The sum of all of the solutions for the equation (6x+k)(3x-11)=0 is 1. What is the value of k?

Answers

Answer 1

Answer:

Answer:

-6x

Step-by-step explanation:

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The variables x and y vary inversely. Use the given values to write an equation relating x and y. x=7/2 y=3/5
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Write as a single exponent. 1. ( 1/10 x 1/10 x 1/10 x 1/10 )^2
2. ( 1/10 x 1/10 x 1/10 )^3
3. ( 10 x 10 x 10 )^-2

Answers

Step-by-step explanation:

1. (1/10 × 1/10 × 1/10 × 1/10)^2

(10^-4)^2

10^-8

2. (1/10 × 1/10 × 1/10)^3

(10^-3)^3

10^-6

3. (10 × 10 × 10)^-2

(10^3)^-2

10^-6

Question

Write as a single exponent.

1. ( 1/10 x 1/10 x 1/10 x 1/10 )^2

2. ( 1/10 x 1/10 x 1/10 )^3

3. ( 10 x 10 x 10 )^-2

Please answer this question correctly

Answers

She has 224 ounces, which I claim is the correct answer. How will you know ?

The equation of a circle is (x - 3)2 + (y + 2)2 = 25. The point (8, -2) is on the circle.What is the equation of the line that is tangent to the circle at (8, -2)?

Answers

Answer:

The equation of the line that is tangent to the circle at (8, -2) is:

$x=8$

Step-by-step explanation:

We know that the line which is tangent at a point on a circle is perpendicular to the line joining the center of the circle and that point.

Here we are given the equation of a circle as:

$(x-3)^2+(y+2)^2=25$

The center of the circle is at: (3,-2)

( Since, the standard form of a circle with center at (h,k) and radius r is given by:

$(x-h)^2+(y-k)^2=r^2$ )

Also, the equation of a line joining (3.-2) and (8,-2) is given by:

$y-(-2)=(-2-(-2))/(8-3)* (x-3)\n\ni.e.\n\ny+2=(-2+2)/(5)* (x-3)\n\ni.e.\n\ny+2=(0)/(5)* (x-3)\n\ni.e.\ y+2=0\n\ni.e.\ y=-2$

Also, we know that the slope of this line is zero.

Also, we know that if two lines are perpendicular with slope m and m' respectively then,

$m\cdot m'=-1\n\ni.e.\n\nm'=(-1)/(m)$

Hence, we get that the slope of the tangent line is:

$(-1)/(0)$

Also, we know that:

The equation of a line with given slope m' and a passing through point (a,b) is given by:

$y-b=m'(x-a)$

Here (a,b)=(8,-2)

and $m'=(-1)/(0)$

i.e. the equation of the tangent line is:

$y-(-2)=(-1)/(0)(x-8)\n\ni.e.\n\ny+2* 0=-1(x-8)\n\ni.e.\n\n-1* (x-8)=0\n\ni.e.\n\n(x-8)=0\n\ni.e.\n\nx=8$

Hello,

O=(3,-2) is the center of the circle and 5 its radius.

P=(8,-2)
The line OP is parallele to ox axis so then tangent is parallele to oy axis
Its equation is x=8.

Hi everyone I need to do this assignment for geometry and I have been stuck on it for days, the question is: "On a piece of paper, construct the initials of your first and last name using a compass and straightedge. Only parallel and perpendicular lines may be used in the construction, and both types of constructions must be demonstrated in your finished product. Do not erase arc markings made during the construction process as these help your instructor determine if the lines are constructed properly.", my initials are VG, but i dont even know how to start this, someone please help thank you!If anyone is taking geometry on flvs or already took it, the assignment I'm talking about is 01.04 Module One Quiz. I'm so lost!

Answers

Example in the attachment below.

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function? f(x) = 8x7 – x5 + x3+6

Answers

According to the Fundamental Theorem of Algebra, the number of roots of a polynomial is equal to the degree of the polynomial. The degree of the polynomial is the highest exponent of a term in the polynomial.
Looking at the function, the term with the highest exponent is 8x7. The exponent is 7; therefore, the function has 7 roots.

According to the Fundamental Theorem of Algebra, the roots exist for the polynomial function $f\left( x \right) = 8{x^7} - {x^5} + {x^3} + 6 x$ is $\boxed7.$

Further explanation:

The Fundamental Theorem of Algebra states that the polynomial has n roots if the degree of the polynomial is n.

$f\left( x \right) = a{x^n} + b{x^(n - 1)} +\ldots + cx + d$

The polynomial function has n roots or zeroes.

Degree is highest power of the polynomial function.

Given:

The polynomial function is $f\left( x \right) = 8{x^7} - {x^5} + {x^3} + 6.$

Explanation:

The polynomial function $f\left( x \right) = 8{x^7} - {x^5} + {x^3} + 6$ has seven zeroes as the degree of the polynomial is 7.

According to the Fundamental Theorem of Algebra, the roots exist for the polynomial function $f\left( x \right) = 8{x^7} - {x^5} + {x^3} + 6$ is $\boxed7.$

Learn more:

1. Learn more about inverse of the functionbrainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Polynomials

Keywords: quadratic equation, equation factorization. Factorized form, polynomial, quadratic formula, zeroes, Fundamental Theorem of algebra, polynomial, seven roots.

It takes Tom 1 hour to lay 30 bricks. He has to lay 180 bricks.
Tom starts to lay the bricks at 9 a.m
He has half an hour break at 11 a.m
He has another half an hour break at 1 p.m

What time should Tom finish laying the 180 bricks?

Answers

he should finish laying the bricks at 3:00pm

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