MATHEMATICS COLLEGE

HALP AND YOU GET CANDY THE PICTURE BELOW IS YOUR KEY TO CANDY (BRAINLIST)

Answers

Answer 1

Answer:

Answer:

3 1/8

Step-by-step explanation:

Wheres my candy!!

Answer 2

Answer:

Answer:

3 1/8

Step-by-step explanation:

10 - 6 7/8 = 3 + 1/8

Related Questions

Boatesville is a 65 3/5 -kilometer drive from stanton. A bus traveling from stanton to boatesville is 24 1/3 kilometers from boatesville. How far has the bus traveled
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Rewrite with positive exponents a^-3 b^-5
Find the quotient of 2/5 and 4/5Give your answer as a fraction in its simplest form.

4. A recipe says that 2 3/5 cups of flour are needed to make 1 batch of biscuits. How many cups of flour are needed to make 2 batches of biscuits? O 43/5 O 51/5 O 26/10 O 6

Answers

the answer is the second option, 5 1/5

What is the value of the expression |5x+12| when x=5

Answers

Answer:

|5x+12| when x=5

I5*5=12I

I37I

Step-by-step explanation:

Answer:

Step-by-step explanation:

X=5

5x=(5×5)=25

25+12=37

A cat has 24 whiskers by its nose. A manatee has 25 times as many whiskers.

How many whiskers does a manatee have?

Answers

Answer:

600 whiskers

Step-by-step explanation:

If you multiply 24 by 25 you get 600

4x (7+8) = (4x _) + (4x _)

Answers

Answer:

4x (7+8)=(4x3) + (4x4)

4x(7+8)=(4x7) +(4x8)

Step-by-step explanation:

Im not sure with one tho

6910
Geometric Proof #1
4x = -24
Names: statements & Reasons Bank:
C
B
x + 18
3x + 25
Division P.O.E
4x + 43 = 19
Given: AC = 19
Prove: x = -6
gure not to sale
4x = 62
Statements
Reasons
Given
Segment Addition
Postulate
AC = 19
AB = x + 18
Definition of Midpoint
Definition of Congruent
Segments
Given
BC = 3x + 25
Given
Addition P.O.E.
x + 18 + 3x + 25 = 19
AB + BC = AC
AB = BC
Substitution
Combine Like Terms
Subtraction P.O.E.
x = -6
Click to add speaker notes

Answers

Answer:

174

Step-by-step explanation:

If the discriminant of a quadratic equation is 4, which statement describes the roots?

Answers

Answer:

Step-by-step explanation:

I. If discriminant >0 then the quadratic equation has the roots x1 and x2 and

a) x1 and x2 are real numbers

b) x1≠x2

II. If discriminant =0 , then x1=x2 and is a real number

III. If discriminant < 0 the equation has complex roots , x1=a+bi ,

x2=a-bi , where i=V-1

Answer: B. There are 2 real roots.

Step-by-step explanation:

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