Last month,Shelly earned $15.38 for mowing lawns,$6.25 for cleaning her room, and $12.04 for other chores. How much did she earn last month?

Answers

Answer 1
Answer: she had earned $33.67 in the last month.
$15.38+$6.25+$12.04= 33.67 roughly


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Write the annual salary in the blanks in the following chart. Paycheck  Pay Period    Annual Salary$1,300        monthly               ? $1,000       biweekly              ? $550            weekly               ? $800          semimonthly        ? Write the annual salary in the blanks in the following chart.
What is the distance between (-5,4) and (8,-2)
Six times the sum of a number and eight is 30. Find the number
Write 2/3 and 3/4 as a pair of fractions with a common denominator
The product of 5 and a number is 10

For the values a = 3.4 and b = 2.6, which are legs of a right triangle, find c, the hypotenuse, to the nearest tenth.A. 4.3

B. 2.4

C. 2.2

D. 4.8

Answers

The length of the hypotenuse is 4.3. This is calculated as the square root of 3.4 squared plus 2.6 squared.

Answer:

Using Pythagoras theorem.

In any right angle triangle:

\text{Hypotenuse side}^2 = \text{Sum of the square of side}

As per the statement:

For the values a = 3.4 and b = 2.6, which are legs of a right triangle.

We have to find c, the hypotenuse:

Apply the Pythagoras theorem, we have;

c^2 = a^2+b^2

Substitute the values we have;

c^2=3.4^2+2.6^2 = 11.56+6.76 = 18.32

then;

c=√(18.32) = 4.28018691

Therefore, the value of c, the hypotenuse, to the nearest tenth is, 4.3 units

I need helps please and ty​

Answers

Answer:

y=7x+4

Step-by-step explanation:

Values of x and y satisfy the equation y=7x+4

Use an algebraic equation to solve the problem. The sides of a triangle are in the ratio 3 : 4 : 5. What is the length of each side if the perimeter of the triangle is 90 cm? A. 10.5 cm, 11.5 cm, and 12.5 cm

B. 22.5 cm, 30 cm, and 37.5 cm

C. 7.5 cm, 11.5 cm, and 32.1 cm

D. 19.3 cm, 25.7 cm, and 32.1 cm

Answers

Answer:

The answer is the option B

22.5\ cm, 30\ cm, 37.5\ cm

Step-by-step explanation:

Let

a,b,and c the length sides of the triangle

we know that

a+b+c=90 ------> equation A

(a)/(b)= (3)/(4)

a=(3)/(4)b -----> equation B

(b)/(c)= (4)/(5)

c=(5)/(4)b -----> equation C

Substitute the equation B and equation C in the equation A

(3)/(4)b+b+(5)/(4)b=90

solve for b

3b=90

b=30\ cm

Substitute the value of b in the equation B

a=(3)/(4)(30)=22.5\ cm

Substitute the value of b in the equation C

c=(5)/(4)(30)=37.5\ cm

Ratio units = 3+4+5 = 12

perimeter = 90 (a+b+c)

1 unit value, 90/12 = 7.5

So, lengths will be 3(7.5), 4(7.5), 5(7.5)

OPTION B IS YOUR ANSWER

Helllllp >_< Compare: 1.2057 O 1.1421OA) >
OB) <
OC)
=
OD) none of the above

Answers

The decimal number 1.2057 is greater than the decimal number 1.1421. Then the correct option is A.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The decimal numbers are given below.

1.2057 and 1.1421

Compare the decimal numbers, then we have

1.2057 > 1.1421

The decimal number 1.2057 is greater than the decimal number 1.1421. Then the correct option is A.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ2

Answer:

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative controls

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative control

Step-by-step explanation:

What property is demonstrated in the equation below? 4(5+3)=(5+3)4

Answers

Answer:

Associative commutative property

The box plots show the number of hours of television a group of middle school students and a group of elementary school students watch each week.Which are true statements when comparing the data in the box plots? Select three choices.

The data for elementary school are more consistent than those for middle school.

More of the data for middle school lie closer to the median than the data for elementary school.

About 50% of elementary school students watch between 4 and 7 hours of television each week.

About one-half of middle school students watch less than 2 hours of television each week.

On average, middle school students watch less television than elementary school students each week.

Answers

Answer:

i) The data for elementary school are more consistent than those for

  middle school.

iii) About 50% of elementary school students watch between 4 and 7  

    hours of television each week.

v) On average, middle school students watch less television than

   elementary school students each week.

Step-by-step explanation:

The box plots show the number of hours of television a group of middle school students and a group of elementary school students watch each week.

The true statements when comparing the data in the box plots

i) The data for elementary school are more consistent than those for

  middle school.

ii) More of the data for middle school lie closer to the median than the data

   for elementary school.

iii) About 50% of elementary school students watch between 4 and 7  

    hours of television each week.

iv) About one-half of middle school students watch less than 2 hours of

   television each week.

v) On average, middle school students watch less television than

   elementary school students each week.

Answer:

It's 1, 3, 5 Yw

Step-by-step explanation:

I am doing the test and that's what I got