Change 3 5/8 into an improper fraction.

Answers

Answer 1

Answer:

The fractions is solved and the improper fraction is A = 29/8

Given data ,

To change 3 5/8 into an improper fraction, we need to combine the whole number and the fraction part.

The fraction part, 5/8, can be expressed as an improper fraction by multiplying the whole number, 3, by the denominator of the fraction, 8, and then adding the numerator, 5. This gives us:

3 * 8 + 5 = 24 + 5 = 29

The denominator remains the same, so the improper fraction is:

A = 29/8

Therefore , the value of A = 29/8

Hence , 3 5/8 can be expressed as the improper fraction 29/8

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Answer 2

Answer:

Answer:

The improper fraction 29/8 is equal to the mixed number 3 5/8.

Step-by-step explanation:

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A submarine at - 45 feet dives 50 feet. Write an expression to represent the submarine's elevation. Need help

Answers

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this might be yo answer im not sure

i hope this helped u tho

(1 point) For the given position vectors r(t)r(t), compute the (tangent) velocity vector r′(t)r′(t) for the given value of tt . A) Let r(t)=(cos4t,sin4t)Let r(t)=(cos⁡4t,sin⁡4t). Then r′(π4)r′(π4)= ( , )? B) Let r(t)=(t2,t3)Let r(t)=(t2,t3). Then r′(5)r′(5)= ( , )? C) Let r(t)=e4ti+e−5tj+tkLet r(t)=e4ti+e−5tj+tk. Then r′(−5)r′(−5)= i+i+ j+j+ kk ?

Answers

Answer:

(a)

$r'(\frac \pi 4) =(0.-4)$

(b)

r'(5)= (10,75)

(c)

$r'(-5) =4 e^(-20)\hat i-5e^(25)\hat j+\hat k$

Step-by-step explanation:

(a)

Give that,the position vector is

r(t) = (cos 4t, sin 4t)

Differentiating with respect to t

r'(t) = (-4sin 4t, 4 cos 4t) [ $(d)/(dt) cos mt = -m \ sin \ mt$ and $(d)/(dt) sin mt = m \ cos \ mt$ ]

To find the $r'(\frac\pi 4)$ , we put $t=\frac \pi4$

$r'(\frac\pi 4) = (-4sin (4.\frac \pi 4), 4 cos (4.\frac \pi 4))$

=(0, -4)

(b)

Give that,the position vector is

r(t) = (t²,t³)

Differentiating with respect to t

r'(t) = (2t, 3t²)

To find r'(5) , we put t=5

r'(5) = (2.5,3.5²)

= (10,75)

(c)

Given position vector is

$r(t) = e^(4t)\hat i+e^(-5t)\hat j+t\hat k$

Differentiating with respect to t

$r'(t) =4 e^(4t)\hat i+(-5)e^(-5t)\hat j+\hat k$

$\Rightarrow r'(t) =4 e^(4t)\hat i-5e^(-5t)\hat j+\hat k$

To find r'(-5) , we put t= - 5 in the above equation

$r'(-5) =4 e^(4.(-5))\hat i-5e^(-5.(-5))\hat j+\hat k$

$\Rightarrow r'(-5) =4 e^(-20)\hat i-5e^(25)\hat j+\hat k$

For the given position vectors r(t)r(t), compute the (tangent) velocity vector r′(t)r′(t) for the given value of tt are:

$A) r' (\pi /4) = (0, -4) \nB) r'(5) = (10, 75)\nC) r'(-5) = (4e^(-20), -5e^(25), 1)$

To compute the velocity vector, we need to find the derivative of the position vector with respect to time (t). This will give us the tangent velocity vector.

A) Let r(t) = (cos⁡4t, sin⁡4t).

