During a test trial, the control and test group are both given a pill. To account for the effect patients may think the drug being tested is having just because they believe they're being treated, the control group is given a "sugar pill," which is called what?A) Placebo
B) Drug
C) Medicine
D) Screening Tool
Ohp xD nvm, the answer is A !

Answers

Answer 1

Answer:

During the test trial, the sugar pill given to the control group is called a placebo. Therefore, the correct option is A. Placebo

What is a placebo ?

A placebo is any drug or a treatment with no active substances, for example a sugar pill.

During clinical trials, usually one group takes the actual drug while the other group takes the placebo without being aware of it.

Placebo is an inactive treatment given to a group of people that is made to look like the real drug, but in reality it simply makes the patient believe they're being treated with the drug and that the drug will help them relieve from the symptoms.

By comparing the results from the two groups, this method helps in analyzing the accurate effects of the drug on the patients and helps in proving that it was the drug that actually treated the symptom and that the treatment did not occur by chance or just a mere belief of the patient thinking they will get better because they're being treated.

This approach helps reduce bias and ensures that the trial's results are more accurate and reliable.

So, the sugar pill given to the control group is called a placebo. Therefore, the correct option is A. Placebo

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Answer 2

Answer: The answer is a placebo.

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In an experiment, 2.54 grams of copper completely reacts with sulfur, producing 3.18 grams of copper(I) sulfide.Determine the total mass of sulfur consumed.
Write the chemical formula of the compound produced.

Answers

Answer:

0.64 g of S

Solution:

The balance chemical equation is as follow,

2 Cu + S ----> Cu₂S

According to equation,

127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S

So,

2.54 g Cu will produce = X g of Cu₂S

Solving for X,

X = (2.54 g * 159 g) / 127 g

X = 3.18 g of Cu₂S

Now, it is confirmed that the reaction is 100% ideal. Therefore,

As,

127 g (2 mole) Cu required = 32 g (1 mole) of S

So,

2.54 g Cu will require = X g of S

Solving for X,

X = (2.54 g * 32 g) / 127 g

X = 0.64 g of S

Answer : The total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, $Cu_2S$ copper oxide.

Solution :

According to the law of conservation of mass, the total mass of reactant should be equal to the total mass of product.

The balanced chemical reaction will be,

$2Cu+S\rightarrow Cu_2S$

In this reaction, copper and sulfur are the reactants and copper sulfide is the product.

Let the mass of sulfur be 'x' gram

$\text{The total mass of reactants}=\text{Total mass of copper}+\text{Total mass of sulfur}=2.54g+x$

$\text{The total mass of product}=\text{Total mass of copper sulfide}=3.18g$

According to the law of conservation of mass,

$\text{The total mass of reactants}=\text{The total mass of product}$

$2.54g+x=3.18g$

$x=(3.18-2.54)g$

$x=0.64g$

Therefore, the total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, $Cu_2S$ copper oxide.

Hydrogen bonding is strongest between molecules of

Answers

i'm not completely sure but i think it's H2O. hope this helps :)

The chemical symbol for iron is

Answers

Fe
FeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFeFe

Fe is the chemical symbol for iron FEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction. ____HNO3 + ____S ---> ____NO + ____H2SO4

Answers

Explanation:

An equation that contains equal number of atoms on both reactant and product side is known as a balanced chemical equation.

Whereas when there will be increase in oxidation number of the atom then it is known as oxidation. When there is decrease in oxidation number of the atom then it is known as reduction.

For example, $4HNO_(3) + S \rightarrow NO + H_(2)SO_(4) + H_(2)O$

Oxidation half reaction : $S \rightarrow H_(2)SO_(4) + 6e^(-)$

Reduction half reaction : $HNO_(3) + 3e^(-) \rightarrow NO$

Therefore, we can conclude that sulfur atom has undergone oxidation and nitrogen atom has undergone reduction.

The following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction.
2HNO3 + S ---> 2NO + H2SO4

A plate moves south at a rate of 2 cm/year. How many meters south from its original location will the plate be in 4,000 years? 8,000 meters south 4,000 meters south 200 meters south 80 meters south

Answers

The distance (in meters south) the plate will be given that the plate is moving at a rate of 2 cm/year is 80 meters south (last option)

How do i determine the distance?

Speed is defined as distance travelled per unit time. This is mathematically written as

Speed = Distance travelled / time

If we make distance the subject, we have

Distance travelled = Speed × time

The following data were obtained from the question:

Speed of plate = 2 cm/year = 2 / 100 = 0.02 m/year
Time = 4000 years
Distance travelled =?

Distance travelled = Speed × time

Distance travelled = 0.02 × 4000

Distance travelled = 80 meters south

Thus, we can conclude that the distance travelled is 80 meters south (last option)

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the plate will be 80 meters south from its original location in 4,000 years. The correct answer is (d) 80 meters south.

The plate moves south at a rate of 2 cm/year. To find out how many meters south it will be in 4,000 years, we need to convert the years to centimeters and then meters.

In 4,000 years, the plate will have moved: 2 cm/year x 4,000 years = 8,000 cm.

Now, to convert 8,000 cm to meters, we need to divide by 100 (since there are 100 centimeters in a meter):

8,000 cm / 100 = 80 meters.

So, the plate will be 80 meters south from its original location in 4,000 years. The correct answer is (d) 80 meters south.

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Complete question is:

A plate moves south at a rate of 2 cm/year. How many meters south from its original location will the plate be in 4,000 years?

a. 8,000 meters south

b. 4,000 meters south

c. 200 meters south

d. 80 meters south

Oxidation numbers are written as ____.

Answers

they are written as superscripts
(a symbol or a figure)

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