If four times a certain number, increased by 6 is equal to 94, what is the number?If x represents the number, then which of the following equations could be used to solve the problem?

4x + 6 = 94
4(x + 6) = 94
x + 6 = 4(94)

Answers

Answer 1

Answer: "4x + 6 = 94" is the equation among the following choices given in the question that could be used to solve the problem. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that you were looking for and it has actually come to your help.

Answer 2

Answer:

Answer:

Step-by-step explanation: its the first answer cause i did this a bit ago

so i remember

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Which inequality has no solution?6(x+2)> x-3

3+4x<2(1+2x)

-2(x+6)< x-20

x-9 < 3 (x-3)

Answers

we will proceed to solve all cases to determine the solution of the problem

case A) $6(x+2)> x-3$

Eliminate the parenthesis of the left side

$6x+12> x-3$

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

$6x-x> -3-12$

Combine like terms

$5x> -15$

$x> -3$

The solution is the interval--------> (-3,∞)

All real numbers greater than $-3$

therefore

The inequality A has solution

case B) $3+4x <2(1+2x)$

Eliminate the parenthesis of the right side

$3+4x <2+4x$

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

$4x-4x <2-3$

Combine like terms

$0 <-1$ ---------> is not true

therefore

The inequality B has no solution

case C) $-2(x+6)< x-20$

Eliminate the parenthesis of the left side

$-2x-12< x-20$

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

$-2x-x< -20+12$

Combine like terms

$-3x< -8$

Multiply by $-1$ both sides

$3x> 8$

$x> (8/3)$

The solution is the interval--------> (8/3,∞)

All real numbers greater than $8/3$

therefore

The inequality C has solution

case D) $x-9<3(x-3)$

Eliminate the parenthesis of the right side

$x-9<3x-9$

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

$x-3x< -9+9$

Combine like terms

$-2x< 0$

Multiply by $-1$ both sides

$2x> 0$

$x>0$

The solution is the interval--------> (0,∞)

All real numbers greater than $0$

therefore

The inequality D has solution

therefore

the answer is

$3+4x <2(1+2x)$

$\boxed{3 + 4x < 2\left( {1 + 2x} \right)}$ inequality has no solution. Option (b) is correct.

Further explanation:

The linear equation with slope m and intercept c is given as follows.

$\boxed{y = mx + c}$

The formula for slope of line with points $\left( {{x_1},{y_1}} \right)$ and $\left( {{x_2},{y_2}} \right)$ can be expressed as,

$\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}$

Given:

The inequalities are as follows,

(a). $6\left( {x + 2} \right) > x - 3$

(b). $3 + 4x < 2\left( {1 + 2x} \right)$

(c). $- 2\left( {x + 6} \right) < x - 20$

(d). $x - 9 < 3\left( {x - 3} \right)$

Explanation:

Solve the inequality $6\left( {x + 2} \right) > x - 3$ to check whether the inequality has solution.

$\begin{aligned}6\left( {x + 2} \right) >& x - 3\n6x + 12 >& x - 3\n6x - x >& - 3 - 12\n 5x >&- 15\nx >& \frac{{ - 15}}{5}\nx >&- 3\n\end{aligned}$

Option (a) has solution.

Solve the inequality $3 + 4x < 2\left( {1 + 2x} \right)$ to check whether the inequality has solution.

$\begin{aligned}3+ 4x &< 2\left( {1 + 2x} \right)\n3 + 4x &< 2 + 4x\n3&< 2\n\end{aligned}$

Option (b) has no solution.

Solve the inequality $- 2\left( {x + 6} \right) < x - 20$ to check whether the inequality has solution.

$\begin{aligned}- 2\left( {x + 6}\right) &< x - 20\n- 2x - 12 &< x - 20\n- 12 + 20 &< x + 2x\n8&< 3x\n(8)/(3) &< x\n\end{aligned}$

Option (c) has solution.

Solve the inequality $x - 9 < 3\left( {x - 3} \right)$ to check whether the inequality has solution.

$\begin{aligned}x - 9&< 3\left( {x - 3} \right)\nx - 9&< 3x - 9\nx&< 3x \n1&< 3\n\end{aligned}$

Option (d) has solution.

$\boxed{3 + 4x < 2\left( {1 + 2x} \right)}$ inequality has no solution. Option (b) is correct.

Learn more:

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: numbers,slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.

In a certain country, a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of an ounce) has an additional cost. The function below represents the cost of mailing one letter in this country.f(c)=0.42 + 0.20[x-1]

Josiah has two letters. The first weighs 2.9 ounces, and the second weighs 4.1 ounces. What is the total amount Josiah can expect to pay for postage?
$1.62
$1.64
$1.84

Answers

Answer:

$1.84

Step-by-step explanation:

We are given that a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of an ounce) has an additional cost.

The function which represents the situation:

$f(c)=0.42 + 0.20[x-1]$

Now Joseph has two letters .

The weight of first letter = 2.9 ounces

Cost of first letter = $0.42 + 0.20[2.9-1]$

= $0.8$

Now , second letter weighs 4.1 ounces

So, cost of second letter = $0.42 + 0.20[4.1-1]$

= $1.04$

Thus the total amount Josiah can expect to pay for postage = $0.8+$1.04

=$1.84

Hence the total amount Josiah can expect to pay for postage is $1.84

Answer:

$1.84

Step-by-step explanation:

Solve this equation

Answers

i think your answer would be -4

kirby often forgets to switch the inequity sign when dividing a negative. when solving 3x-10≥x, should kirby collect the variables on the left or the right? why?

Answers

You should collect the variable on the left side since you can't have two variables of the same letter on each side.so you would take the variable from the right side and subtract it from the left. So subtract x on both sides. Your new problem is 2x-10 is greater than or equal to 0. Now you add 10 on both sides. Your new problem is 2x is greater than or equal to 10. Now divide by 2 on both sides. Your answer would be x is greater than or equal to 5

How do you factor x squared plus 3x