If 65 + a = 71, then a =
If a= 9 then 5a =

Answers

Answer 1
Answer:

Answer:

a = 6   5a=45

Step-by-step explanation:

part 1) 65 + a =71

           a = 71 -65

           a = 6

part 2) if a = 9 then 5a = 5x9 = 45

           


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Find the GCF. 20, 45x

Answers

Here what you can do is list the factors for both terms:
20: 2, 2, 5
45x: 3, 3, 5, x

The only factor that both terms share is 5, so 5 is your GCF.
Yes the GCF of 20 and 45x is 5. Due to the fact that 20: 1 & 20, 2 & 10, 4 & 5 and 45: 1 & 45, 3 & 15, 5 & 9 also only one of them has the variable x so it is not common.

Of the following numbers ,which one is prime,32,42,29,15!

Answers

only 29,
32,42,15 have more than 2 factors. 
Of the following numbers, which one is prime: 32, 42, 29, 15?A. 29

Use the substitution method to solve the system of equations. Choose the correct ordered pair.x + y = 5 y = 7

Answers

First we put 7 in the place of y, after that subtract 7 from both sides, the answer is -2.
x + y= 5      y = 7
x+ 7=5
x= 5-7
x = -2

Please someone help me out, please don't put the incorrect answerWhat is the distance between the points (-1, 2) and (2, 6)?​

Answers

Answer:

5

Step-by-step explanation:

Distance Equation Solution:

d=√((2-(-1)^2+(6-2)^2)\nd=√((3)^2+(4)^2)  \nd= √(9+6)\nd= √(25)\nd=5

A worker is hired for $80 a day on the condition that if business is slow, the worker will only receive half pay.  At the end of 20 days, the worker receives $1,320.  On how many days was business slow?

Answers

7 slow days

You know the worker worked a total of 20 days, some at $80 per day, and some at $40 per day.  After the 20 days, the worker was paid $1320.

x = days paid full time ($80)
y = days paid half time ($40)

you have two unknowns, so you'll need two equations to solve, from the problem statement, we can derive the following relationships:

($80)x + ($40)y = $1320
x + y = 20 days

x = 20 - y
80(20 - y) + 40y = 1320
1600 - 80y + 40y = 1320
1600 - 40y = 1320
1600 - 1320 = 40y
280 = 40y
y = 280/40 = 7

thus 7 days paid half time (i.e. slow days)

verify your solution is correct
y = 7
x = 20 - 7 = 13
80(13) + 40(7) = 1320 [OK]



a random sample of 130 students is chosen from a population of 4,500 students. if the mean iq in the sample is 120 with a standard deviation of 5, what is the 99% confidence interval for the students' mean iq score? answers given below: 118.87−121.13 107.12−132.88 125−135 115−125

Answers

Answer with explanation:

Total Sample Size = 4,500 Students

Sample Chosen(n) = 130 students

Mean IQ of the Sample,\bar{X} = 120

Standard Deviation, \sigma=5

To Calculate 99% confidence interval for the students' mean IQ score, we will calculate,

Z_(99 percent)=2.58

Formula for Confidence Interval

=\bar{X} \pm Z_(99 percent)* (\sigma)/(√(n))\n\n=120 \pm 2.58 * (5)/(√(130))\n\n=120 \pm (12.9)/(11.401)\n\n =120 \pm 1.1314\n\n=120 \pm 1.13

The Value of Confidence interval will lie between

⇒  120 - 1.13 to 120 +1.13

⇒118.87 to 121.13

Option A:  118.87−121.13

C.I.=120 \pm z_( \alpha /2) ( \sigma )/( √(n) ) \n =120 \pm 2.58 * (5)/( √(130) ) \n =120 \pm 1.13 \n =118.87 - 121.13