To find r'(t), we take the derivative of each component with respect to t:

r'(t) = (d/dt (cos⁡4t), d/dt (sin⁡4t))

r'(t) = (-4sin⁡4t, 4cos⁡4t)

To find r'(π/4), we substitute t = π/4 into r'(t):

r'(π/4) = (-4sin⁡(4(π/4)), 4cos⁡(4(π/4)))

r'(π/4) = (-4sin⁡π, 4cos⁡π)

r'(π/4) = (0, -4)

B) $Let \ r(t) = (t^2, t^3).$

To find r'(t), we take the derivative of each component with respect to t:

$r'(t) = (d/dt (t^2), d/dt (t^3))\nr'(t) = (2t, 3t^2)$

To find r'(5), we substitute t = 5 into r'(t):

$r'(5) = (2(5), 3(5)^2)\nr'(5) = (10, 75)$

C) Let $r(t) = e^(4t)i + e^(-5t)j + tk.$

To find r'(t), we take the derivative of each component with respect to t:

$r'(t) = (d/dt (e^(4t)), d/dt (e^(-5t)), d/dt (t))]\n\nr'(t) = (4e^(4t)), -5e^(-5t), 1)$

To find r'(-5), we substitute t = -5 into r'(t):

$r'(-5) = (4e^(4{-5}), -5e^(-5(-5)), 1) \n\nr'(-5) = (4e^(-20), -5e^(25), 1)$

So, the answers are:

$A) r' (\pi /4) = (0, -4) \nB) r'(5) = (10, 75)\nC) r'(-5) = (4e^(-20), -5e^(25), 1)$

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99% confidence interval for the population standard deviation

Answers

99% = 2.58

how to find ?

Divide your confidence level by 2: . 95/2 = 0.475. Step 2: Look up the value you calculated in Step 1 in the z-table and find the corresponding z-value. The z-value that has an area of .

Human body temperatures have a mean of 98.20° F and a standard deviation of 0.62°. Sally's temperature can be described by z = -1.5. What is her temperature? Round your answer to the nearest hundredth.

Answers

Answer:

$97.27^(o)F$

Step-by-step explanation:

We have been given that human body temperatures have a mean of 98.20° F and a standard deviation of 0.62°. Sally's temperature can be described by z = -1.5.

To find Sally's temperature we will use z-score formula.

$z=(x-\mu)/(\sigma)$ , where $\mu$ = Mean, $\sigma$ = Standard deviation.

Let us substitute our given values in z-score formula.

$-1.5=(x-98.20)/(0.62)$

Multiply 0.62 to both sides of equation.

$0.62*-1.5=0.62* (x-98.20)/(0.62)$

$-0.93=x-98.20$

Add 98.20 to both sides of equation.

$-0.93+98.20=x-98.20+98.20$

$97.27=x$

Therefore, Sally's temperature will be 97.27 degrees Fahrenheit.

$Z=\frac{X-\mu}\sigma\iff-1.5=(X-98.20^\circ)/(0.62^\circ)\implies X\approx97.27^\circ$

Select all points that are on the line through 0,5and 2,8.

4,11
5,10
6,14
30,50
40,60

Answers

Answer:

Options (1), (3), and (4)

Step-by-step explanation:

Since, slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

m = $(y_2-y_1)/(x_2-x_1)$

Therefore, slope of a line passing through (0, 5) and (2, 8) will be,

m = $(8-5)/(2-0)$ = 1.5

Equation of line passing through (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of a line passing through (0, 5) and slope = 1.5,

y - 5 = 1.5(x - 0)

y = 1.5x + 5

Since, all the points which lie on this line will satisfy this equation.

For (4, 11),

11 = 1.5(4) + 5

11 = 11

Point (4, 11) lies on this line.

Point (5, 10)

10 = 1.5(5) + 5

10 = 7.5 + 5

10 = 12.5

But 10 ≠ 12.5

Therefore, (5, 10) doesn't line on the line.

Point (6, 14)

14 = 1.5(6) + 5

14 = 14

True.

Therefore, (6, 14) lies on the line.

Point (30, 50)

50 = 1.5(30) + 5

50 = 50

True.

Therefore, (30, 50) lies on the line.

Point (40, 60)

60 = 1.5(40) + 5

60 = 65

But 60 ≠ 65

Therefore, (40, 60) doesn't lie on the line.

Options (1), (3) and (4) and the correct options.

Answer:

1, 3 and 4. I had the same question on my assignment :)

Step-by-step explanation:

Dejah is proving that perpendicular lines have slopes that are opposite reciprocals. She draws line s and labels two points on the line as (−a, 0) and (0, b).Enter the answers, in simplest form, in the boxes to complete the proof.

Answers

Answer:

math is hard :(

Step-by-step explanation:

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