars of taxes from my pay check every month? ( Keep in mind, some months have 4 weeks and some have 5 wks and I get paid bi-weekly not semi monthly )

Answers

Given:
hourly rate = 11.50
hours worked in a week = 40 hours
taxes per moth = 60

Every month may be 4 weeks or 5 weeks but we know that 1 year has 52.1429 weeks.

Let us compute for the whole year:

Earnings:
11.50 /1 hour * 40 hours/1week * 52.1429 weeks/1year  
= 11.50 * 40 *  52.1429/year
= 23,985.734 per year

Taxes:
60 / per month * 12 months / 1 year
= 60 * 12/year
= 720 per year

Net earning per year
23,985.734 - 720 = 23,264.734 

Net earning per month
23,264.734 ÷ 12 months = 1,938.81 

You will earn 23,264.73 annually from a monthly earning of 1,938.81

NEED answer soon. just the 4 letters thankss

Answers

Answer:

a = 25m^2

b = 5m

d = 35.73 m^2

c = 7.94m

Step-by-step explanation:

First, remember that the area of a square of side length L is:

A = L^2

And for a triangle rectangle with catheti a and b, and hypotenuse H, we have the relation:

H^2 = a^2 + b^2  (Phytagorean's theorem)

Ok, let's look at the left image, we have a green triangle rectangle.

The bottom cathetus has a length equal to the side length of a square with area of 16m^2

Then the side length of that square (and the cathetus) is:

L^2 = 16m^2

L = √(16m^2) = 4m

The left cathetus has a length equal to the side length of a square of area = 9m^2

Then the side length of that cathetus is:

K^2 = 9m^2

K = √(9m^) = 3m

Then the catheti of the green triangle rectangle are:

4m and 3m

Then the hypotenuse of this triangle (b) is:

b^2 = (4m)^2 + (3m)^2

b^2 = 16m^2 + 9m^2 = 25m^2

b = √(25m^2) = 5m

And b is the side length of the red square, then the area of that square is:

a = b^2 = 25m^2

Now let's go to the other image.

Here we have an hypotenuse of side length H, such that:

H^2 = 144m^2

And we have a cathetus (the one adjacent to the green triangle) of side length L such that:

L^2 = 81m^2

The other cathetus will have a sidelength c, such that:

c^2 = area of the purple square

By the Pythagorean's theorem we have:

144m^2 = 81m^2 + c^2

144m^2 = 81m^2 + c^2

144m^2 - 81m^2 = c^2

63m^2 = c^2

(√63m^2) = c = 7.94m

And the area of a triangle rectangle is equal to the product between the catheti divided by two.

We know that one cathetus is equal to c = 7.94m

And the other on is equal to the square root of 81m^2

√(81m^2) = 9m

then the area of the triangle is:

d = (7.94m)*(9m)/2 = 35.73 m^2