A LAN Uses category 6 cabling. An issue with the connection results in network link to get degeneration and Only one device can communicate at a time. What is the connection operating at?Half duplex
Simplex
Partial
Full Duplex

Answers

Answer 1
Answer:

Answer:

partial

Explanation:


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Write a program segment that simulates flipping a coin 25 times by generating and displaying 25 random integers, each of which is either 1 or 2
What suggestions do you have for preventing scope creep in projects?
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Poor quality lateral communication will result in which ofthefollowing?a. Lack of directionb. Lack of coordinationc. Lack of delegationd. Lack of control
This problem will be discussed in Lab6. In Lab6, the TAs will also discuss about the solution of Function Problem 1 that required you to write several functions. Additionally, the last week's lab problems on loop will be discussed too, if you need more help on them. See the deadline. You should try your best to complete it within the lab time. First n prime numbers: Write a program that takes a positive integer n as input and prints all the prime numbers from 1 to n.

An attacker is intent on disturbing the communication by inserting bogus packets into the communications. A. Discuss whether such an attack would succeed in systems protected by IPsec.
B. Discuss whether such an attack would succeed in systems protected by SSL.

Answers

Answer:

A. No, it would not succeed.

B. Yes, the attack will succeed.

Explanation:

In the seven-layer OSI model of computer networking, packet strictly refers to a protocol data unit at layer 3, the network layer. So if an attacker wants to insert bogus/ fake packets this will happen at the network layer.

A. IPSec works on network layer (the IP layer) of the OSI model protecting and authenticating IP packets. It provides data integrity, authentication and confidentiality between participating peers at the IP layer.

Thus, inserting bogus packets into the communications by an attacker will not have any affect on security of a system which has IPSec security and therefore it will not succeed.

B. SSL/TLS is an application layer protocol that fits into layer 5 to 7 of the OSI model. However, an attack by inserting bogus packets into the communications will succeed as SSL only provides protection for layer 5 to 7 and not the network layer.

Write out the base sequence that is added directly after the primer. In order for Moodle to correctly grade this question, write only the letters representing the bases, write your answer in 5' to 3' direction, and do not have any spaces between the letters and do not label the 5' and 3' ends.

Answers

Answer:

see explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

Which exercise can help you prevent Carpel Tunnel Syndrome?make a fist, hold, and stretch your fingers

bend slightly and stretch your right hand up

move your head back and forward slowly

blink your eyes often

Answers

Make a Fist, hold, and stretch your fingers is the correct answer
A. make a fist, hold, and stretch your fingers

C And D are rather absurd as Carpal Tunnel Syndrome is 
caused by a pinched nerve in the wrist.

Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by " seconds". End with a newline.

Answers

Answer:

The program to this question as follows:

Program:

#include <iostream> //defining header file

using namespace std;

void PrintPopcornTime(int bagOunces) //defining method PrintPopcornTime that accepts bagOunces

{

//defining conditional statement

if (bagOunces < 3) //if block checks bagOunces less then 3  

{

cout << "Too small"<<endl;

}

else if (bagOunces > 10)

{

cout << "Too large"<<endl; //else if value greater than 10

}

else //else block

{

cout << (bagOunces*6) <<" seconds"<<endl; //calculate seconds

}

}

int main()  

{

int bagOunces; //defining integer variable bagOunces

cout<<"Enter number: "; //message

cin>>bagOunces; //input value by user

PrintPopcornTime(bagOunces); //calling the method

return 0;

}

Output:

Enter number: 3

18 seconds

Explanation:

In the above C++ language code, the first header file is defined, then the method "PrintPopcornTime" is defined, in this method, an integer variable "bagOunces" is passed as a parameter, inside the method a conditional statement is used that can be described as follows:

  • In the if block, it will check that the "bagOunces" variable value is less than 3, if it is true, it will print "Too small". otherwise, it will go else if block.
  • In else if the "bagOunces" variable value is greater then 10, if it is true, it will print "Too large", otherwise it will go else block.
  • In the else block it will calculate the total second and prints its value in new line.

In the next step, the main method is defined, inside this method, an integer variable "bagOunces" is defined, which is used for user input and inside this method, the PrintPopcornTime is called.

The completed function "PrintPopcornTime()" can be referred to as given below.

We have,

The completed function "PrintPopcornTime()" as requested:

void PrintPopcornTime(int bagOunces) {

   if (bagOunces < 2) {

       System.out.println("Too small");

   } else if (bagOunces > 10) {

       System.out.println("Too large");

   } else {

       int time = 6 * bagOunces;

       System.out.println(time + " seconds");

   }

   System.out.println();

}

In this function, we check the value of "bagOunces" using conditionalstatements.

If it's less than 2, we print "Too small".

If it's greater than 10, we print "Too large".

Otherwise, we calculate the time by multiplying 6 with "bagOunces" and print it followed by " seconds".

Finally, we print a new line to end the output.

Thus,

The completed function "PrintPopcornTime()" can be referred to as given above.

Learn more about programming of functions here:

brainly.com/question/14684896

#SPJ6

#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The function will look for the search string within the #target string. # #The function should return a string representing where in #the target string the search string was found: # # - If search string is at the very beginning of target # string, then return "Beginning". For example: # string_finder("Georgia Tech", "Georgia") -> "Beginning" # # - If search string is at the very end of target string, # then return "End". For example: # string_finder("Georgia Tech", "Tech") -> "End" # # - If search string is in target string but not at the # very beginning or very end, then return "Middle. For # example: # string_finder("Georgia Tech", "gia") -> "Middle" # # - If search string is not in target string at all, then # return "Not found". For example: # string_finder("Georgia Tech", "Idaho") -> "Not found" # #Assume that we're only interested in the first instance #of the search string if it appears multiple times in the #target string, and that search string is definitely #shorter than target string. # #Hint: Don't be surprised if you find that the "End" case #is the toughest! You'll need to look at the lengths of #both the target string and the search string. #Write your function here!

Answers

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

       return "not found"

#you can add an elif condition instead of else for not found condition as:

#elif position==-1    

#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

print(string_finder("Georgia Tech", "Idaho"))

Explanation:

The program can also be written in by using string methods.

def string_finder(target,search):  #method definition that takes target string and string to be searched

       if target.startswith(search):  #startswith() method scans the target string and checks if the (substring) search is present at the start of target string

           return "Beginning"  #if above condition it true return Beginning

       elif target.endswith(search):  #endswith() method scans the target string and checks if the (substring) search is present at the end of target string

           return "End"#if above elif condition it true return End

       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

           return "Middle"  #if above elif condition it true return End

       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

Which statement must be included in a program in order touse a deque container?a. #include vector

b. #include

c. #include container

d. #include deque

Answers

Answer:

d.#include deque

Explanation:

We have to include deque library in order to use a deque container and the syntax to include is #include<deque>.Deque is a double ended queue which is a sequence container and allows operations of contraction and expansion on both ends of the queue.Double ended queues are a special case of simple queue since in simple queue the insertion is from rear end and deletion is from front end but in deque insertion and deletion is possible at both ends rear and front.

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