A water lily is floating in a murky pond rooted on the bottom of the pond by a stem of unknown length. The lily can be lifted 2 feet over the water and moved 6 feet to the side. What is the depth of the pond?

Answers

Answer 1
Answer:

The depth of the pond is 8 feet and this can be determined by using the Pythagorean theorem.

Given :

  • A water lily is floating in a murky pond rooted on the bottom of the pond by a stem of unknown length.
  • The lily can be lifted 2 feet over the water and moved 6 feet to the side.

The Pythagorean theorem can be used to determine the depth of the pound. The Pythagorean theorem according to the attached diagram is given by:

\rm (BD)^2 = (BC)^2+(CD)^2

Now, put the value of the given lengths according to the attached diagram in the above equation.

(x+2)^2= 6^2+x^2

x^2+4+4x = 36+x^2

4x = 32

x = 8

Therefore, the depth of the pond is 8 feet.

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Answer 2
Answer: 12 Feet is the depth of the pond.  I am just guessing but i think that is it.

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Approximate the logarithm using the properties of logarithms, given logb 2 ≈ 0.3562,

logb 3 ≈ 0.5646,
and
logb 5 ≈ 0.8271.
(Round your answer to four decimal places.)
㏒b(2b^3)

Answers

Final answer:

By using the properties of logarithms, namely ㏒b(a * c) = ㏒b(a) + ㏒b(c) and ㏒b(a^p) = p * ㏒b(a), we find the  approximation of the logarithm ㏒b(2b^3) to be 3.3562.

Explanation:

To approximate the value of ㏒b(2b^3), we can use the properties of logarithms. The first one is that ㏒b(a * c) = ㏒b(a) + ㏒b(c), where a and c are the numbers we wish to find the logarithm of. We can apply this property to your given expression as follows:

  • ㏒b(2b^3) = ㏒b(2) + ㏒b(b^3).

The second logarithmic property we need is that ㏒b(a^p) = p * ㏒b(a), where a is the base, and p is the exponent. We can apply this property to the second term on the right side:

  • ㏒b(b^3) = 3 * ㏒b(b).
  • Since ㏒b(b) is equal to 1 (because b raised to the power of 1 is b), then our equation becomes:
  • ㏒b(2b^3) = ㏒b(2) + 3.

Now, we can substitute the values given for ㏒b(2), which is 0.3562:

  • ㏒b(2b^3) = 0.3562 + 3 = 3.3562.

So, approximating ㏒b(2b^3) to four decimal places, we get 3.3562.

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que representa Laos hombres con relacion al total

Help with this math question please thanks

Answers

For this case, what we should do is use the given equation.
 A = P (1 + r) ^ t
 Substituting values we have:
 3900 = 1100 * (1 + 0.04) ^ t
 Clearing t we have:
 (1.04) ^ t = (3900) / (1100)
 log1.04 ((1.04) ^ t) = log1.04 ((3900) / (1100))
 t = log1.04 ((3900) / (1100))
 t = 32.3 years
 Answer:
 
the time will be:
 
t = 32.3 years

Malik is buying a guinea pig. The guinea pig comes with a cage and food bowls for $ 125.00 . The expenses for feeding and caring for the guinea pig are $ 18.00 each month. How much will it cost Malik to buy and care for the guinea pig for one year?

Answers

Answer:

$341.00

Step-by-step explanation:

"$ 18.00 each month."

$18.00*$12.00=$216.00

$216.00+$125.00=$341.00

hope this helpes

be sure to give brainliest

Need help asap

6. Which line has a slope equal to 1?

HELP ON 7 two

Answers

Answer:

6 is the third one 7 is D

Step-by-step explanation:

hope this helps

if its wrong my bad

The daily demand for ice cream cones at a price of $1.20 per cone is 50 cones. At a price of $2.20 per cone, the demand is 30 cones. Use linear interpolation to estimate the demand at a price of $1.50 per cone.

Answers

The estimated demand for ice cream cones at a price of $1.50 per cone is 44 cones using linear interpolation.

Linear interpolation can be used to estimate the demand at a price of $1.50 per cone based on the given data points.

Let, the price as "P" (in dollars) and the demand as "D" (in cones).

Given data points:

Price = $1.20, Demand = 50 cones

Price = $2.20, Demand = 30 cones

We want to estimate the demand at Price = $1.50.

First, calculate the demand change between the two price points:

Demand change = Demand at $2.20 - Demand at $1.20

Demand change = 30 - 50 = -20 cones

Now, calculate the price difference between the target price ($1.50) and the lower price ($1.20):

Price difference = Target Price - Lower Price

Price difference = 1.50 - 1.20 = 0.30

Next, calculate the proportional change in demand due to the price difference:

Proportional change = (Price difference / Price change) * Demand change

Proportional change = (0.30 / 1.00) * (-20) = -6 cones

Finally, estimate the demand at the target price:

Demand at target price = Demand at lower price + Proportional change

Demand at target price = 50 - 6 = 44 cones

Therefore, the estimated demand for ice cream cones at a price of $1.50 per cone is 44 cones using linear interpolation.

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Final answer:

Using linear interpolation, the estimated demand for ice cream cones at a price of $1.50 per cone is 44 cones.

Explanation:

To estimate the demand at a price of $1.50 per cone using linear interpolation:

  1. Calculate the slope or rate of change of the demand by using the formula: slope = (change in demand) / (change in price).
  2. Using the given data, calculate the slope as (30-50) / ($2.20-$1.20) = -20 / $1.00 = -20.
  3. Then, use the slope and one of the given points to find the equation of the linear demand function. Let's use the point (50, $1.20).
  4. The linear demand function is given by: demand = slope * (price - given price) + given demand.
  5. Substituting the values, we have demand = -20 * (price - $1.20) + 50.
  6. Finally, substitute the given price of $1.50 into the demand function: demand = -20 * ($1.50 - $1.20) + 50 = -20 * $0.30 + 50 = 44 cones.

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TEST QUESTION: Jane is making bows for the holidays. One bow requires 23 yard of ribbon. Jane has 13 yards of ribbon. What is the GREATEST number of projects Jane can complete with this ribbon? ​

Answers

Answer:

this makes no sense she can make any bows