Median of a cumulative frequency graph

Answers

Answer 1
Answer:

Answer:

Sorry this is a really really late reply but to find the median on the graph you need to find the mid value, so for example if the y axis goes up to 60, then the middle of the values will be 30. You go across this 30th value and find the median.

Hope this helps.

Answer 2
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Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of μ=22.5 in. and a standard deviation of σ=1.1 in. These data are often used in the design of different​ seats, including aircraft​ seats, train​ seats, theater​ seats, and classroom seats. Instead of using 0.05 for identifying significant​ values, use the criteria that a value x is significantly high if​ P(x or ​greater) ≤0.01 and a value is significantly low if​ P(x or ​less) ≤0.01.Find the​ back-to-knee lengths separating significant values from those that are not significant.
What is the solution to the system of equations? y = –3x + 6 y = 9

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Answers

Answer:

Bottom left

Step-by-step explanation:

Function: each x only has one y, and this is the only graph that fits the description

The answer is the bottom left one!

Two equivalents of 7/4

Answers

Answer:

14/8        21/12

Step-by-step explanation:

Which graph does NOT represent a function?

Answers

Answer:

graph b

Step-by-step explanation:

it's b because it doesn't have any features like a function it's just a round shape that makes it a none function

N<2^2. mathematical induction​

Answers

Answer:

Inequality Form:
n < 4

Interval Notation:
(-, 4)


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Sec (90 -A) sinA = cot (90-A). tan( 90- A)​

Answers

Step-by-step explanation:

sec(90-A) . Sin A = cot (90-A) . tan(90-A)

cosec X sinA = tanA X cotA

1/sinA X sinA = tanA X 1/tanA

1=1

Hence proved

L.H.S=sec(90-A)·sinA

        =cosecA·sinA ;[sec(90-A)= cosecA]

        =1/sinA·sinA ;[cosecA=1/sinA]

        =1

R.H.S=cot(90-A)·tan(90-A)

        =tanA·cotA ;[cot(90-A)=tanA, tan(90-A)=cotA]

        =tanA·1/tanA ;[cotA=1/tanA]

        =1

thus, L.H.S=R.H.S

[Proved]

Is (0,5) a solution to the equation y=2x?​

Answers

Answer:

No.

Step-by-step explanation:

If (0,5) is a solution to y=2x, then 5=2(0) has to be true.

It is not because 5=2(0) is not true.

2(0)=0 and 0 is definitely not 5.

An example of a point on y=2x is (5,10) since 10=2(5) is true.

Answer:

No

Step-by-step explanation:

The coordinate points are x and y.

So, in this case, 0 would be x and 5 would be y.

We can substitute those numbers into our equation to get:

5=(2)(0)

2 multiplied by 0 equals 0.

0 CANNOT equal 5.

Therefore, your answer is NO, (0,5) isn't the solution to the equation y=2x.

-Stay smart, stay golden :)