A mine produces ore that is about 0.6% nickel. About how much ore from this mine would you need to get 3,000 kg of nickel?

Answers

Answer 1

Answer: The correct answer is 5000

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Solve 2cos x+2cos 2x=0 on the interval [0,2pi)

Answers

$2cosx+2cos2x=0 \n -2sin^2x+2cos^2x+2cosx=0 \n -2(1-cos^2x)+2cos^2x+2cosx=0 \n -2+2cos^2x+2cos^2x+2cosx=0 \n 4cos^2x+2cosx-2=0 \n t=cos x \n 4t^2+2t-2=0 \n \Delta=4+32=36 \n t_1= (-2-6)/(8)=-1 \n t_2= (-2+6)/(8)= (1)/(2) \n cos x=-1 \lor cos x= (1)/(2) \n x=-\pi \lor x= (5\pi)/(3)$

Given: LK congruent NM,Kj congruent Mj Prove: LT congruent NJ

PLS PLS PLS HELP IM FAILING GEOMETRY RNNNNN

Answers

By the Definition of congruent property, we have proved that:

VW ≅ VX

Congruent Property:

The three properties of congruence are the reflexive property of congruence, the symmetric property of congruence and the transitive property of congruence. These properties can be applied to line segments, angles, triangles, or any other shape.

Given: VZ ≅ VY and WY ≅ XZ

Prove: VW ≅ VX

Proof:

(Given): VZ ≅ VY and WY ≅ XZ

By the Definition of Congruent Substitute:

VZ = VY and WY = XZ

⇒ VZ = VX + XZ , and,

VY = VW + WY

By Substituting

VX + XZ = VW + WY

Again,

VX + WY = VW + WY

Now,

By Subtraction property of Equality

VX = VW

VW = VX (Definition of congruent property.)

Complete Question:

IF VZ congruent of VY and WY congruent of XZ. Prove that VW is Congruent of VX.

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Compare the mean and standard deviation of Set A and Set B.Set A: 7, 3, 4, 9, 2
Set B: 5, 8, 7, 6, 4

Answers

Set A: {7, 3, 4, 9, 2}
Finding the Mean of Set A: $\bar{x} = (7 + 3 + 4 + 9 + 2)/(5)$
   $\bar{x} = (25)/(5)$
   $\bar{x} = 5$

Finding the Standard of Set A: $\sigma = \sqrt{\frac{(\bar{x} - x_(1))^(2) + (\bar{x} - x_(2))^(2) + (\bar{x} - x_(3))^(2) + (\bar{x} - x_(4))^(2) + (\bar{x} - x_(5))^(2)}{n}}$
   $\sigma = \sqrt{((5 - 7)^(2) + (5 - 3)^(2) + (5 - 4)^(2) + (5 - 9)^(2) + (5 - 2)^(2))/(5)}$
   $\sigma = \sqrt{((-2)^(2) + (2)^(2) + (1)^(2) + (-4)^(2) + (3)^(2))/(5)}$
   $\sigma = \sqrt{(4 + 4 + 1 + 16 + 9)/(5)}$
   $\sigma = \sqrt{(34)/(5)}$
   $\sigma = √(6.8)$
   $\sigma \approx 2.6$

Finding the Mean of Set B: $\bar{x} = (5 + 8 + 7 + 6 + 4)/(5)$
   $\bar{x} = (30)/(5)$
   $\bar{x} = 6$

Finding the Standard Deviation of Set B: $\sigma = \sqrt{\frac{(\bar{x} - x_(1))^(2) + (bar{x} - x_(2))^(2) + (\bar{x} - x_(3))^(2) + (\bar{x} - x_(4))^(2) + (\bar{x} - x_(5))}{n}}$
$\sigma = \sqrt{((6 - 5)^(2) + (6 - 8)^(2) + (6 - 7)^(2) + (6 - 6)^(2) + (6 - 4)^(2))/(5)}$
$\sigma = \sqrt{((1)^(2) + (-2)^(2) + (-1)^(2) + (0)^(2) + (2)^(2))/(5)}$
$\sigma = \sqrt{(1 + 4 + 1 + 0 + 4)/(5)}$
$\sigma = \sqrt{(10)/(2)}$
$\sigma = √(5)$
$\sigma \approx 2.236$

The mean and standard deviation of Sets A and B are different.

Final answer:

Mean of Set A is 5 and Set B is 6. Standard deviation of Set A is approximately 2.83, and for Set B, it's approximately 1.67. This indicates that values in Set B are generally closer to their mean than values in Set A to their mean.

Explanation:

To compare the mean and standard deviation of Set A and Set B, we first need to calculate these for each set. Mean is the average of the numbers and standard deviation is a measure of the amount of variation or dispersion of a set of values.

First, calculate the mean by adding the numbers in each set and dividing by the total number of values. For Set A, the mean is (7+3+4+9+2)/5 = 5. For Set B, the mean is (5+8+7+6+4)/5 = 6.

The standard deviation is a bit more complex, as it involves subtracting the mean from each value, squaring the result, finding the mean of these squares, and then taking the square root of that mean. For Set A, these steps result in a standard deviation of approximately 2.83. For Set B, these steps result in a standard deviation of approximately 1.67.

In conclusion, Set B has a higher mean and a lower standard deviation compared to Set A which means values in Set B are generally closer to the mean of Set B than values in Set A are to the mean of Set A.

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Find the area of a triangle with base b = 24 ft and height h = 17 ft.

Answers

Answer:

204ft^2

Step-by-step explanation:

24*17/2=204

Kitchen chairs are purchased wholesale for $36 by a discount furniture store. Then, the store marks up the chairs by 60 percent. The store has a special sale where all items are marked down by 20 percent. How much would two chairs cost during the sale?

Answers

As a result of the sale, two chairs can be purchased at the discounted price of $92.16.

After the store bought the chairs for $36, they gave it a markup of 60%. The new price is:

= Cost of chair + Markup

= 36 + (60% x 36)

= $57.60

They then reduced this price by 20%:

= Marked up price - Discount

= 57.60 - (20% x 57.60)

= $46.08

Two chairs are to be bought:

= 46.08 x 2

= $92.16

In conclusion, two chairs would cost $92.16

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starts at 36....marks up by 60%
36 + 0.60(36) = 36 + 21.60 = 57.60
now they mark it down by 20%
57.60 - 0.20(57.60) = 57.60 - 11.52 = 46.08

46.08 * 2 = 92.16

What is the value of the expression (3a-b)/(6(b+a)) when a = 4 and b = -2?