A puppy is running with a speed of 11.2 m/s towards it owner when itgets distracted by a squirrel and stops running. If it halted its run in 2 s,
what is the puppy's acceleration?
Answers
Answer:
-5.6m/s²
Explanation:
Given parameters:
Initial speed = 11.2m/s
Time of running = 2s
Unknown:
Acceleration of the puppy = ?
Solution:
Acceleration is the rate of change of velocity with time.
So;
Acceleration =
final speed = 0m/s
Acceleration = = -5.6m/s²
Final answer:
The puppy's acceleration is -5.6 m/s².
Explanation:
Acceleration is a measure of how quickly an object changes its speed. The formula for acceleration is a = Δv / Δt, where Δv is the change in velocity and Δt is the change in time. To find the puppy's acceleration, we can use the formula for acceleration:
acceleration = (final velocity - initial velocity) / time.
In this case, the initial velocity is 11.2 m/s and the final velocity is 0 m/s (since the puppy stops running). The time taken to stop is 2 s.
Substituting the values into the formula, we get:
acceleration = (0 m/s - 11.2 m/s) / 2 s.
Simplifying the equation gives us the acceleration of the puppy, which is -5.6 m/s².
Learn more about acceleration here:
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