Solve for h if d=1/2hw

Answers

Answer 1
Answer: d = 1/2hw
2dhw = 1
h = 1/2dw

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Answer 2
Answer:

d = 1/2 hw

hw = 2d

h = 2d/w


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Select the expression that is equivalent to the polynomial given below. (4x + 3)(3x - 8)a.) 12x2 - 23x - 24b.) 12x2 + 41x + 24c.) 12x2 - 23x + 24 d.) 12x2 - 41x - 24which would be the best option?

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Answers

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Hope this helps ! :)

Find all the real and complex solutions of the polynomial equation. Be sure to show ALL work (4 points):x3-2x2+9x-18=0

Answers

2, 3i, -3i are the real and complex solutions of the polynomial equation.

What is Polynomial?

Polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables

The given polynomial is x³-2x²+9x-18

x³-2x²+9x-18=0

Take the common terms from first two terms

x²(x-2)+9(x-2)

(x²+9)(x-2)=0

(x²+3²)(x-2)=0

x-2=0

x=2

and x²+3²=0

x=3i and x=-3i

Hence, 2, 3i, -3i are the real and complex solutions of the polynomial equation.

To learn more on Polynomials click:

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If an object is dropped from a height of 85 feet, the function h(t)=-16t^2+85 gives the height of the object after t seconds. Approximately, when will the object hit the ground?a. 85.00 seconds
b. 69.00 seconds
c. 0.33 seconds
d. 2.30 seconds

Answers

We are given the function of the situation. The function is given as h(t) = -16t^2 + 85 where h(t) signifies that height is a function of time. For this case, our height would be zero and we find the time it hits the ground. Thus, 

0 = -16t^2 + 85
t = 2.30 seconds

The answer is d.

The difference of two numbers is 11 and their product is 42.find these numbers.

Answers

\left\{\begin{array}{ccc}x-y=11&\to x=y+11\nx\cdot y=42\end{array}\right\n\n(y+11)y=42\ny^2+11y-42=0\ny^2+14y-3y-42=0\ny(y+14)-3(y+14)=0\n(y+14)(y-3)=0\iff y=-14\ \vee\ y=3\n\nx=-14+11=-3\ \vee\ x=3+11=14\n\nAnswer:-3\ and\ -14\ or\ 14\ and\ 3
a-b=11\n a=11+b \n ab=42 \n(11+b)*b=42 \n b^2+11b=42 \n b^2+11b-42=0 \n b^2 +14b-3b -42=0 \n b(b+14)-3(b+14)=0 \n (b+14)(b-3)=0 \n b+14=0 \ b-3=0 \nb= -14 \ b=3 a=11+b \n 1)a=11-14 \na=-3 \n 2)a=11+3 \n a=14

The weights for a population of North American raccoons have a bell-shaped frequency curve with a mean of about 12 pounds and a standard deviation of about 2.5 pounds. About 95% of the weights for individual raccoons in this population fall between what two values?

Answers

Answer:

Step-by-step explanation:

Given that the weights for a population of North American raccoons have a bell-shaped frequency curve with a mean of about 12 pounds and a standard deviation of about 2.5 pounds

Since bell shaped is given we can assume that this follows a normal distribution symmetrical about the mean.

To find 95% two values we can use Z critical value for 95%

i.e. ±1.96

95% will lie between 12±1.96(2.5)

= 12±4.9

=(7.1, 16.9)

$4.30 makeup; 40% discount; 6% tax

Answers

4.30 × (0.40)= d (what the discount is, but not money owed) subtract that from original 4.30-d=b. then add 0.06 of 4.30 to b.