In the function f(x) what is f(3)

Answers

Answer 1

Answer: Hello there!

f(x)=x
f(x) is also known as y
x is 3, which means the x value on the right is 3

Answer: f(3)=3

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Answer:

The answer is that x is equal to 33⁰

Help photo question. Mathematics. :D

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m = 4
n = 1

If you substitute in your values, you can see that 4 + 1 = 5
And 4 - 1 = 3
Hope this helped :)

HELP PLEASE!?!17. A building lot in a city is shaped as a 30° -60° -90° triangle. The side opposite the 30° angle measures 41 feet.
a. Find the length of the side of the lot opposite the 60° angle.
b. Find the length of the hypotenuse of the triangular lot.
c. Find the sine, cosine, and tangent of the 30° angle in the lot. Write your answers as decimals rounded to four decimal places.

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The attached pic shows each step.

Multiply to negative 60 add to negative 11

BRAINLIEST!!!!!!please hurry!!!!!what is 3+4(74-32)+89

Answers

Answer:

260

Step-by-step explanation:

3+4(42)+89

3+168+89

260

Answer:

260

Step-by-step explanation:

Work in the parentheses first; 74-32 is 42. Then work with multiplication, 42 times 4 is 168. 168+89+3 = 260

I am confused on this , I’ve tried twice and got it wrong.

Answers

Answer:

$f^-^1(x)=-x^2+6x-5 \ \text{for the domain}\ [3, \infty)$

Step-by-step explanation:

Consider the function $f(x)=√(4-x)+3$ for the domain $(- \infty, 4]$ .

Find $f^-^1(x)$ , where f^(-1) is the inverse of f.

Also state the domain of f^(-1) in interval notation.

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We can start solving this problem by finding the inverse of f(x). This is done by switching the x- and y- variables, and solving for y.

$y=√(4-x)+3 \rightarrow x=√(4-y)+3$
$x=√(4-y)+3$

We can start solving for y by subtracting 3 from both sides of the equation.

$x-3=√(4-y)$

Get rid of the radical by squaring both sides of the equation.

$(x-3)^2=(√(4-y))^2$
$(x-3)(x-3)=4-y$

Use FOIL to multiply the binomial (x-3) together.

$x^2-3x-3x+9=4-y$

Combine like terms.

$x^2-6x+9=4-y$

Subtract 4 from both sides of the equation.

$x^2-6x+5=-y$

Divide both sides of the equation by -1.

$-x^2+6x-5=y$
$f^-^1(x)=-x^2+6x-5$

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The domain and range of a function are flipped for its inverse, meaning that to find the domain of the inverse function, you can find the range of the original function f(x), and that will be your inverse function's domain.

The range of $f(x)=√(4-x) +3$ is $y \geq 3$ , since the vertical shift of the graph is at k = 3. You can also graph this function on a calculator to see that the graph does indeed start at y = 3.