My elderly relatives liked to tease me at weddings saying “ you’ll be next!” They soon stopped, once I started doing the same at funerals

Answers

Answer 1
Answer:

LOLLOLOLOOLOLASDLODSALLOASDLOASD


Related Questions

80 plus what equals 44??
In country​ A, about five times as many cars are manufactured per day than in country B. If the total number of these cars manufactured per day is 39,612​, find the number manufactured in country B and the number manufactured in country A.
A welding drawing shows that the​ weld-root reinforcement cannot exceed ​" in thickness. Your weld measurement tools are​ metric, so this value needs to be converted to millimeters. You know that one inch equals 2.54 centimeters. What is the maximum​ weld-root reinforcement allowed in​ millimeters? Round your answer to the nearest tenth of a millimeter.
Twenty percent of the town's population is over the age of 65. If there are 320 residents over the age of 65, what is the town's total population?
The sum of three consecutive odd integers is -381

Kelly flies a distance of 2,100 miles. the trip takes 4 2/3 hourswhat is the airplanes unit rate of speed in miles per hour?

at this rate of speed, how many miles the airplane travel in 1 1/2 hours?

Answers

Answer: A=450

Step-by-step explanation:

What is the solution of the equation (x - 5)2 +3(x-5)+9 = 0? Use u substitution and the quadratic formula to solve.​

Answers

Answer:

x= (7+3i√(3) )/(2) and (7-3i√(3) )/(2)

Step-by-step explanation:

(x - 5)^(2) +3(x-5)+9

(x - 5)^(2)= x2−10x+25

3(x-5)= 3x-15

x^2-10x+25+3x-15+9

x^2-7x+19=0

a=1 b=-7 c=19

use quadratic formula

\frac{-b+\sqrt{b^(2) -4ac} }{2a}

\frac{-(-7)+\sqrt{-7^(2)-4(1)(19) } }{2}

\frac{7+\sqrt{49{}-4(19) } }{2}

\frac{7+\sqrt{49{}-76 } }{2}

\frac{7+\sqrt{-27{} } }{2}

√(-27) =3i√(3)

(7+3i√(3) )/(2)

(2 + 3i) + (4 - 6i) equal?

Answers

Answer:

Yes indeed, at least I'm pretty sure.

Step-by-step explanation:

4 is half of 2, and 3 is half of 6. you could write them as equal, just like 1/2 and 2/4 fractions.

Answer:

6-3i

Step-by-step explanation:

First, you need to get rid of perenthesis. Use destributuve property to do so.

Then, add the add the same types of integers(whole numbers and numbers with variables)

after that, you get your answer!

A principle of $4570 is placed into account that earns 4.5 interest if the interest is compounded annually how much money will be in the account

Answers

Answer:

205.65 interest

Step-by-step explanation:

Answer:

Option D on Edg.

Step-by-step explanation: I took the test and the correct option is $5695.05.

On the first day of the fiscal year, a company issues $65,000, 6%, five-year installmentnotes that have annual payments of $15,431. The first note payment consists of $3,900 of
interest and $11,531 of principal repayment.
a. Journalize the entry to record the issuance of the installment notes.
b. Journalize the first annual note payment.

Answers

Answer:

Dr  cash      $65,000

Cr Notes payable              $65,000

repayment:

Dr Notes payable      $11,531

Dr interest expense  $3,900

Cr Cash                                        $15,431

Step-by-step explanation:

Upon the issuance of the notes,the cash received would be debited to cash account and the same amount credited to notes payable account.

The payment of $15,431 as annual repayment on the notes payable would be credited to cash account as an outflow of cash from the business while the notes payable and interest expense accounts would be debited with $11,531 and$3,900 respectively

Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2

Answers

y'-\frac13y=\frac13xe^x\ln x\,y^(-2)

Divide both sides by \frac13y^(-2)(x):

3y^2y'-y^3=xe^x\ln x

Substitute v(x)=y(x)^3, so that v'(x)=3y(x)^2y'(x).

v'-v=xe^x\ln x

Multiply both sides by e^(-x):

e^(-x)v'-e^(-x)v=x\ln x

The left side can be condensed into the derivative of a product.

(e^(-x)v)'=x\ln x

Integrate both sides to get

e^(-x)v=\frac12x^2\ln x-\frac14x^2+C

Solve for v(x):

v=\frac12x^2e^x\ln x-\frac14x^2e^x+Ce^x

Solve for y(x):

y^3=\frac12x^2e^x\ln x-\frac14x^2e^x+Ce^x

\implies\boxed{y(x)=\sqrt[3]{\frac14x^2e^x(2\ln x-1)+Ce^x}}