A tree 5 ft tall grows an average of 8 in. each year. Which equation models the tree’s height h after x years?
Answers
Answer: h=8x+5
hope this helps vote me brainliest
h = Tree's height in inches
x = years of growth
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Answers
Enter the x-intercepts of the quadratic function in the boxes.
Answers
Answer:
The x-intercepts of the quadratic function are 8 and -4.
Step-by-step explanation:
The given function is
Equate the function f(x) equal to 0, to find the x-intercepts of the quadratic function.
The middle term can be written as -8x+4x.
Take out the common factors.
Using zero product property,
Therefore the x-intercepts of the quadratic function are 8 and -4.
well the intercepts are (8,0) and (-4,0) its a lot of math so you need to find it i would show you but i have a quiz
im not sure tho soo
A. y = 7/4x + 7
B. y = - 7x - 28
C. y = - 7/4x - 7
D. y = 7x + 28
Answers
Answer:
A. y = 7/4x + 7
Step-by-step explanation:
y = mx +c
4y -7x = 8
(make y the subject of formulae)
4y = 8 + 7x
divide through by the coefficient of y (4)
y = 2 + 7/4x
7/4 = m1
since the line is parallel m1 = m2
let see :{y -y¹}÷ {x-x1} = 7/4
x¹= -4 , y¹ = 0
{y - 0} ÷ {x- (-4) } = 7/4
cross multiply
4(y - 0) = 7(x+4)
4y - 0 = 7x + 28
4y = 7x +28 +0
4y = 7x + 28
(divide both sides by the coefficient of y)
y = 7/4x +28/4
y = 7/4x + 7
What is the value of x?
Answers
To find the value of x, we need to take the inverse sin (also known as arcsin) of 0.5:
x = arcsin(0.5)
Using a calculator, we find that x is approximately 30 degrees (or π/6 radians).
Answers
The co-ordinate points of B is (3,1)
What is midpoint in a line ?
A midpoint in a given line segment divides the line segment in two equal parts.
In the given question
AB is a line segment.
Point A has co-ordinates (-1,5) and midpoint M has co-ordinates (1,3).
Assuming point B has co-ordinates (x,y)
We know midpoint formula is give by
M of x = (x₁ + x₂)/2 and M of y = (y₁ + y₂)/2
∴ 1 = (-1 + x₂)/2
2 = - 1 +x₂
x₂ = 3
And
3 = ( 5 + y₂)/2
6 = 5 + y₂
y₂ = 1
So the co-ordinate points of B(x₂,y₂) = (3,1)
Learn more about midpoints here :
#SPJ2
Answer:
(3,1)
Step-by-step explanation:
let B be (x,y)
m(1,3)=midpoint
A(-1,5)=(x1,y1)
B(x,y)=(x2,y2)
(1,3)= x1+x2/2 y1+y2/2
(1,3)= -1+x/2 5+y/2
so,
-1+x/2=1 5+y/2=3
-1+x=2 5+y=6
x=3 y=1
therefore the co ordinates of B(x,y) are (3,1)