What is the domain of the function y=10-5x

Answers

Answer 1

Answer: Any real number (-inf, inf)

Answer 2

Answer: Domain of definition of a function is the set of numbers which the variable attains and for which the function is defined.

f(x) = sqrt (5x-10)

here x can have value equal to any real number >=2 because if x attains value less that 2, 5x-10 becomes negative and sqrt(5x-10) has no real value.

therefore the domain of the function f(x) is (2, infinity) inclusive of 2.

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What is the Gcf of 32 and 72

Answers

The GCF is 8 it divides both values without a remainder

Find the next two numbers in the pattern. 5, −20, 80, −320, ...

Answers

Answer:

1280, -5120

Step-by-step explanation:

it gets multiplied by -4 every time

PLEASE ITS DUE TONIGHT!!!! Sally rides her bike to run errands. It takes her 18 minutes at 10 mph to get to her first stop. She spends 20 minutes riding at 12 mph to get to her second stop. It then takes her 15 minutes riding at 15 mph to get home. a. Draw a speed vs. time graph for the time that Sally spent riding her bike. b. How far did she travel?

Answers

Answer:

The equation that relates distance, rate, and time is

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Step-by-step explanation:

Identify the conic section of xy=4

Answers

This is a hyperbola check wiki for some guidance or plot it with wolfram alpha.

The voltage V required for a circuit is given by $v=√(PR)$ , where P is the power in watts and R is the resistance in ohms.How many more volts are needed to light a 100-watt light bulb than a 75-watt light bulb if the resistance of both is 110 ohms? Round answer to the nearest tenth.

Answers

Answer:

✓11000-✓8250=~ 14 volts

Step-by-step explanation:

the answer is the difference by 100-watt light bulb to a 75 light bulb.

so, all you have to do is this:

v1-v2--------> ✓PR-✓P2R2

so you'll have ✓100.110-✓75.110= ✓11000-✓8250= 14

I hope it helps

Final answer:

By using the formula v=√PR, it is calculated that approximately 13.8 more volts are needed to light a 100-watt bulb than a 75-watt bulb, both having a resistance of 110 ohms.

Explanation:

To find out how many more volts are needed to light a 100-watt light bulb than a 75-watt light bulb, the amount of voltage required for each bulb is to be calculated using the given formula v= √PR, and then subtracted to find the difference.

For voltage required to light a 100-watt bulb:

v100= √(100W * 110 ohms) = 105.4 volts

For 75-watt bulb:

v75 = √(75W * 110 ohms) = 91.6 volts

The difference in voltage:

v100 - v75 = 105.4V - 91.6V = 13.8V

So, approximately 13.8 more volts are needed to light a 100-watt bulb than a 75-watt bulb, when rounded to the nearest tenth.