What temperature in Fahrenheit is 50 degree celsius? (Enter numeric value only. If rounding is necessary, round to the nearest whole number.)

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Answer 1
Answer: Step #1: Subtract 32. Step #2: Mutliply by 5. Step #3: Divide by 9... 50-32 = 18; 18 * 5 = 90; 90 / 9 = 10 degrees celsius.

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Dx+hy=j,forx   x=    thanx for any and all help

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dx+hy=j \n \n dx = j-hy \ \ / : \ d \n \nd\neq 0\n \nx=(j-hy )/(d)


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Dx = j - hy

x= (j - hy) / D

If AD = 6 meters, which does AB equal? Select one of the options below as your answer:
A.6 meters
B.10 meters
C.12 meters
D.15 meters

Answers

AD = 6 m
AB is a hypotenuse and AD is an adjecant. 
cos 60° = AD / AB
AB = AD / cos 60°
AB = AD : 1/2
AB = 6 : 1/2 = 12
Answer:
C ) 12 meters

Solve the equation. X^2-6x+6=0

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x^2-6x+6=0 \n \na=1, \ \ b=-6, \ \ c=6 \n\n\Delta =b^2-4ac = (-6)^2 -4\cdot1\cdot 6 = 36-24=12\n\n√(\Delta )=√(12)=√(4\cdot 3)=2√(3)\n \nx_(1)=(-b-√(\Delta) )/(2a)=(6-2√(3))/(2 )=(2( 3- √(3)))/(2)= 3- √(3)\n\nx_(2)=(-b+√(\Delta) )/(2a)=(6+2√(3))/(2 )=(2( 3+ √(3)))/(2)= 3+ √(3)
x^2-6x+6=0\n x^2-6x+9-3=0\n (x-3)^2=3\n x-3=\sqrt 3 \vee x-3=-\sqrt3\n x=3+\sqrt3 \vee x=3-\sqrt3

If sin α=(12/13), and cos α=(5/13), then tan α = ?

Answers

sin α  =  12/13             opposite/hypothenue
cos α  =  5/13              adjacent/hypothenue
tan α  =  12/5                opposite/adjacent