What is 67.142 rounded to the nearest ones?

Answers

Answer 1

Answer: 67.142 rounded to the nearest ones is 67 cause the .1 is not .5 or greater.

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a student has an average of 76 on the first 5 quizzes, what average is needed on the next 5 quizzes to pull his quiz average up to an 80?

A student answered 46 problems on the test correctly and received a grade of 88%. how many problems were on the test if all problems we wear the same number of points?

Answers

The answer is 52 questions

so to find percentages we do the part over the whole. So in this equations we do

(answered correctly)/(total number of questions) * 100=grade

answered correctly = 46
Total number problems = x
where x is the number we don't know
and
grade is 88

(46)/(x) = .88

multiply both sides by x

we get

46 = .88x

we just need to simplify
46/.88 = x
52.27 = x

Which of the following expressions is correctly written in scientific notation?

Answers

Answer:

The 3rd choice.

Step-by-step explanation:

The third choice has what it takes to be a scientific notation.

If there's 4 quarts in 1 gallon, how many gallons are in 200 quarts

Answers

Answer:

the answer is 50 gallons

Step-by-step explanation:

200/4 = 50

Question 7
X-9= -6
What is X

Answers

the answer to this question is x=3

Simplify the expression

Answers

Answer:

f(x) = 5x² + 2x

g(x) = 6x - 6

Step-by-step explanation:

$(5x^3-8x^2-4x)/(6x^2-18x+12)\n\n6(x^2-3x+2)\ne0\ \iff\ x=(3\pm√(9-8))/(2)\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\n\n\n(5x^3-8x^2-4x)/(6x^2-18x+12)=(x(5x^2-8x-4))/(6(x^2-3x+2))=(x(5x^2-10x+2x-4))/(6(x^2-2x-x+2))=\n\n\n=(x[5x(x-2)+2(x-2)])/(6[x(x-2)-(x-2)]) =(x(x-2)(5x+2))/(6(x-2)(x-1))=(x(5x+2))/(6(x-1))=(5x^2+2x)/(6x-6)\n\n\nf(x)=5x^2+2x\n\ng(x)=6x-6$

state the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation

Answers

Answer:

domain (-∞, ∞)
range (-∞, 4]
increasing (-∞, 0)
decreasing (0, ∞)
constant (only at x=0, not on any interval)

Step-by-step explanation:

The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).

The vertical extent of the graph includes y=4 and all numbers less than that:

range: (-∞, 4]

The graph is increasing to the left of its vertex at x=0, decreasing to the right.

increasing (-∞, 0); decreasing (0, ∞)

There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.

Final answer:

The domain of a function refers to all possible inputs while the range comprises all potential outputs. The function increases, decreases, or remains constant when the respective slope is positive, negative, or zero. I've provided an explanation based on the indication of the respective slopes described in your problem.

Explanation:

To determine the domain, range, and intervals of increase, decrease, or constant for a function, we need to examine the specific input and output values as well as the curvature of the function.

Domain of a function refers to all possible input values (x-values). For example, in the probability distribution function (PDF), the domain may include all numerical values or could be expressed through a non-numerical set such as different hair colors. From the provided information, I can deduce that the domain of X is {English, Mathematics, ...} - a list of all majors offered at the university, indicating all the possible inputs of this function. The domain of Y and Z are numerical, from zero up to an upper limit.

Range of a function is all the potential output values (y-values). The range is usually derived from the domain values after undergoing certain transformations via the function. Unfortunately, without further specifics about the function, I can't provide a conclusive range.

For intervals of increase, decrease, or constant, you look at the slope of the function. A function is increasing on an interval if the y-value increases as the x-value increases. Contrary to this, a function is decreasing on an interval if the y-value decreases as the x-value increases. If the y-value remains constant as the x-value varies, the function is constant on that interval. Different parts of your provided solutions indicate the function starts with positive slope (increasing), then levels off (becomes constant).

Learn more about Function Analysis here:

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